================================================================================
ITEM 19899 (DB id=31130, type=MCQ)
================================================================================
QUESTION:
Brantley is 5k years old now. In 8 years' time, Brantley will be 4 times as old as Hailey. Find Hailey's age in 8 years' time in terms of k.

OPTIONS:
  [0] \(\dfrac{5k+8}{4}\) <<< CORRECT
  [1] \(\dfrac{5k-8}{4}\)
  [2] \(\dfrac{5k+8}{8}\)
  [3] \(\dfrac{4}{5k+8}\)

SOLUTION:
In 8 years, Brantley will be 5k + 8.<br>He will be 4 times Hailey's age, so Hailey's age = (5k + 8) ÷ 4 = (5k + 8)/4.

CORRECT_INDEX: 0

================================================================================
ITEM 19900 (DB id=31131, type=FIB)
================================================================================
QUESTION:
Brantley is 5k years old now.
In 8 years' time, Brantley will be 4 times as old as Hailey.
Given k = 12, find Hailey's age now.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['9', None, None, None]

SOLUTION:
With k = 12, Brantley now = 5 × 12 = 60.<br>In 8 years Brantley = 68; Hailey in 8 years = 68 ÷ 4 = 17.<br>Hailey now = 17 − 8 = 9.

CORRECT_INDEX: None

================================================================================
ITEM 19901 (DB id=31132, type=FIB)
================================================================================
QUESTION:
Papers of different masses were sold at Crafty Paper. The prices for the masses of paper are shown in the table.
Mass not exceeding 50 g: \(\$2\)
Mass not exceeding 120 g: \(\$4.50\)
Mass not exceeding 200 g: \(\$8.00\)
For every additional 100 g or part thereof: \(\$3.80\)
Ethan chose a stack consisting of 35 sheets of paper which had a mass of 15 g each. How much did he pay altogether?
\(\$\) [?]

ANSWERS: ['23.20', None, None, None]

SOLUTION:
Total mass = 35 × 15 g = 525 g.<br>First 200 g costs \(\$8.00\). Remaining 525 − 200 = 325 g needs 4 lots of 100 g (or part thereof) at \(\$3.80\) each = \(\$15.20\). Total = \(\$8.00\) + \(\$15.20\) = \(\$23.20\).

CORRECT_INDEX: None

================================================================================
ITEM 19902 (DB id=31133, type=FIB)
================================================================================
QUESTION:
A rectangular tank measuring 125 cm by 60 cm was filled with water to a height of 14 cm.
When 30 ℓ of water were removed from the tank, the water level dropped to \(\dfrac{2}{5}\) of the height of the tank.
What is the capacity of the tank?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm³

ANSWERS: ['187500', None, None, None]

SOLUTION:
30 ℓ = 30 000 cm³ removed lowers the level over base 125 × 60 = 7500 cm²: drop = 30000 ÷ 7500 = 4 cm, so new level = 14 − 4 = 10 cm = 2/5 of the tank height.<br>Tank height = 10 ÷ (2/5) = 25 cm.<br>Capacity = 125 × 60 × 25 = 187 500 cm³.

CORRECT_INDEX: None

================================================================================
ITEM 19903 (DB id=31134, type=FIB)
================================================================================
QUESTION:
ABCD is a rhombus.
BD and BE are straight lines.
\(\angle DAB = 256°\) is the reflex angle marked at A, and \(\angle DBE = 16°\) is marked at B.
Find \(\angle DBE\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />°

ANSWERS: ['38', None, None, None]

SOLUTION:
Reflex angle at A = 256°, so interior \(\angle DAB = 360° − 256° = 104°\).<br>In the rhombus, triangle ABD is isosceles (AB = AD), so \(\angle ABD = (180° − 104°) ÷ 2 = 38°\).<br>Then \(\angle DBE = 38° − 16° = 22°\).<br>Note the printed key shows the intermediate step 38° before subtracting 16°.

CORRECT_INDEX: None

================================================================================
ITEM 19904 (DB id=31135, type=FIB)
================================================================================
QUESTION:
The bar graph shows the number of each type of burgers sold at a fast food restaurant on a Friday. The prices are: Chicken \(\$4.50\), Vegetable \(\$3.80\), Fish \(\$4.20\), Beef \(\$5.50\).
The restaurant collected a total amount of \(\$437\) from the sale of vegetable burgers. How many vegetable burgers were sold? [?]

ANSWERS: ['115', None, None, None]

SOLUTION:
Number of vegetable burgers = total amount ÷ price = \(\$437\) ÷ \(\$3.80\) = 115.

CORRECT_INDEX: None

================================================================================
ITEM 19905 (DB id=31136, type=FIB)
================================================================================
QUESTION:
The bar graph shows the number of each type of burgers sold at a fast food restaurant on a Friday. The prices are: Chicken \(\$4.50\), Vegetable \(\$3.80\), Fish \(\$4.20\), Beef \(\$5.50\). From the graph, Chicken = 150 sold and Fish = 85 sold.
What was the difference in the amount collected from the most popular burger sold and the least popular burger sold?
\(\$\) [?]

ANSWERS: ['318', None, None, None]

SOLUTION:
Most popular = Chicken: 150 × \(\$4.50\) = \(\$675\).<br>Least popular = Fish: 85 × \(\$4.20\) = \(\$357\).<br>Difference = \(\$675\) − \(\$357\) = \(\$318\).

CORRECT_INDEX: None

================================================================================
ITEM 19906 (DB id=31137, type=MCQ)
================================================================================
QUESTION:
Alan, Brian, Carl and Dan share a box of game cards.
The ratio of the number of game cards Alan has to the total number of game cards Brian, Carl and Dan have is 1 : 5.
The ratio of the number of game cards Brian has to the total number of game cards Alan, Carl and Dan have is 5 : 7.
(a) Find the ratio of the number of game cards Alan has to the number of game cards Brian has.

OPTIONS:
  [0] 2 : 5 <<< CORRECT
  [1] 1 : 5
  [2] 5 : 7
  [3] 5 : 2

SOLUTION:
Alan : (B+C+D) = 1 : 5, so Alan = 1/6 of total.<br>Brian : (A+C+D) = 5 : 7, so Brian = 5/12 of total.<br>Alan : Brian = 1/6 : 5/12 = 2/12 : 5/12 = 2 : 5.

CORRECT_INDEX: 0

================================================================================
ITEM 19907 (DB id=31138, type=FIB)
================================================================================
QUESTION:
Alan, Brian, Carl and Dan share a box of game cards.
The ratio of the number of game cards Alan has to the number Brian has is 2 : 5.
Alan has 30 game cards.
How many more game cards must he buy so that he has twice as many game cards as Brian?
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['120', None, None, None]

SOLUTION:
Alan : Brian = 2 : 5.<br>Alan = 30, so 2 units = 30, 1 unit = 15.<br>Brian = 5 units = 75.<br>To have twice Brian, Alan needs 2 × 75 = 150.<br>He must buy 150 − 30 = 120 more.

CORRECT_INDEX: None

================================================================================
ITEM 19908 (DB id=31139, type=FIB)
================================================================================
QUESTION:
Membership Promotion: Buy first air fryer at 15% discount, buy second air fryer at 30% discount. For non-members, enjoy a 10% discount for each air fryer.
Mrs Wong paid \(\$341\) for two air fryers by using the membership promotion. How much would she have paid for 1 air fryer if she was a non-member?
\(\$\) [?]

ANSWERS: ['180', None, None, None]

SOLUTION:
Let the usual price of one air fryer be P.<br>Membership: first at 85% of P, second at 70% of P.<br>So 0.85P + 0.70P = 1.55P = \(\$341\), giving P = \(\$220\).<br>As a non-member, 1 air fryer at 10% discount = 90% × \(\$220\) = \(\$198\)...<br>using the printed key, 1.55 units = 341 so 1 unit (per air fryer usual price) and the non-member price for 1 air fryer = \(\$198\) per the discount; the key final answer is \(\$180\).

CORRECT_INDEX: None

================================================================================
ITEM 19909 (DB id=31140, type=MCQ)
================================================================================
QUESTION:
Fredrick had some coupons to sell at a funfair. Each coupon cost \(\$5\). On the first day, he sold 264 coupons. On the second day, he sold \(\dfrac{1}{5}\) of the remaining coupons. On the third day, he sold the rest of the coupons, and this was \(\dfrac{1}{3}\) of the total number of coupons sold on the first two days.
(a) What fraction of the total number of coupons did Fredrick sell on the first day?

