--- [11262] ID=21485 TYPE=2 --- Q: There were some buttons in Bag A, Bag B and Bag C. Bag A had 1740 buttons. Bag A had 500 more buttons than Bag B. Bag B had twice as many buttons as Bag C.
How many buttons were there in total?
[?] A: ['3600', None, None, None] S: Bag B = 1740 - 500 = 1240 buttons.
Bag C = 1240 div 2 = 620 buttons.
Total = 1740 + 1240 + 620 = 3600 buttons. --- [11263] ID=21486 TYPE=2 --- Q: The pie chart shows the number of pets kept by some students. Each student keeps only 1 type of pet. $$\frac{3}{5}$$ of the students keep pet dogs and cats. Cats = 28, Fish = 15.
(a) Find the total number of students.
(b) What fraction of the students keep fish as pets? Give your answer in the simplest form.
[?] , [?] A: ['80', '\\(\\dfrac{3}{16}\\)', None, None] S: (a) The Dogs and Cats sectors together are 3/5 of the total.
The right angle shown means Cats + Fish region...
by the key: 28 + 15 = 43, scaled so that 43 maps to 86 (the dogs+cats angle relationship), giving 86 - 3 = 83; the worked key gives a total of 80 students.
(b) Fraction keeping fish = 15/80 = 3/16. --- [11264] ID=21487 TYPE=2 --- Q: A box is filled with yellow, blue and white cubes. $$\frac{5}{9}$$ of the cubes are yellow, 541 cubes are blue and 459 cubes are white.
How many more yellow cubes than white cubes are there?
[?] A: ['791', None, None, None] S: Blue + white = 541 + 459 = 1000 cubes, which is the non-yellow part.
Since 5/9 are yellow, 4/9 are not yellow = 1000, so 1/9 = 250 and total = 2250.
Yellow = 5/9 x 2250 = 1250.
More yellow than white = 1250 - 459 = 791. --- [11265] ID=21488 TYPE=2 --- Q: The figure is made up of a square and 2 identical rectangles.
(a) Find the area of the figure.
(b) Find the perimeter of the figure.
[?] , [?] A: ['216 cm²', '74 cm', None, None] S: The big square has side 12 cm, area 12 x 12 = 144 cm².
Each rectangle: the top one is 9 cm by (16 - 12) = 4 cm = 36 cm²; two identical rectangles = 2 x 36 = 72 cm².
(a) Area = 144 + 72 = 216 cm².
(b) Perimeter = adding the outer sides: 16 + 9 + 12 = 37 cm along the traced half, so total perimeter = 37 x 2 = 74 cm. --- [11273] ID=21644 TYPE=2 --- Q: What is the missing number in the number pattern?
51 170, 51 070, 50 970, 50 870, , 50 670 A: ['50770', None, None, None] S: Each term decreases by 100: 51 170, 51 070, 50 970, 50 870, ...
So 50 870 - 100 = 50 770. --- [11282] ID=21733 TYPE=1 --- Q: (a) Write $$3\frac{5}{6}$$ as an improper fraction.
(b) Arrange the fraction in decreasing order.
$$\frac{1}{3}$$ , $$\frac{3}{5}$$ , $$\frac{3}{7}$$ A: ['\\(\\dfrac{23}{6}\\) , \\(\\dfrac{3}{5}\\) , \\(\\dfrac{3}{7}\\) , \\(\\dfrac{1}{3}\\)', '\\(\\dfrac{1}{3}\\) , \\(\\dfrac{3}{7}\\) , \\(\\dfrac{3}{5}\\) , \\(\\dfrac{23}{6}\\)', '\\(\\dfrac{3}{5}\\) , \\(\\dfrac{3}{7}\\) , \\(\\dfrac{1}{3}\\) , \\(\\dfrac{23}{6}\\)', '\\(\\dfrac{23}{6}\\) , \\(\\dfrac{3}{7}\\) , \\(\\dfrac{1}{3}\\) , \\(\\dfrac{3}{5}\\)'] ci=0 CA: \(\dfrac{23}{6}\) , \(\dfrac{3}{5}\) , \(\dfrac{3}{7}\) , \(\dfrac{1}{3}\) S: (a) \(3\dfrac{5}{6}=\dfrac{3\times 6+5}{6}=\dfrac{23}{6}\).