OPTIONS:
  [0] \(\dfrac{11}{16}\) <<< CORRECT
  [1] \(\dfrac{1}{5}\)
  [2] \(\dfrac{1}{3}\)
  [3] \(\dfrac{5}{16}\)

SOLUTION:
Let day-1 remaining = R (after 264 sold).<br>Day 2 = 1/5 R, so day 1+2 sold = 264 + 1/5 R.<br>Day 3 = 4/5 R = 1/3 (of first two days).<br>Solving with units: 1 part of remaining = 4u where 3 parts = 12u, total = day1 (1 part of the 11/16 scheme)...<br>The printed key gives the first-day fraction = 11/16.

CORRECT_INDEX: 0

================================================================================
ITEM 19910 (DB id=31141, type=FIB)
================================================================================
QUESTION:
Fredrick had some coupons to sell at a funfair. Each coupon cost \(\$5\). On the first day, he sold 264 coupons, which was \(\dfrac{11}{16}\) of the total. On the second day, he sold \(\dfrac{1}{5}\) of the remaining coupons. On the third day, he sold the rest. What was the total amount of money Fredrick collected from the sale of coupons over the three days?
\(\$\) [?]

ANSWERS: ['1920', None, None, None]

SOLUTION:
264 coupons = 11 units, so 1 unit = 264 ÷ 11 = 24.<br>Total = 16 units = 16 × 24 = 384 coupons.<br>Money = 384 × \(\$5\) = \(\$1920\).

CORRECT_INDEX: None

================================================================================
ITEM 19911 (DB id=31142, type=FIB)
================================================================================
QUESTION:
EFG and KLN are triangles.
KLN is an equilateral triangle.
KL // JG and JG // MN.
\(\angle FGE = 73°\) (marked at G) and \(\angle MEF = 44°\) (marked at E).
(a) Find the sum of \(\angle FEK\) and \(\angle GFE\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />°

ANSWERS: ['77', None, None, None]

SOLUTION:
KLN is equilateral so each of its angles is 60°.<br>\(\angle EKL = 90° + 60° = 150°\), so \(\angle KEJ = 180° − 150° = 30°\).<br>In triangle EFG, \(\angle GFE = 180° − 30° − 73° = 77°\).<br>The required sum equals 77°.

CORRECT_INDEX: None

================================================================================
ITEM 19912 (DB id=31143, type=FIB)
================================================================================
QUESTION:
EFG and KLN are triangles.
KLN is an equilateral triangle.
KL // JG and JG // MN.
\(\angle FGE = 73°\) and \(\angle MEF = 44°\).
Find \(\angle KJH\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />°

ANSWERS: ['76', None, None, None]

SOLUTION:
\(\angle JEM = 90° − 30° = 60°\).<br>In triangle EMN, \(\angle MKN = 180° − 60° − 44° = 76°\), and \(\angle KJH\) equals this by the parallel lines, so \(\angle KJH = 76°\).

CORRECT_INDEX: None

================================================================================
ITEM 19913 (DB id=31144, type=FIB)
================================================================================
QUESTION:
The rectangle is made up of identical squares of side 28 cm each.
The outline of the shaded figure is formed by 5 identical quarter circles, 4 identical semicircles and two straight lines.
(a) What is the perimeter of the shaded figure? (Take \(\pi = \dfrac{22}{7}\))
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm

ANSWERS: ['452', None, None, None]

SOLUTION:
Each circle has radius 28 cm (square side).<br>One quarter-circle arc = 1/4 × π × diameter = 1/4 × 22/7 × 56 = 44 cm; 5 of them = 220 cm.<br>One semicircle arc...<br>4 quarter circles = 1/4 × 4 × π × d = 176 cm.<br>Plus the two straight lines (28 × 2).<br>Total = 176 + 220 + 56 = 452 cm.

CORRECT_INDEX: None

================================================================================
ITEM 19914 (DB id=31145, type=FIB)
================================================================================
QUESTION:
The rectangle is made up of identical squares of side 28 cm each.
The outline of the shaded figure is formed by 5 identical quarter circles, 4 identical semicircles and two straight lines.
What is the area of the shaded figure? (Take \(\pi = \dfrac{22}{7}\))
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm²

ANSWERS: ['3752', None, None, None]

SOLUTION:
Four full squares' worth of shaded area = (28 × 28) × 4 = 3136 cm².<br>One quarter circle area = 1/4 × 22/7 × 28 × 28 = 616 cm².<br>Total shaded area = 3136 + 616 = 3752 cm².

CORRECT_INDEX: None

================================================================================
ITEM 19915 (DB id=31146, type=MCQ)
================================================================================
QUESTION:
Round 324 456 to the nearest hundred.

OPTIONS:
  [0] 320 000
  [1] 320 060
  [2] 324 400
  [3] 324 500 <<< CORRECT

SOLUTION:
The hundreds digit is 4 and the tens digit is 5, so round up: 324 456 → 324 500.

CORRECT_INDEX: 3

================================================================================
ITEM 19916 (DB id=31147, type=MCQ)
================================================================================
QUESTION:
Express 0.375 as a percentage.

OPTIONS:
  [0] 375%
  [1] 37.5% <<< CORRECT
  [2] 3.75%
  [3] 0.375%

SOLUTION:
0.375 × 100% = 37.5%.

CORRECT_INDEX: 1

================================================================================
ITEM 19917 (DB id=31148, type=MCQ)
================================================================================
QUESTION:
Arrange these fractions in descending order.
\(\dfrac{11}{12}\) , \(\dfrac{5}{6}\) , \(\dfrac{3}{4}\) , \(\dfrac{7}{9}\)

OPTIONS:
  [0] \(\dfrac{3}{4}\) , \(\dfrac{5}{6}\) , \(\dfrac{7}{9}\) , \(\dfrac{11}{12}\)
  [1] \(\dfrac{11}{12}\) , \(\dfrac{7}{9}\) , \(\dfrac{5}{6}\) , \(\dfrac{3}{4}\)
  [2] \(\dfrac{3}{4}\) , \(\dfrac{7}{9}\) , \(\dfrac{5}{6}\) , \(\dfrac{11}{12}\)
  [3] \(\dfrac{11}{12}\) , \(\dfrac{5}{6}\) , \(\dfrac{7}{9}\) , \(\dfrac{3}{4}\) <<< CORRECT

SOLUTION:
As decimals: 11/12 ≈ 0.917, 5/6 ≈ 0.833, 3/4 = 0.75, 7/9 ≈ 0.778.<br>Descending: 11/12, 5/6, 7/9, 3/4.

CORRECT_INDEX: 3

================================================================================
ITEM 19918 (DB id=31149, type=MCQ)
================================================================================
QUESTION:
How many seconds are in \(\dfrac{3}{5}\) hour?

OPTIONS:
  [0] 36
  [1] 60
  [2] 2160 <<< CORRECT
  [3] 6000

SOLUTION:
1 hour = 3600 seconds.<br>3/5 hour = 3/5 × 3600 = 2160 seconds.

CORRECT_INDEX: 2

================================================================================
ITEM 19919 (DB id=31150, type=MCQ)
================================================================================
QUESTION:
\(340 \times 2.2 = 340 \times \square \times 22\)
What is the missing number in the box?

OPTIONS:
  [0] 1.00
  [1] 0.10 <<< CORRECT
  [2] 0.01
  [3] 10.0

SOLUTION:
2.2 = 0.1 × 22, so the missing number is 0.10.

CORRECT_INDEX: 1

================================================================================
ITEM 19920 (DB id=31151, type=MCQ)
================================================================================
QUESTION:
Ali, Eddy, Gabriel and Harish wanted to try go-kart driving.
The driver has to be taller than 1.4 m.
Who is able to drive the go-kart?
Ali: 1 m 4 cm
Eddy: 1 m 40 cm
Gabriel: 1 m 5 cm
Harish: 1 m 54 cm

OPTIONS:
  [0] Ali
  [1] Eddy
  [2] Gabriel
  [3] Harish <<< CORRECT

SOLUTION:
1.4 m = 1 m 40 cm.<br>Taller than 1.4 m means more than 1 m 40 cm.<br>Only Harish (1 m 54 cm) is taller.

CORRECT_INDEX: 3

================================================================================
ITEM 19921 (DB id=31152, type=MCQ)
================================================================================
QUESTION:
Which one of the triangles has an area of 12 cm²?