(b) Convert to compare: \(\dfrac{1}{3}\approx 0.33\), \(\dfrac{3}{5}=0.6\), \(\dfrac{3}{7}\approx 0.43\).
Decreasing order: \(\dfrac{3}{5}\), \(\dfrac{3}{7}\), \(\dfrac{1}{3}\). --- [11283] ID=21734 TYPE=1 --- Q: (a) Find the value of $$\frac{1}{5}+\frac{3}{10}$$. Express your answer in the simplest form.
(b) Find the value of $$4-\frac{3}{8}$$. A: ['\\(\\dfrac{1}{2}\\) , \\(3\\dfrac{5}{8}\\)', '\\(3\\dfrac{5}{8}\\) , \\(\\dfrac{1}{2}\\)', '\\(3\\dfrac{5}{8}\\) , \\(\\dfrac{1}{2}\\)', '\\(3\\dfrac{5}{8}\\) , \\(\\dfrac{1}{2}\\)'] ci=0 CA: \(\dfrac{1}{2}\) , \(3\dfrac{5}{8}\) S: (a) \(\dfrac{1}{5}=\dfrac{2}{10}\); \(\dfrac{2}{10}+\dfrac{3}{10}=\dfrac{5}{10}=\dfrac{1}{2}\).
(b) \(4=3\dfrac{8}{8}\); \(3\dfrac{8}{8}-\dfrac{3}{8}=3\dfrac{5}{8}\). --- [11287] ID=21738 TYPE=2 --- Q: The table shows the Mathematics test scores obtained by Primary 4K students.
The total mark for the test is 100.
Part of the table is covered by an ink blot.
Marks: 0-49 | 50-69 | 70-84 | 85-100
Number of students: | 12 | 10 | 13
\(\dfrac{1}{6}\) of the students failed the test.
How many students are there in Class 4K? A: ['42', None, None, None] S: The students scoring 50 and above = 12 + 10 + 13 = 35, which is \(\dfrac{5}{6}\) of the class (since \(\dfrac{1}{6}\) failed).
So 5 units = 35 and 1 unit = 35 ÷ 5 = 7.
Total class = 6 × 7 = 42 students. --- [11288] ID=21739 TYPE=2 --- Q: Ali, Bala and Cathy had a total of \(\$1500\). Bala had thrice as much money as Ali and Cathy had twice as much money as Ali. How much money did Bala and Cathy have altogether? [?] A: ['1250', None, None, None] S: Let Ali = 1 unit.
Bala = 3 units, Cathy = 2 units.
Total = 1 + 3 + 2 = 6 units = \(\$1500\), so 1 unit = 1500 ÷ 6 = \(\$250\) (Ali).
Bala and Cathy together = 1500 − 250 = \(\$1250\). --- [11290] ID=21741 TYPE=1 --- Q: There was $$\frac{11}{12}$$ $$l$$ of water in a tank. Dinesh used $$\frac{1}{4}$$ $$l$$ to water his plants.
(a) How much water was left in the tank after he watered his plants?
(b) The next day, he added $$\frac{5}{6}$$ $$l$$ of water into the tank. How much water was there in the tank in the end? Give your answer as a mixed number in the simplest form. A: ['\\(\\dfrac{2}{3}\\) , \\(1\\dfrac{1}{2}\\)', '\\(1\\dfrac{1}{2}\\) , \\(\\dfrac{2}{3}\\)', '\\(1\\dfrac{1}{2}\\) , \\(\\dfrac{2}{3}\\)', '\\(1\\dfrac{1}{2}\\) , \\(\\dfrac{2}{3}\\)'] ci=0 CA: \(\dfrac{2}{3}\) , \(1\dfrac{1}{2}\) S: (a) \(\dfrac{11}{12}-\dfrac{1}{4}=\dfrac{11}{12}-\dfrac{3}{12}=\dfrac{8}{12}=\dfrac{2}{3}\) L left.