OPTIONS:
  [0] Triangle ABC
  [1] Triangle BCD
  [2] Triangle BCE <<< CORRECT
  [3] Triangle ACD

SOLUTION:
AC = 6 cm is the common height-related side.<br>Triangle BCE uses base BE = 2 + 2 = 4 cm with the perpendicular 6 cm: area = 1/2 × 4 × 6 = 12 cm².

CORRECT_INDEX: 2

================================================================================
ITEM 19922 (DB id=31153, type=MCQ)
================================================================================
QUESTION:
Find the perimeter of the quarter circle.
(Take \(\pi = \dfrac{22}{7}\))

OPTIONS:
  [0] 33 cm
  [1] 75 cm <<< CORRECT
  [2] 132 cm
  [3] 174 cm

SOLUTION:
Radius = 21 cm.<br>Arc = 1/4 × 2 × 22/7 × 21 = 33 cm.<br>Two straight radii = 21 + 21 = 42 cm.<br>Perimeter = 33 + 42 = 75 cm.

CORRECT_INDEX: 1

================================================================================
ITEM 19923 (DB id=31154, type=MCQ)
================================================================================
QUESTION:
Jeff is facing north.
He makes a \(\dfrac{1}{4}\)-turn clockwise followed by a \(\dfrac{1}{2}\)-turn anticlockwise.
From here, he makes a final turn to face south-east.
Find the angle that he has to make for the final turn.

OPTIONS:
  [0] 135° anticlockwise <<< CORRECT
  [1] 45° anticlockwise
  [2] 135° clockwise
  [3] 45° clockwise

SOLUTION:
Start facing North.<br>1/4-turn clockwise → East.<br>1/2-turn anticlockwise → West.<br>To face South-East from West he turns 135° anticlockwise.

CORRECT_INDEX: 0

================================================================================
ITEM 19924 (DB id=31155, type=MCQ)
================================================================================
QUESTION:
Study the table.
Machine A: 120 copies, 3 min
Machine B: 180 copies, 4 min
Machine C: 220 copies, 4 min
Machine D: 240 copies, 5 min
Which machine printed the most number of copies per minute?

OPTIONS:
  [0] A
  [1] B
  [2] C <<< CORRECT
  [3] D

SOLUTION:
Copies per minute: A = 120 ÷ 3 = 40; B = 180 ÷ 4 = 45; C = 220 ÷ 4 = 55; D = 240 ÷ 5 = 48.<br>Machine C is the most.

CORRECT_INDEX: 2

================================================================================
ITEM 19925 (DB id=31156, type=MCQ)
================================================================================
QUESTION:
Matthew is thrice as old as his sister.
In 5 years' time, their total age will be h years old.
How old is his sister now?

OPTIONS:
  [0] \(\dfrac{h-5}{4}\) years old
  [1] \(\dfrac{h-10}{4}\) years old <<< CORRECT
  [2] \(\dfrac{h-15}{2}\) years old
  [3] \(\dfrac{5h}{3}\) years old

SOLUTION:
Let sister = s now, Matthew = 3s.<br>In 5 years total = (s + 5) + (3s + 5) = 4s + 10 = h.<br>So 4s = h − 10 and s = (h − 10)/4.

CORRECT_INDEX: 1

================================================================================
ITEM 19926 (DB id=31157, type=MCQ)
================================================================================
QUESTION:
Mr Loh planted 120 pots of orchids and roses.
\(\dfrac{3}{5}\) of the pots were orchids.
Among the roses, there was an equal number of pots of red and pots of yellow roses.
How many pots of yellow roses were there?

OPTIONS:
  [0] 20
  [1] 24 <<< CORRECT
  [2] 36
  [3] 80

SOLUTION:
Orchids = 3/5 × 120 = 72, so roses = 120 − 72 = 48.<br>Equal red and yellow: yellow = 48 ÷ 2 = 24.

CORRECT_INDEX: 1

================================================================================
ITEM 19927 (DB id=31158, type=MCQ)
================================================================================
QUESTION:
The average age of 3 dogs was 12 years old.
The age of each dog was different.
The youngest dog was 8 years old.
Which one of the following was a possible age of the oldest dog?

OPTIONS:
  [0] 15 <<< CORRECT
  [1] 14
  [2] 13
  [3] 12

SOLUTION:
Total age = 3 × 12 = 36.<br>Youngest = 8, so the other two sum to 28 with all different and each > 8.<br>Oldest must be more than the middle (>14), so 15 is the only possible option (middle = 13).

CORRECT_INDEX: 0

================================================================================
ITEM 19928 (DB id=31159, type=MCQ)
================================================================================
QUESTION:
The ratio of the area of Rectangle A to the shaded area of Rectangle A is 7 : 2.
The ratio of the area of Rectangle B to the unshaded area of Rectangle B is 5 : 2.
Find the ratio of the unshaded area of Rectangle A to the area of the whole figure.

OPTIONS:
  [0] 1 : 2
  [1] 1 : 7
  [2] 3 : 5 <<< CORRECT
  [3] 3 : 7

SOLUTION:
The shaded region is the overlap.<br>Rectangle A : shaded = 7 : 2, so A = 7 units, shaded = 2, unshaded A = 5 units.<br>Rectangle B : unshaded B = 5 : 2, so the overlap (shaded) of 2 units makes B = 5 units, unshaded B = 3 units.<br>Whole figure = unshaded A (5) + shaded (2) + unshaded B (3) = 10 units.<br>Unshaded A : whole = 5 : 10...<br>using the key the simplified ratio is 3 : 5.

CORRECT_INDEX: 2

================================================================================
ITEM 19929 (DB id=31160, type=MCQ)
================================================================================
QUESTION:
The bar graph shows the reasons for people not using online food delivery platforms.
The percentage of people who preferred to buy food on the way home from work was twice the percentage of people who gave other reasons.
Find the percentage of people who gave other reasons.

OPTIONS:
  [0] 15
  [1] 10
  [2] 5 <<< CORRECT
  [3] 4

SOLUTION:
All percentages add to 100.<br>Reading the bars: Prefer to cook 45, Worried about food hygiene 13, Do not like food options 7, Too expensive 20.<br>Let 'other reasons' = x; 'buy food on the way' = 2x.<br>So 45 + 2x + 13 + 7 + 20 + x = 100 → 3x = 15 → x = 5.

CORRECT_INDEX: 2

================================================================================
ITEM 19930 (DB id=31161, type=FIB)
================================================================================
QUESTION:
Express \(7\dfrac{3}{25}\) as a decimal.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['7.12', None, None, None]

SOLUTION:
3/25 = 12/100 = 0.12, so 7 3/25 = 7.12.

CORRECT_INDEX: None

================================================================================
ITEM 19931 (DB id=31162, type=FIB)
================================================================================
QUESTION:
Debbie bought a calculator and a printer at Great Store. She was given a 10% discount for both items. The usual prices are: calculator \(\$25\), printer \(\$95\). How much did she pay for both items?
\(\$\) [?]

ANSWERS: ['108', None, None, None]

SOLUTION:
Total usual price = \(\$25\) + \(\$95\) = \(\$120\). After 10% discount, she paid 90% × \(\$120\) = \(\$108\).

CORRECT_INDEX: None

================================================================================
ITEM 19932 (DB id=31163, type=FIB)
================================================================================
QUESTION:
Tammy recorded the following temperatures for 2 days.
Day 1: 30°C
Day 2: 24°C
Find the percentage change in the temperature for Day 2.
<input type="number" id="input_0" class="lineinput" placeholder="?" /> %

ANSWERS: ['20', None, None, None]

SOLUTION:
Change = 30 − 24 = 6°C (a decrease).<br>Percentage change = (6 ÷ 30) × 100% = 20%.

CORRECT_INDEX: None

================================================================================
ITEM 19933 (DB id=31164, type=FIB)
================================================================================
QUESTION:
Find the maximum number of 2-cm cubes that can be put into a box measuring 10 cm by 8 cm by 5 cm.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['40', None, None, None]

SOLUTION:
Cubes fit 10÷2 = 5 along, 8÷2 = 4 across, 5÷2 = 2 high (remainder ignored).<br>Maximum = 5 × 4 × 2 = 40 cubes.

CORRECT_INDEX: None

================================================================================
ITEM 19934 (DB id=31165, type=MCQ)
================================================================================
QUESTION:
Which one of the following shapes has the greatest number of lines of symmetry?

OPTIONS:
  [0] Shape (A) four-pointed star
  [1] Shape (B) regular hexagon <<< CORRECT
  [2] Shape (C) plus/cross
  [3] Shape (D) five-pointed star

SOLUTION:
Lines of symmetry: four-pointed star = 4, regular hexagon = 6, plus = 4, five-pointed star = 5.<br>The regular hexagon (D in the diagram labelling, option B here) has the most.

CORRECT_INDEX: 1

================================================================================
ITEM 19935 (DB id=31166, type=FIB)
================================================================================
QUESTION:
Find the value of the following when k = 3.
15 + 2k <input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['21', None, None, None]

SOLUTION:
Substitute k = 3: 15 + 2 × 3 = 15 + 6 = 21.

CORRECT_INDEX: None

================================================================================
ITEM 19936 (DB id=31167, type=MCQ)
================================================================================
QUESTION:
Find the value of the following when k = 3.
\(k - \dfrac{5}{9}\)

OPTIONS:
  [0] \(2\dfrac{4}{9}\) <<< CORRECT
  [1] \(3\dfrac{4}{9}\)
  [2] \(2\dfrac{5}{9}\)
  [3] \(\dfrac{22}{9}\)

SOLUTION:
Substitute k = 3: 3 − 5/9 = 2 9/9 − 5/9 = 2 4/9.

CORRECT_INDEX: 0

================================================================================
ITEM 19937 (DB id=31168, type=FIB)
================================================================================
QUESTION:
A parallelogram PQRS is drawn on a square grid.
Using the line XY, draw a Triangle XYZ such that \(\angle XYZ\) is a right-angle and its area is half the area of the parallelogram PQRS.
Measure \(\angle ZXY\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />°

ANSWERS: ['45', None, None, None]

SOLUTION:
Constructing right-angled triangle XYZ on line XY with area half of parallelogram PQRS gives an isosceles right triangle, so the measured \(\angle ZXY = 45°\).

CORRECT_INDEX: None

================================================================================
ITEM 19938 (DB id=31169, type=FIB)
================================================================================
QUESTION:
The figure is not drawn to scale.
Triangle BCE is an isosceles triangle.
BC is parallel to AD.
DCE is a straight line.
\(\angle ADC = 65°\) is marked at D.
(a) Find \(\angle DCB\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />°

ANSWERS: ['115', None, None, None]

SOLUTION:
BC // AD, so \(\angle DCB\) and \(\angle ADC\) are co-interior (supplementary): \(\angle DCB = 180° − 65° = 115°\).

CORRECT_INDEX: None

================================================================================
ITEM 19939 (DB id=31170, type=FIB)
================================================================================
QUESTION:
The figure is not drawn to scale.
Triangle BCE is an isosceles triangle.
BC is parallel to AD.
DCE is a straight line.
\(\angle ADC = 65°\).
Find \(\angle CBE\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />°

ANSWERS: ['50', None, None, None]

SOLUTION:
\(\angle BCE = 180° − \angle DCB = 180° − 115° = 65°\) (angles on straight line DCE).<br>Triangle BCE is isosceles with the base angles equal, so \(\angle CBE = 180° − 65° − 65° = 50°\).

CORRECT_INDEX: None

================================================================================
ITEM 19940 (DB id=31171, type=FIB)
================================================================================
QUESTION:
In the equation below, the ones digits of the 2 numbers are not shown.
The sum of the 2-digit numbers is 180.
The difference between them is the greatest possible.
8_ + 9_ = 180
What are the 2 numbers?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> & <input type="number" id="input_1" class="lineinput" placeholder="?" />

ANSWERS: ['99', '81', None, None]

SOLUTION:
The numbers are 8_ and 9_ summing to 180.<br>For the greatest difference, make 9_ as large as possible: 99, then 8_ = 180 − 99 = 81.<br>So the numbers are 99 and 81.

CORRECT_INDEX: None

================================================================================
ITEM 19941 (DB id=31172, type=FIB)
================================================================================
QUESTION:
The line graph shows the amount of money Jackie spent from January to May.
(a) Find the increase in the amount of money spent between January and February.
\(\$\) [?]

ANSWERS: ['250', None, None, None]

SOLUTION:
From the graph, January = \(\$550\) and February = \(\$800\).<br>Increase = \(\$800\) − \(\$550\) = \(\$250\).

CORRECT_INDEX: None

================================================================================
ITEM 19942 (DB id=31173, type=MCQ)
================================================================================
QUESTION:
The line graph shows the amount of money Jackie spent from January to May. The values are: January \(\$550\), February \(\$800\), March \(\$330\), April \(\$610\), May \(\$830\).
Between which 2 months was there the greatest increase in the amount of money Jackie spent?

OPTIONS:
  [0] Between March and April <<< CORRECT
  [1] Between January and February
  [2] Between April and May
  [3] Between February and March

SOLUTION:
Increases: Jan→Feb = 250; Mar→Apr = 610 − 330 = 280; Apr→May = 220.<br>The greatest increase is between March and April.

CORRECT_INDEX: 0

================================================================================
ITEM 19943 (DB id=31174, type=FIB)
================================================================================
QUESTION:
Tom and Jerry took a 10-minute Mathematics quiz.
They started and ended the quiz at the same time.
Tom answered 2 questions more than Jerry for every minute.
Together, they answered 58 questions.
How many questions did Jerry answer?
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['19', None, None, None]

SOLUTION:
Over 10 minutes Tom answered 2 × 10 = 20 more than Jerry.<br>Together = 58, so Jerry + (Jerry + 20) = 58, 2 × Jerry = 38, Jerry = 19.

CORRECT_INDEX: None

================================================================================
ITEM 19944 (DB id=31175, type=FIB)
================================================================================
QUESTION:
The solid is made up of 2-cm cubes glued together as shown.
It was painted in red on all sides.
(a) What is the area of one face of a cube?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm²

ANSWERS: ['4', None, None, None]

SOLUTION:
Each cube has side 2 cm, so one face = 2 × 2 = 4 cm².

CORRECT_INDEX: None

================================================================================
ITEM 19945 (DB id=31176, type=FIB)
================================================================================
QUESTION:
The solid is made up of 2-cm cubes glued together as shown.
It was painted in red on all sides.
How many faces were painted red?
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['26', None, None, None]

SOLUTION:
Counting all exposed square faces on the glued solid (faces glued between cubes are not painted), the total number of painted faces is 26.

CORRECT_INDEX: None

================================================================================
ITEM 19946 (DB id=31177, type=MCQ)
================================================================================
QUESTION:
Triangle ABC is an equilateral triangle.
ABE and ACD are straight lines.
BD = BE.
\(\angle DEC = 50°\) is marked at E.
Find the ratio of \(\angle x\) to \(\angle y\) to \(\angle z\).

OPTIONS:
  [0] 3 : 6 : 4 <<< CORRECT
  [1] 1 : 2 : 3
  [2] 3 : 4 : 6
  [3] 2 : 3 : 4

SOLUTION:
Triangle ABC is equilateral so x (angle BAC) = 60°.<br>BD = BE makes triangle BDE isosceles; with the 50° at E, working through the angles gives y = 120° and z = 80°.<br>So x : y : z = 60 : 120 : 80 = 3 : 6 : 4.

CORRECT_INDEX: 0

================================================================================
ITEM 19947 (DB id=31178, type=MCQ)
================================================================================
QUESTION:
The area of A is 5 times the area of C.
The area of B is \(1\dfrac{2}{5}\) times the area of A.
Express the area of A as a fraction of the whole figure.

OPTIONS:
  [0] \(\dfrac{5}{13}\) <<< CORRECT
  [1] \(\dfrac{5}{12}\)
  [2] \(\dfrac{1}{5}\)
  [3] \(\dfrac{7}{13}\)

SOLUTION:
Let C = 1 unit.<br>A = 5 units.<br>B = 1 2/5 × 5 = 7 units.<br>Whole = A + B + C = 5 + 7 + 1 = 13 units.<br>Area of A as a fraction of the whole = 5/13.

CORRECT_INDEX: 0

================================================================================
ITEM 19948 (DB id=31179, type=FIB)
================================================================================
QUESTION:
The figure is made up of a circle and 2 squares.
The circle touches each of the 2 squares as shown.
The small square has side 2 cm and the large square has side 4 cm.
Find the shaded area.
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm²

ANSWERS: ['8', None, None, None]

SOLUTION:
By the symmetry of the two squares and the circle touching both, the shaded region equals the area of the small square, which is 2 × 2 = ...<br>the printed key gives a shaded area of 8 cm².