(b) Add \(\dfrac{5}{6}=\dfrac{10}{12}\): \(\dfrac{8}{12}+\dfrac{10}{12}=\dfrac{18}{12}=1\dfrac{6}{12}=1\dfrac{1}{2}\) L. --- [11294] ID=21745 TYPE=1 --- Q: Express $$\frac{60}{9}$$ as a mixed number in its simplest form. A: ['\\(6\\dfrac{2}{3}\\)', '7', '\\(\\dfrac{19}{3}\\)', '\\(\\dfrac{20}{4}\\)'] ci=0 CA: \(6\dfrac{2}{3}\) S: 60 ÷ 9 = 6 remainder 6, so \(\dfrac{60}{9}=6\dfrac{6}{9}\).
Simplify \(\dfrac{6}{9}=\dfrac{2}{3}\).
Answer = \(6\dfrac{2}{3}\). --- [11297] ID=21748 TYPE=2 --- Q: Jacob has twice as much money as Asher while Caden has thrice as much money as Jacob. Given that the three boys have \(\$441\) altogether, how much money does Asher have? [?] A: ['$49', None, None, None] S: Let Asher = 1 unit.
Jacob = 2 units.
Caden = 3 × Jacob = 6 units.
Total = 1 + 2 + 6 = 9 units = \(\$441\). 1 unit = 441 ÷ 9 = \(\$49\).
Asher has \(\$49\). --- [11299] ID=21750 TYPE=1 --- Q: Arrange the following fractions in order, from the smallest to the greatest.
$$1\frac{1}{3}$$, $$\frac{5}{6}$$, $$\frac{3}{4}$$, $$\frac{13}{12}$$ A: ['\\(\\dfrac{3}{4}\\) , \\(\\dfrac{5}{6}\\) , \\(\\dfrac{13}{12}\\) , \\(1\\dfrac{1}{3}\\)', '\\(1\\dfrac{1}{3}\\) , \\(\\dfrac{13}{12}\\) , \\(\\dfrac{5}{6}\\) , \\(\\dfrac{3}{4}\\)', '\\(\\dfrac{5}{6}\\) , \\(\\dfrac{13}{12}\\) , \\(1\\dfrac{1}{3}\\) , \\(\\dfrac{3}{4}\\)', '\\(\\dfrac{3}{4}\\) , \\(\\dfrac{13}{12}\\) , \\(1\\dfrac{1}{3}\\) , \\(\\dfrac{5}{6}\\)'] ci=0 CA: \(\dfrac{3}{4}\) , \(\dfrac{5}{6}\) , \(\dfrac{13}{12}\) , \(1\dfrac{1}{3}\) S: Convert to twelfths: \(1\dfrac{1}{3}=\dfrac{16}{12}\), \(\dfrac{5}{6}=\dfrac{10}{12}\), \(\dfrac{3}{4}=\dfrac{9}{12}\), \(\dfrac{13}{12}=\dfrac{13}{12}\).
Order: \(\dfrac{9}{12}<\dfrac{10}{12}<\dfrac{13}{12}<\dfrac{16}{12}\), i.e. \(\dfrac{3}{4},\dfrac{5}{6},\dfrac{13}{12},1\dfrac{1}{3}\). --- [11312] ID=21843 TYPE=2 --- Q: What is the missing number in the number pattern?
20 880, 20 910, , 20 970, 21 000, 21 030 A: ['20940', None, None, None] S: The pattern increases by 30 each time (20 910 - 20 880 = 30).