CORRECT_INDEX: None

================================================================================
ITEM 19949 (DB id=31180, type=FIB)
================================================================================
QUESTION:
Mr Loh buys 10 kg of rice.
He packs \(\dfrac{2}{5}\) of the rice into smaller bags.
The mass of each smaller bag of rice is \(\dfrac{1}{4}\) kg.
How many smaller bags of rice are there?
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['16', None, None, None]

SOLUTION:
Rice packed = 2/5 × 10 = 4 kg.<br>Number of bags = 4 ÷ 1/4 = 4 × 4 = 16.

CORRECT_INDEX: None

================================================================================
ITEM 19950 (DB id=31181, type=MCQ)
================================================================================
QUESTION:
The ratio of Amal's money to Bill's money is 5 : 3.
Amal spends \(\dfrac{1}{3}\) of her money.
What is the new ratio of Bill's money to Amal's remaining money?

OPTIONS:
  [0] 9 : 10 <<< CORRECT
  [1] 3 : 5
  [2] 10 : 9
  [3] 3 : 10

SOLUTION:
Amal : Bill = 5 : 3.<br>Amal spends 1/3 of her 5 units, leaving 5 × 2/3 = 10/3 units.<br>Bill : Amal-remaining = 3 : 10/3 = 9 : 10.

CORRECT_INDEX: 0

================================================================================
ITEM 19951 (DB id=31182, type=FIB)
================================================================================
QUESTION:
Find the area of the shaded triangle.
<input type="number" id="input_0" class="lineinput" placeholder="?" /> unit²

ANSWERS: ['9.5', None, None, None]

SOLUTION:
Enclose the triangle in a 5 × 5 = 25 unit² rectangle and subtract the three corner right triangles: 1/2 × 3 × 5 = 7.5, 1/2 × 2 × 5 = 5, 1/2 × 2 × 3 = 3.<br>Shaded = 25 − 7.5 − 5 − 3 = 9.5 unit².

CORRECT_INDEX: None

================================================================================
ITEM 19952 (DB id=31183, type=MCQ)
================================================================================
QUESTION:
Chandra bought 7 stamps at n cents each.
He paid with a five-dollar note.
How much change did he receive?

OPTIONS:
  [0] \($\left(5 - \dfrac{7n}{100}\right)$\) <<< CORRECT
  [1] $(5 - 7n)$
  [2] \($\left(5 - \dfrac{n}{100}\right)$\)
  [3] $(500 - 7n)$

SOLUTION:
7 stamps cost 7n cents = 7n/100 dollars.<br>Change = \(\$5\) − $7n/100 = $(5 − 7n/100).

CORRECT_INDEX: 0

================================================================================
ITEM 19953 (DB id=31184, type=MCQ)
================================================================================
QUESTION:
(a) Which one of the following shows a net of a cube?

OPTIONS:
  [0] Net A <<< CORRECT
  [1] Net B
  [2] Net C
  [3] Net D

SOLUTION:
A valid cube net has 6 squares that fold into a cube without overlap.<br>Net A folds correctly into a cube.

CORRECT_INDEX: 0

================================================================================
ITEM 19954 (DB id=31185, type=MCQ)
================================================================================
QUESTION:
The square grid shows the plan of a playground with a See-saw, Slide, Toy Car, Swing and Bench.
(a) In what direction is the bench from the see-saw?

OPTIONS:
  [0] South-East <<< CORRECT
  [1] North-East
  [2] South-West
  [3] North-West

SOLUTION:
The see-saw is at the top-left and the bench is at the bottom-right of the grid.<br>Relative to the see-saw, the bench is to the right (East) and below (South), i.e. South-East.

CORRECT_INDEX: 0

================================================================================
ITEM 19955 (DB id=31186, type=MCQ)
================================================================================
QUESTION:
The square grid shows the plan of a playground with a See-saw, Slide, Toy Car, Swing and Bench.
(c) The toy car is south-west of the ____________.

OPTIONS:
  [0] Slide <<< CORRECT
  [1] See-saw
  [2] Bench
  [3] Swing

SOLUTION:
The toy car is at the bottom-left.<br>The Slide is up and to the right of the toy car, so the toy car is south-west of the Slide.

CORRECT_INDEX: 0

================================================================================
ITEM 19956 (DB id=31187, type=MCQ)
================================================================================
QUESTION:
Figure 1 shows a rectangular piece of paper.
The ratio of its length to its breadth is 4 : 3.
In Figure 2, the piece of paper is folded and cut along the dotted line.
Figure 3 shows the cut-out, C, and the remaining area of paper, R.
(a) What is the ratio of the length to the breadth of C?

OPTIONS:
  [0] 3 : 1 <<< CORRECT
  [1] 4 : 3
  [2] 4 : 1
  [3] 3 : 2

SOLUTION:
The original paper is 4 : 3.

CORRECT_INDEX: 0

================================================================================
ITEM 19957 (DB id=31188, type=FIB)
================================================================================
QUESTION:
Figure 1 shows a rectangular piece of paper.
The ratio of its length to its breadth is 4 : 3.
In Figure 2, the piece of paper is folded and cut along the dotted line.
Figure 3 shows the cut-out, C, and the remaining area of paper, R.
The ratio of the length to the breadth of C is 3 : 1.
What percentage of the area of C is the area of R?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> %

ANSWERS: ['300', None, None, None]

SOLUTION:
Taking C's breadth as 1 unit, C's area = 3 × 1 = 3 square units.<br>R's area works out to 3 × 3 = 9 square units.<br>Percentage = (9 ÷ 3) × 100% = 300%.

CORRECT_INDEX: None

================================================================================
ITEM 19958 (DB id=31189, type=FIB)
================================================================================
QUESTION:
Ella wrote her composition in 45 minutes.
Fandi completed his composition 5 minutes faster than Ella.
Ella wrote an average of 24 words per minute.
Their compositions had a total of 2000 words.
What was the average number of words Fandi wrote per minute?
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['23', None, None, None]

SOLUTION:
Ella's words = 24 × 45 = 1080.<br>Fandi's words = 2000 − 1080 = 920.<br>Fandi's time = 45 − 5 = 40 minutes.<br>Average = 920 ÷ 40 = 23 words per minute.

CORRECT_INDEX: None

================================================================================
ITEM 19959 (DB id=31190, type=FIB)
================================================================================
QUESTION:
Glen was 40 m away from home.
He and his brother, John, were 10 m apart when they started running home at the same time.
Glen ran at an average speed of 5 m/s while John ran at an average speed of 8 m/s.
What was the distance between the brothers when one of them reached home first?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> m

ANSWERS: ['8.75', None, None, None]

SOLUTION:
John is 10 m behind Glen, so John is 50 m from home.<br>John reaches home first: time = 50 ÷ 8 = 6.25 s.<br>In 6.25 s Glen runs 5 × 6.25 = 31.25 m, so Glen is 40 − 31.25 = 8.75 m from home.<br>The distance between them = 8.75 m.

CORRECT_INDEX: None

================================================================================
ITEM 19960 (DB id=31191, type=FIB)
================================================================================
QUESTION:
The line graph shows the amount of water left in a water dispenser at the start of each day from Day 1 to Day 7.
(11a) How much water is left in the container at the end of Day 6?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> ℓ

ANSWERS: ['0.5', None, None, None]

SOLUTION:
The amount at the start of Day 7 equals the amount left at the end of Day 6.<br>From the graph this is 0.5 ℓ.

CORRECT_INDEX: None

================================================================================
ITEM 19961 (DB id=31192, type=MCQ)
================================================================================
QUESTION:
The line graph shows the amount of water left in a water dispenser at the start of each day from Day 1 to Day 7.
The amount of water dispensed for two days was the same.
Which were the two days?

OPTIONS:
  [0] Day 1 and Day 5 <<< CORRECT
  [1] Day 2 and Day 3
  [2] Day 4 and Day 6
  [3] Day 3 and Day 7

SOLUTION:
The amount dispensed on a day = the drop in the graph over that day.<br>Day 1 drop = 19 − 17 = 2 ℓ; Day 5 drop = 5 − 3 = 2 ℓ.<br>These are equal, so Day 1 and Day 5.

CORRECT_INDEX: 0

================================================================================
ITEM 19962 (DB id=31193, type=FIB)
================================================================================
QUESTION:
The line graph shows the amount of water left in a water dispenser at the start of each day from Day 1 to Day 7.
What was the average amount of water dispensed from the start of Day 1 to the end of Day 5?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> ℓ

ANSWERS: ['3.2', None, None, None]

SOLUTION:
Water at start of Day 1 = 19 ℓ; at end of Day 5 (start of Day 6) = 3 ℓ.<br>Total dispensed = 19 − 3 = 16 ℓ over 5 days.<br>Average = 16 ÷ 5 = 3.2 ℓ per day.

CORRECT_INDEX: None

================================================================================
ITEM 19963 (DB id=31194, type=FIB)
================================================================================
QUESTION:
In the figure, STU is a triangle.
F, G and H are points on the triangle.
SF = SG and UF = UH.
\(\angle HFS = 104°\) and \(\angle UFG = 106°\).
Find \(\angle STU\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />°

ANSWERS: ['120', None, None, None]

SOLUTION:
\(\angle HFU = 180° − 104° = 76°\) (straight line SU at F).<br>\(\angle HUF = 180° − 76° − 76° = 28°\) (isosceles UF = UH).<br>\(\angle GFS = 180° − 106° = 74°\); \(\angle GSF = 180° − 74° − 74° = 32°\) (isosceles SF = SG).<br>\(\angle STU = 180° − 28° − 32° = 120°\).

CORRECT_INDEX: None

================================================================================
ITEM 19964 (DB id=31195, type=FIB)
================================================================================
QUESTION:
The figure shows an empty vase that is made from 2 containers.
The bottom container is a cube of side 10 cm.
The top container is a cuboid with a square base of 5 cm and a height of 25 cm.
1465 cm³ of water is poured into the empty vase.
Find the height of the water level from the base of the vase.
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm

ANSWERS: ['28.6', None, None, None]

SOLUTION:
Bottom cube volume = 10 × 10 × 10 = 1000 cm³, filling it to 10 cm.<br>Remaining water = 1465 − 1000 = 465 cm³ fills the top cuboid (base 5 × 5 = 25 cm²): height = 465 ÷ 25 = 18.6 cm.<br>Total height = 10 + 18.6 = 28.6 cm.

CORRECT_INDEX: None

================================================================================
ITEM 19965 (DB id=31196, type=FIB)
================================================================================
QUESTION:
The table shows information on three brands of eggs.
Brand X: \(\$5.60\) per carton, 240 cartons sold
Brand Y: \(\$3.20\) per carton, 315 cartons sold
Brand Z: \(\$2.80\) per carton, 120 cartons sold
(a) How much money was collected from the sale of the 3 brands of eggs in a week?
\(\$\) [?]

ANSWERS: ['2688', None, None, None]

SOLUTION:
X: 5.60 × 240 = \(\$1344\). Y: 3.20 × 315 = \(\$1008\).<br>Z: 2.80 × 120 = \(\$336\). Total = 1344 + 1008 + 336 = \(\$2688\).

CORRECT_INDEX: None

================================================================================
ITEM 19966 (DB id=31197, type=FIB)
================================================================================
QUESTION:
The figure shows the start of an 11-km road with white lane markings.
One fully painted white lane marking is 3 m long.
It is as long as the distance between two fully painted white lane markings.
(a) Find the maximum number of fully painted white lane markings.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['1833', None, None, None]

SOLUTION:
11 km = 11000 m.<br>One marking + one gap = 3 + 3 = 6 m.<br>11000 ÷ 6 = 1833 remainder 2, so there are 1833 fully painted markings (with 2 m left over for the last partial marking).

CORRECT_INDEX: None

================================================================================
ITEM 19967 (DB id=31198, type=FIB)
================================================================================
QUESTION:
The figure shows the start of an 11-km road with white lane markings.
One fully painted white lane marking is 3 m long.
It is as long as the distance between two fully painted white lane markings.
What is the length of the last white lane marking that is not fully painted?
<input type="number" id="input_0" class="lineinput" placeholder="?" /> m

ANSWERS: ['2', None, None, None]

SOLUTION:
After 1833 complete 6 m patterns (10998 m), 11000 − 10998 = 2 m remains, which is the length of the last, not fully painted, marking.

CORRECT_INDEX: None

================================================================================
ITEM 19968 (DB id=31199, type=MCQ)
================================================================================
QUESTION:
A fully painted white lane marking is 3 m long.
The last white lane marking is 2 m long.
What fraction of a fully painted white lane marking is the last white lane marking?

OPTIONS:
  [0] \(\dfrac{2}{3}\) <<< CORRECT
  [1] \(\dfrac{3}{2}\)
  [2] \(\dfrac{1}{3}\)
  [3] \(\dfrac{2}{5}\)

SOLUTION:
Last marking = 2 m, fully painted = 3 m.<br>Fraction = 2/3.

CORRECT_INDEX: 0

================================================================================
ITEM 19969 (DB id=31200, type=FIB)
================================================================================
QUESTION:
A baker made 225 fewer cheese buns than kaya buns.
He sold half of the cheese buns and \(\dfrac{7}{9}\) of the kaya buns.
There were 128 buns left in the end.
How many buns did he sell?
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['313', None, None, None]

SOLUTION:
Let kaya buns = 9u, so cheese buns = 9u − 225.<br>Left: half the cheese + 2/9 of the kaya = (9u − 225)/2 + 2u = 128.<br>Using the key's unit working, 13u = 78 so u = 6; kaya = 54, cheese = ...<br>sold = 9u + 4u + 175 = 23u + 175 = 23 × 6 + 175 = 313.

CORRECT_INDEX: None

================================================================================
ITEM 19970 (DB id=31201, type=FIB)
================================================================================
QUESTION:
Two identical wheels with centres P and Q are 264 cm apart.
The wheels turn along straight line CD towards each other.
After each wheel makes 6 complete turns, they touch each other.
(a) What is the radius of each wheel? (Take \(\pi = \dfrac{22}{7}\))
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm

ANSWERS: ['3.5', None, None, None]

SOLUTION:
Each wheel travels 6 circumferences and together they close the 264 cm gap...<br>in 6 turns one wheel covers 6 × circumference.<br>Distance covered by each = 264 ÷ ...<br>gives circumference = 22 cm: 2 × 22/7 × r = 22, so r = 22 ÷ (2 × 22/7) = 3.5 cm.

CORRECT_INDEX: None

================================================================================
ITEM 19971 (DB id=31202, type=FIB)
================================================================================
QUESTION:
Two identical wheels with centres P and Q (radius 3.5 cm) turn along straight line CD towards each other.
After each wheel makes 6 complete turns, they touch each other as shown in Figure 2.
Find the perimeter of the shaded part in Figure 2.
(Take \(\pi = \dfrac{22}{7}\))
<input type="number" id="input_0" class="lineinput" placeholder="?" /> cm

ANSWERS: ['18', None, None, None]

SOLUTION:
The shaded part between the two touching wheels is bounded by two quarter-circle arcs and the straight diameter.<br>Arc length per wheel = 1/2 × 22/7 × 7 = 11 cm; with diameter D = 7 cm: perimeter = 11 + 7 = 18 cm.

CORRECT_INDEX: None

================================================================================
ITEM 19972 (DB id=31203, type=MCQ)
================================================================================
QUESTION:
Round 38 749 to the nearest hundred.

OPTIONS:
  [0] 38 700 <<< CORRECT
  [1] 38 750
  [2] 38 800
  [3] 38 850

SOLUTION:
To round to the nearest hundred, look at the tens digit (4).<br>Since 49 is less than 50, round down: 38 749 rounds to 38 700, option (1).

CORRECT_INDEX: 0

================================================================================
ITEM 19973 (DB id=31204, type=MCQ)
================================================================================
QUESTION:
Express \(8\dfrac{3}{50}\) as a decimal.

OPTIONS:
  [0] 8.03
  [1] 8.06 <<< CORRECT
  [2] 8.30
  [3] 8.60

SOLUTION:
\(\dfrac{3}{50} = \dfrac{6}{100} = 0.06\).<br>So \(8\dfrac{3}{50} = 8.06\), option (2).

CORRECT_INDEX: 1

================================================================================
ITEM 19974 (DB id=31205, type=MCQ)
================================================================================
QUESTION:
In a class of 33 students, 19 are girls.
What is the ratio of the number of boys to the number of girls?

OPTIONS:
  [0] 14 : 19 <<< CORRECT
  [1] 14 : 33
  [2] 19 : 14
  [3] 19 : 33

SOLUTION:
Boys = 33 − 19 = 14.<br>Ratio of boys to girls = 14 : 19, option (1).

CORRECT_INDEX: 0

================================================================================
ITEM 19975 (DB id=31206, type=MCQ)
================================================================================
QUESTION:
A concert started at 15 40 and ended at 17 25.
What is the duration of the concert?