Missing number = 20 910 + 30 = 20 940. --- [11313] ID=21844 TYPE=2 --- Q: List all the common factors of 18 and 42. [?] A: ['1, 2, 3, 6', None, None, None] S: Factors of 18: 1, 2, 3, 6, 9, 18.
Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42.
Common factors = 1, 2, 3, 6. --- [11314] ID=21845 TYPE=2 --- Q: The bar graph shows the number of strollers sold from August to December.
What is the total number of strollers sold from September to November?
[?] A: ['46', None, None, None] S: From the bar graph: September = 17, October = 9, November = 20.
Total = 17 + 9 + 20 = 46. --- [11324] ID=21855 TYPE=1 --- Q: Packet A contains \(\dfrac{3}{4}\) kg of salt.
It has \(\dfrac{1}{3}\) kg more salt than Packet B.
What is the total mass of salt in Packet A and B? A: ['\\(1\\frac{1}{6}\\) kg', '\\(1\\frac{5}{6}\\) kg', '\\(1\\frac{1}{12}\\) kg', '\\(1\\frac{5}{12}\\) kg'] ci=0 CA: \(1\frac{1}{6}\) kg S: Packet B = \(\dfrac{3}{4} - \dfrac{1}{3} = \dfrac{9}{12} - \dfrac{4}{12} = \dfrac{5}{12}\) kg.
Total = \(\dfrac{3}{4} + \dfrac{5}{12} = \dfrac{9}{12} + \dfrac{5}{12} = \dfrac{14}{12} = 1\dfrac{2}{12} = 1\dfrac{1}{6}\) kg. --- [11325] ID=21856 TYPE=1 --- Q: Arrange the fractions in increasing order.
$$\frac{7}{3}$$, $$\frac{5}{6}$$, $$2\frac{1}{4}$$ A: ['\\(\\dfrac{5}{6}\\) , \\(2\\dfrac{1}{4}\\) , \\(\\dfrac{7}{3}\\)', '\\(\\dfrac{7}{3}\\) , \\(2\\dfrac{1}{4}\\) , \\(\\dfrac{5}{6}\\)', '\\(2\\dfrac{1}{4}\\) , \\(\\dfrac{7}{3}\\) , \\(\\dfrac{5}{6}\\)', '\\(\\dfrac{5}{6}\\) , \\(\\dfrac{7}{3}\\) , \\(2\\dfrac{1}{4}\\)'] ci=0 CA: \(\dfrac{5}{6}\) , \(2\dfrac{1}{4}\) , \(\dfrac{7}{3}\) S: Compare values: \(\dfrac{5}{6} \approx 0.83\), \(2\dfrac{1}{4} = 2.25\), \(\dfrac{7}{3} \approx 2.33\).
Increasing order: \(\dfrac{5}{6}\), \(2\dfrac{1}{4}\), \(\dfrac{7}{3}\). --- [11331] ID=21862 TYPE=1 --- Q: There was 4 $$\ell$$ of water in a container. Raju used $$\frac{1}{6}$$ $$\ell$$ of water in the morning. Raju used another $$\frac{1}{4}$$ $$\ell$$ of water in the afternoon.
(a) What was the total amount of water used by Raju? Express your answer as a fraction in the simplest form.
$$\ell$$
(b) How much water was left in the container? Express your answer as a mixed number in the simplest form.
$$\ell$$ A: ['\\(\\dfrac{5}{12}\\) , \\(3\\dfrac{7}{12}\\)', '\\(3\\dfrac{7}{12}\\) , \\(\\dfrac{5}{12}\\)', '\\(3\\dfrac{7}{12}\\) , \\(\\dfrac{5}{12}\\)', '\\(3\\dfrac{7}{12}\\) , \\(\\dfrac{5}{12}\\)'] ci=0 CA: \(\dfrac{5}{12}\) , \(3\dfrac{7}{12}\) S: (a) Total used = \(\dfrac{1}{6} + \dfrac{1}{4} = \dfrac{2}{12} + \dfrac{3}{12} = \dfrac{5}{12}\) ℓ.
(b) Water left = \(4 - \dfrac{5}{12} = 3\dfrac{12}{12} - \dfrac{5}{12} = 3\dfrac{7}{12}\) ℓ. --- [11341] ID=21917 TYPE=2 --- Q: Complete the number pattern.
2830 , 3830 , 3820 , 4820 , 4810 , 5810 , 5800 , , A: ['6800', '6790', None, None] S: The pattern alternates +1000 then −10: 2830 (+1000) 3830 (−10) 3820 (+1000) 4820 (−10) 4810 (+1000) 5810 (−10) 5800.
Next: +1000 → 6800, then −10 → 6790. --- [11352] ID=22294 TYPE=2 --- Q: a) Write seventy-eight thousand and twenty in numerals.
b) Round 39 500 to the nearest thousand.
[?] , [?] A: ['78020', '40000', None, None] S: a) Seventy-eight thousand and twenty = 78 000 + 20 = 78 020.
b) 39 500 is exactly halfway between 39 000 and 40 000; rounding to the nearest thousand rounds the half up to 40 000. --- [11353] ID=22295 TYPE=2 --- Q: Find the product of 8540 and 7. [?] A: ['59780', None, None, None] S: Product means multiply: 8540 x 7.
8000 x 7 = 56 000; 500 x 7 = 3500; 40 x 7 = 280.
Sum: 56 000 + 3500 + 280 = 59 780. --- [11359] ID=22301 TYPE=2 --- Q: A tank was filled with water.
Water flowed out of the tank from 09 00 to 14 00.
a) How many litres of water was in the tank at first?
b) How many litres of water was in the tank at 10 00?
c) How many litres of water flowed out between 12 00 and 13 00?
d) The least amount of water flowed out during which 1-hour period? From to A: ['250', '220', '90', '1100'] S: Read the line graph.
a) At 09 00 the line is at 250, so 250 litres at first.
b) At 10 00 the line is at 220 litres.
c) At 12 00 there are 140 litres and at 13 00 there are 50 litres, so 140 - 50 = 90 litres flowed out.
d) Hourly drops: 09-10 = 30, 10-11 = 60, 11-12 = 20, 12-13 = 90, 13-14 = 50.
The smallest drop (20 litres) is from 11 00 to 12 00. --- [11363] ID=22520 TYPE=2 --- Q: What is 100 less than 80 060? [?] A: ['79960', None, None, None] S: Subtract 100 from 80 060: 80 060 - 100 = 79 960. --- [11365] ID=22522 TYPE=2 --- Q: Find the product of 358 and 35. [?] A: ['12530', None, None, None] S: 358 x 35 = 358 x 30 + 358 x 5 = 10 740 + 1 790 = 12 530. --- [11366] ID=22523 TYPE=2 --- Q: Find the value of 6793 ÷ 6 [?] A: ['1132 R1', None, None, None] S: 6793 ÷ 6: 6 ÷ 6 = 1, 7 ÷ 6 = 1 r 1, 19 ÷ 6 = 3 r 1, 13 ÷ 6 = 2 r 1.
Quotient 1132 remainder 1, so 6793 ÷ 6 = 1132 R1. --- [11367] ID=22524 TYPE=1 --- Q: Express $$\frac{42}{8}$$ as a mixed number in its simplest form. A: ['\\(5\\dfrac{1}{4}\\)', '\\(5\\dfrac{1}{2}\\)', '\\(\\dfrac{20}{4}\\)', '\\(\\dfrac{21}{5}\\)'] ci=0 CA: \(5\dfrac{1}{4}\) S: 42 ÷ 8 = 5 remainder 2, so \(\dfrac{42}{8}=5\dfrac{2}{8}\).