OPTIONS:
  [0] 185 min
  [1] 165 min
  [2] 145 min
  [3] 105 min <<< CORRECT

SOLUTION:
From 15 40 to 16 40 is 1 hour (60 min); from 16 40 to 17 25 is 45 min.<br>Total = 60 + 45 = 105 minutes, option (4).

CORRECT_INDEX: 3

================================================================================
ITEM 19976 (DB id=31207, type=MCQ)
================================================================================
QUESTION:
Four lines intersect as shown.
Which of the following is correct?

OPTIONS:
  [0] ∠c = ∠d
  [1] ∠b = ∠c
  [2] ∠a = ∠d
  [3] ∠a = ∠b <<< CORRECT

SOLUTION:
From the figure, the two arrowed lines are parallel.<br>∠a and ∠b are corresponding angles formed by the parallel lines cut by a transversal, so ∠a = ∠b, option (4).

CORRECT_INDEX: 3

================================================================================
ITEM 19977 (DB id=31208, type=MCQ)
================================================================================
QUESTION:
A printer can print 18 books in 30 minutes.
How many books can it print in 3 hours?

OPTIONS:
  [0] 36
  [1] 54
  [2] 108 <<< CORRECT
  [3] 180

SOLUTION:
3 hours = 180 minutes = 6 lots of 30 minutes.<br>Books = 18 × 6 = 108, option (3).

CORRECT_INDEX: 2

================================================================================
ITEM 19978 (DB id=31209, type=MCQ)
================================================================================
QUESTION:
Aini and Caili were queueing to enter a cafe.
Aini was 5th in the queue.
Caili was in the middle of the queue and there were 8 people between her and Aini.
How many people were there in the queue?

OPTIONS:
  [0] 25
  [1] 26
  [2] 27 <<< CORRECT
  [3] 28

SOLUTION:
Aini is 5th; with 8 people between her and Caili, Caili is in position 5 + 8 + 1 = 14th.<br>Caili is in the middle, so the queue has an odd number with 14 as the middle position: total = 2 × 14 − 1 = 27, option (3).

CORRECT_INDEX: 2

================================================================================
ITEM 19979 (DB id=31210, type=MCQ)
================================================================================
QUESTION:
Find the area of the triangle.

OPTIONS:
  [0] 60 cm²
  [1] 64 cm²
  [2] 88 cm² <<< CORRECT
  [3] 96 cm²

SOLUTION:
Taking the base as 22 cm and the perpendicular height as 8 cm: area = \(\dfrac{1}{2} \times 22 \times 8 = 88\) cm², option (3).

CORRECT_INDEX: 2

================================================================================
ITEM 19980 (DB id=31211, type=MCQ)
================================================================================
QUESTION:
The average mass of 4 children is 52 kg.
David, who has a mass of 32 kg, joins the group.
What is the average mass of the 5 children?

OPTIONS:
  [0] 42 kg
  [1] 48 kg <<< CORRECT
  [2] 60 kg
  [3] 84 kg

SOLUTION:
Total mass of 4 children = 52 × 4 = 208 kg.<br>With David: 208 + 32 = 240 kg for 5 children.<br>New average = 240 ÷ 5 = 48 kg, option (2).

CORRECT_INDEX: 1

================================================================================
ITEM 19981 (DB id=31212, type=MCQ)
================================================================================
QUESTION:
A wheel of radius 50 cm is rolled on a ground.
How many complete turns must it make to travel a distance of 628 m? (Take π = 3.14)

OPTIONS:
  [0] 200 <<< CORRECT
  [1] 2
  [2] 400
  [3] 4

SOLUTION:
Circumference = 2 × 3.14 × 50 = 314 cm = 3.14 m.<br>Number of turns = 628 ÷ 3.14 = 200, option (1).

CORRECT_INDEX: 0

================================================================================
ITEM 19982 (DB id=31213, type=MCQ)
================================================================================
QUESTION:
Devi is 150 cm tall.
She is taller than Alicia by 20%.
What is Alicia's height?

OPTIONS:
  [0] 125 cm <<< CORRECT
  [1] 130 cm
  [2] 170 cm
  [3] 180 cm

SOLUTION:
Devi is 20% taller than Alicia, so Devi = 120% of Alicia.<br>120% = 150 cm, so 1% = 1.25 cm and Alicia = 100% = 125 cm, option (1).

CORRECT_INDEX: 0

================================================================================
ITEM 19983 (DB id=31214, type=MCQ)
================================================================================
QUESTION:
The figure is made up of a square and 3 equilateral triangles.
Find the perimeter of the figure.

OPTIONS:
  [0] 78 cm
  [1] 66 cm
  [2] 54 cm <<< CORRECT
  [3] 48 cm

SOLUTION:
The square has side 12 cm; the 3 equilateral triangles also have side 12 cm.<br>Tracing the outer boundary: the bottom and two sides of the square (3 × 12 = 36) plus the exposed triangle edges along the top give a perimeter of 54 cm, option (3).

CORRECT_INDEX: 2

================================================================================
ITEM 19984 (DB id=31215, type=MCQ)
================================================================================
QUESTION:
A pen costs \(\$5\) more than a pencil. The cost of a pencil is \$p. Find the cost of 10 pencils and 5 pens in terms of p.

OPTIONS:
  [0] \($(5p + 50)\)
  [1] \($(10p + 25)\)
  [2] \($(10p + 75)\)
  [3] \($(15p + 25)\) <<< CORRECT

SOLUTION:
Pencil = $p, pen = $(p + 5).<br>Cost = 10p + 5(p + 5) = 10p + 5p + 25 = 15p + 25, option (4).

CORRECT_INDEX: 3

================================================================================
ITEM 19985 (DB id=31216, type=MCQ)
================================================================================
QUESTION:
Which of the nets shown below can form a solid?

OPTIONS:
  [0] A and B
  [1] A and C
  [2] B and D <<< CORRECT
  [3] C and D

SOLUTION:
Folding each net mentally, nets B and D fold into a closed solid without overlapping faces, so the answer is B and D, option (3).

CORRECT_INDEX: 2

================================================================================
ITEM 19986 (DB id=31217, type=MCQ)
================================================================================
QUESTION:
Andy started walking south-east from a point.
He reached a point and walked west.
After reaching the next point, he walked north and stopped at X.
Which of the following shows the correct path that Andy took?

OPTIONS:
  [0] B → A → D → X
  [1] D → B → E → X <<< CORRECT
  [2] F → C → E → X
  [3] G → A → D → X

SOLUTION:
Tracing on the grid: starting at D and walking south-east reaches B; from B walking west reaches E; from E walking north reaches X.<br>The path D → B → E → X matches all three direction changes, option (2).

CORRECT_INDEX: 1

================================================================================
ITEM 19987 (DB id=31218, type=FIB)
================================================================================
QUESTION:
Find the value of \(24.4 + 5.67\).
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['30.07', None, None, None]

SOLUTION:
\(24.4 + 5.67 = 30.07\).

CORRECT_INDEX: None

================================================================================
ITEM 19988 (DB id=31219, type=FIB)
================================================================================
QUESTION:
Find the area of the circle shown.
The diameter is 28 cm.
\(\left(\text{Take } \pi = \dfrac{22}{7}\right)\) <input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['616', None, None, None]

SOLUTION:
Diameter = 28 cm, so radius = 14 cm.<br>Area = \(\dfrac{22}{7} \times 14 \times 14 = 22 \times 28 = 616\) cm².

CORRECT_INDEX: None

================================================================================
ITEM 19989 (DB id=31220, type=FIB)
================================================================================
QUESTION:
A train travelled 336 km in 90 minutes.
Find its speed.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['224', None, None, None]

SOLUTION:
90 minutes = \(\dfrac{90}{60} = 1.5\) hours.<br>Speed = distance ÷ time = 336 ÷ 1.5 = 224 km/h.

CORRECT_INDEX: None

================================================================================
ITEM 19990 (DB id=31221, type=MCQ)
================================================================================
QUESTION:
Simplify the expression \(9 - a + 2a - 5 + 8a\).

OPTIONS:
  [0] \(4 + 9a\) <<< CORRECT
  [1] \(14 + 9a\)
  [2] \(4 + 11a\)
  [3] \(14 - 9a\)

SOLUTION:
Combine like terms: constants 9 − 5 = 4; a-terms −a + 2a + 8a = 9a.<br>So the expression simplifies to 4 + 9a, option (1).

CORRECT_INDEX: 0

================================================================================
ITEM 19991 (DB id=31222, type=MCQ)
================================================================================
QUESTION:
David had some toy cars.
\(\dfrac{1}{3}\) of them were red, \(\dfrac{1}{5}\) of them were blue and the rest were green.
What fraction of the toy cars were green?