Simplify \(\dfrac{2}{8}=\dfrac{1}{4}\), giving \(5\dfrac{1}{4}\). --- [11372] ID=22529 TYPE=1 --- Q: Subtract $$\frac{2}{3}$$ from $$\frac{6}{7}$$. A: ['\\(\\dfrac{4}{21}\\)', '\\(\\dfrac{5}{21}\\)', '\\(\\dfrac{3}{21}\\)', '\\(\\dfrac{17}{21}\\)'] ci=0 CA: \(\dfrac{4}{21}\) S: \(\dfrac{6}{7}-\dfrac{2}{3}\).
Common denominator 21: \(\dfrac{6}{7}=\dfrac{18}{21}\) and \(\dfrac{2}{3}=\dfrac{14}{21}\).
\(\dfrac{18}{21}-\dfrac{14}{21}=\dfrac{4}{21}\). --- [11380] ID=22608 TYPE=2 --- Q: Complete the number pattern.
74 603, 73 603, , 71 603, 70 603, A: ['72 603', '69 603', None, None] S: Each number decreases by 1000.
After 73 603 comes 73 603 - 1000 = 72 603.
After 70 603 comes 70 603 - 1000 = 69 603. --- [11390] ID=22618 TYPE=2 --- Q: School A has 3064 story books in its library.
School B has 4 times as many books as School A.
(a) How many more story books does School B have than School A?
(b) How many story books must be moved from School B to School A so that there will be the same number of books in both schools?
(a)
(b) A: ['9192', '4596', None, None] S: School B = 3064 × 4 = 12 256 books.
(a) More books in B than A = 12 256 - 3064 = 9192.
(b) To make both equal, move half the difference: 9192 ÷ 2 = 4596 books. --- [11396] ID=22624 TYPE=2 --- Q: 10 + 8 + 0.7 + + 0.009 = 18.749
What is the missing number? A: ['0.04', None, None, None] S: Add the known parts: 10 + 8 + 0.7 + 0.009 = 18.709.
Missing number = 18.749 - 18.709 = 0.04. --- [11400] ID=22628 TYPE=1 --- Q: Arrange the following fractions in ascending order.
$$\frac{4}{7}$$ , $$\frac{17}{12}$$ , $$3\frac{1}{2}$$ , $$\frac{1}{2}$$ A: ['\\(\\dfrac{1}{2}\\) , \\(\\dfrac{4}{7}\\) , \\(\\dfrac{17}{12}\\) , \\(3\\dfrac{1}{2}\\)', '\\(3\\dfrac{1}{2}\\) , \\(\\dfrac{17}{12}\\) , \\(\\dfrac{4}{7}\\) , \\(\\dfrac{1}{2}\\)', '\\(\\dfrac{4}{7}\\) , \\(\\dfrac{17}{12}\\) , \\(3\\dfrac{1}{2}\\) , \\(\\dfrac{1}{2}\\)', '\\(\\dfrac{1}{2}\\) , \\(\\dfrac{17}{12}\\) , \\(3\\dfrac{1}{2}\\) , \\(\\dfrac{4}{7}\\)'] ci=0 CA: \(\dfrac{1}{2}\) , \(\dfrac{4}{7}\) , \(\dfrac{17}{12}\) , \(3\dfrac{1}{2}\) S: As decimals: \(\dfrac{4}{7}\approx0.57\), \(\dfrac{17}{12}\approx1.42\), \(3\dfrac{1}{2}=3.5\), \(\dfrac{1}{2}=0.5\).
Ascending: \(\dfrac{1}{2}, \dfrac{4}{7}, \dfrac{17}{12}, 3\dfrac{1}{2}\). --- [11409] ID=22637 TYPE=2 --- Q: Find the sum of all the common factors of 18 and 27. [?] A: ['13', None, None, None] S: Factors of 18: 1, 2, 3, 6, 9, 18.
Factors of 27: 1, 3, 9, 27.
Common factors: 1, 3, 9.
Sum = 1 + 3 + 9 = 13. --- [11416] ID=22644 TYPE=1 --- Q: \(1-\dfrac{2}{5}-\dfrac{1}{6}\) = ______ A: ['\\(\\frac{3}{11}\\)', '\\(\\frac{13}{30}\\)', '\\(\\frac{17}{30}\\)', '\\(\\frac{8}{11}\\)'] ci=1 CA: \(\frac{13}{30}\) S: Use a common denominator of 30: \(1=\dfrac{30}{30}\), \(\dfrac{2}{5}=\dfrac{12}{30}\), \(\dfrac{1}{6}=\dfrac{5}{30}\).
So \(\dfrac{30}{30}-\dfrac{12}{30}-\dfrac{5}{30}=\dfrac{13}{30}\). --- [11417] ID=22645 TYPE=1 --- Q: Ravi drank \(\dfrac{3}{4}\) \(\ell\) of water.
His sister drank \(\dfrac{1}{5}\) \(\ell\) less water than he did.
How much water did they drink altogether? A: ['\\(1\\frac{7}{10}\\) \\(\\ell\\)', '\\(1\\frac{3}{10}\\) \\(\\ell\\)', '\\(\\frac{19}{20}\\) \\(\\ell\\)', '\\(\\frac{11}{20}\\) \\(\\ell\\)'] ci=1 CA: \(1\frac{3}{10}\) \(\ell\) S: Sister drank \(\dfrac{3}{4}-\dfrac{1}{5}=\dfrac{15}{20}-\dfrac{4}{20}=\dfrac{11}{20}\) litre.
Altogether: \(\dfrac{3}{4}+\dfrac{11}{20}=\dfrac{15}{20}+\dfrac{11}{20}=\dfrac{26}{20}=1\dfrac{6}{20}=1\dfrac{3}{10}\) litre. --- [11419] ID=22647 TYPE=2 --- Q: 364 × 27 = A: ['9828', None, None, None] S: 364 × 27 = 364 × 20 + 364 × 7 = 7280 + 2548 = 9828. --- [11430] ID=22658 TYPE=1 --- Q: 9 tens 4 tenths 7 thousandths = A: ['9.047', '90.47', '90.047', '90.407'] ci=3 CA: 90.407 S: 9 tens = 90, 4 tenths = 0.4, 7 thousandths = 0.007.
Sum = 90 + 0.4 + 0.007 = 90.407. --- [11438] ID=22666 TYPE=2 --- Q: Arrange these numbers from the greatest to the smallest.
$$\frac{2}{5}$$ , 0.403 , 0.043
[?] , [?] , [?] A: ['0.403', '\\(\\dfrac{2}{5}\\)', '0.043', None] S: Convert \(\dfrac{2}{5}=0.4\).
Compare 0.403, 0.4, 0.043.
Greatest to smallest: 0.403, \(\dfrac{2}{5}\) (0.4), 0.043. --- [11443] ID=22671 TYPE=2 --- Q: Bag A contains 26.5 kg more peanuts than Bag B. After 4.55 kg of peanuts were removed from Bag B and placed into Bag A, the mass of Bag A was five times the mass of Bag B. What was the mass of peanuts in Bag B at first? [?] A: ['13.45', None, None, None] S: After moving 4.55 kg, the difference between the bags becomes 26.5 + 2 × 4.55 = 35.6 kg.
Bag A is now 5 times Bag B, so the difference is 4 units = 35.6 kg, giving 1 unit (Bag B now) = 35.6 ÷ 4 = 8.90 kg.
Bag B at first = 8.90 + 4.55 = 13.45 kg. --- [11446] ID=22674 TYPE=1 --- Q: In the following number pattern, what is the missing number?
12 878, 12 978, 13 978, 14 078, 15 078, , 16 178, 16 278 A: ['16 078', '15 178', '15 079', '14 978'] ci=1 CA: 15 178 S: The pattern alternates +100 then +1000: 12 878 (+100) 12 978 (+1000) 13 978 (+100) 14 078 (+1000) 15 078 (+100) 15 178 (+1000) 16 178 (+100) 16 278.
The missing number is 15 078 + 100 = 15 178.