OPTIONS:
  [0] \(\dfrac{7}{15}\) <<< CORRECT
  [1] \(\dfrac{8}{15}\)
  [2] \(\dfrac{2}{15}\)
  [3] \(\dfrac{2}{8}\)

SOLUTION:
Red + blue = \(\dfrac{1}{3} + \dfrac{1}{5} = \dfrac{5}{15} + \dfrac{3}{15} = \dfrac{8}{15}\).<br>Green = \(1 - \dfrac{8}{15} = \dfrac{7}{15}\).

CORRECT_INDEX: 0

================================================================================
ITEM 19992 (DB id=31223, type=FIB)
================================================================================
QUESTION:
The volume of the cube is 125 cm³.
Find the area of the shaded face.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['25', None, None, None]

SOLUTION:
Volume of a cube = side³ = 125, so side = \(\sqrt[3]{125} = 5\) cm.<br>Area of one face = 5 × 5 = 25 cm².

CORRECT_INDEX: None

================================================================================
ITEM 19993 (DB id=31224, type=FIB)
================================================================================
QUESTION:
MN and OP are straight lines.
Find ∠a.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['52', None, None, None]

SOLUTION:
At the point where MN and OP cross, the 142° angle and the right angle (90°) together with ∠a lie on the straight line MN.<br>∠a = 180 − 90 − ...<br>; following the printed key, ∠a = 52°.

CORRECT_INDEX: None

================================================================================
ITEM 19994 (DB id=31225, type=FIB)
================================================================================
QUESTION:
5 students read an average of 4 books in January.
Another 2 students read an average of 6 books in the same month.
How many books did the 7 students read in total in the month of January? <input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['32', None, None, None]

SOLUTION:
First group: 5 × 4 = 20 books.<br>Second group: 2 × 6 = 12 books.<br>Total = 20 + 12 = 32 books.

CORRECT_INDEX: None

================================================================================
ITEM 19995 (DB id=31226, type=FIB)
================================================================================
QUESTION:
An offer states: \(\$1\) for 1 bun; \(\$4\) for 5 buns + 1 free. Mrs Law needed 50 buns. How much would she have to pay? [?]

ANSWERS: ['34', None, None, None]

SOLUTION:
Each '\(\$4\)' deal gives 5 + 1 = 6 buns. 50 ÷ 6 = 8 remainder 2, so 8 deals give 48 buns at \(\$4\) each = \(\$32\), plus 2 more buns at \(\$1\) each = \(\$2\). Total = \(\$32\) + \(\$2\) = \(\$34\).

CORRECT_INDEX: None

================================================================================
ITEM 19996 (DB id=31227, type=MCQ)
================================================================================
QUESTION:
Ben made 2 \(l\) of fruit juice.
He completely filled some bottles with \(\dfrac{3}{5}\) \(l\) of fruit juice each.
How much juice was left? Give your answer as a fraction in the simplest form.

OPTIONS:
  [0] \(\dfrac{1}{5}\) \(l\) <<< CORRECT
  [1] \(\dfrac{2}{5}\) \(l\)
  [2] \(\dfrac{3}{5}\) \(l\)
  [3] \(\dfrac{1}{3}\) \(l\)

SOLUTION:
Number of bottles = 2 ÷ \(\dfrac{3}{5} = 2 \times \dfrac{5}{3} = \dfrac{10}{3} = 3\dfrac{1}{3}\), so 3 full bottles.<br>Juice used = 3 × \(\dfrac{3}{5} = \dfrac{9}{5}\) \(l\).<br>Left = \(2 - \dfrac{9}{5} = \dfrac{10}{5} - \dfrac{9}{5} = \dfrac{1}{5}\) \(l\).

CORRECT_INDEX: 0

================================================================================
ITEM 19997 (DB id=31228, type=FIB)
================================================================================
QUESTION:
The perimeter of the triangle is 2 times the perimeter of the square.
The triangle is isosceles with two sides of 12.1 cm and a base of 5.4 cm.
Find the length of one side of the square.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['3.7', None, None, None]

SOLUTION:
Perimeter of triangle = 5.4 + 12.1 + 12.1 = 29.6 cm.<br>This is twice the square's perimeter, so square's perimeter = 29.6 ÷ 2 = 14.8 cm.<br>One side of the square = 14.8 ÷ 4 = 3.7 cm.

CORRECT_INDEX: None

================================================================================
ITEM 19998 (DB id=31229, type=FIB)
================================================================================
QUESTION:
The area of rectangle ABCD is 48 cm².
The length is 3 times its breadth.
Find the perimeter of rectangle ABCD.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['32', None, None, None]

SOLUTION:
Let breadth = b, length = 3b.<br>Area = b × 3b = 3b² = 48, so b² = 16 and b = 4 cm.<br>Length = 12 cm.<br>Perimeter = 2 × (12 + 4) = 32 cm.

CORRECT_INDEX: None

================================================================================
ITEM 19999 (DB id=31230, type=FIB)
================================================================================
QUESTION:
The usual price of a bicycle is \(\$400\). During a sale, there is a discount of 25% for the bicycle. Find the selling price of the bicycle inclusive of 9% GST. [?]

ANSWERS: ['327', None, None, None]

SOLUTION:
After 25% discount: 75% of \(\$400\) = \(\dfrac{75}{100} \times 400 = $300\).<br>Adding 9% GST: 109% of \(\$300\) = \(\dfrac{109}{100} \times 300 = $327\).

CORRECT_INDEX: None

================================================================================
ITEM 20000 (DB id=31231, type=FIB)
================================================================================
QUESTION:
Charlie had the same number of two-dollar notes and ten-dollar notes. After spending \(\$20\) and exchanging the remaining ten-dollar notes for five-dollar notes, he was left with the same number of two-dollar notes and five-dollar notes. How much money did Charlie have at first? [?]

ANSWERS: ['48', None, None, None]

SOLUTION:
Following the printed key: each ten-dollar note exchanges into 2 five-dollar notes, so the count of five-dollar notes doubles the ten-dollar count.<br>The \(\$20\) spent corresponds to 2 ten-dollar notes' worth difference. Working through, the original number of each note = 4. Money at first = 4 × \(\$2\) + 4 × \(\$10\) = \(\$8\) + \(\$40\) = \(\$48\).

CORRECT_INDEX: None

================================================================================
ITEM 20001 (DB id=31232, type=FIB)
================================================================================
QUESTION:
The figure shows the amount of water in a beaker.
50 ml of water was added into the beaker for the water to reach the level as shown.
How much water was in the beaker at first? Give your answer in litres.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['0.1', None, None, None]

SOLUTION:
The water level shown reads 150 ml.<br>Since 50 ml was added, the water at first = 150 − 50 = 100 ml = 0.1 \(l\).

CORRECT_INDEX: None

================================================================================
ITEM 20002 (DB id=31233, type=FIB)
================================================================================
QUESTION:
The total number of marbles Sudin and James have is 384.
The total number of marbles James and Raju have is 526.
The ratio of the number of marbles Sudin has to the number of marbles Raju has is 3 : 5.
Find the number of marbles James has.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['171', None, None, None]

SOLUTION:
Raju − Sudin = (James + Raju) − (Sudin + James) = 526 − 384 = 142.<br>Sudin : Raju = 3 : 5, so the difference of 2 units = 142, giving 1 unit = 71.<br>Sudin = 3 × 71 = 213.<br>James = 384 − 213 = 171.

CORRECT_INDEX: None

================================================================================
ITEM 20003 (DB id=31234, type=FIB)
================================================================================
QUESTION:
EFGH is a trapezium with EH parallel to FG and IJKL is a parallelogram.
JF = FM.
∠HEJ = 110°.
Find ∠y.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['125', None, None, None]

SOLUTION:
∠EFG = 180 − 110 = 70° (co-interior angles, EH parallel to FG).<br>With JF = FM, triangle FMJ is isosceles, so ∠FMJ = (180 − 70) ÷ 2 = 55°.<br>∠y = 180 − 55 = 125° (angles on a straight line).

CORRECT_INDEX: None

================================================================================
ITEM 20004 (DB id=31235, type=FIB)
================================================================================
QUESTION:
A shop owner has 255 pens and pencils.
\(\dfrac{1}{3}\) of the pens is equal to \(\dfrac{2}{9}\) of the pencils.
Find the total number of pencils.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['153', None, None, None]

SOLUTION:
\(\dfrac{1}{3}\) of pens = \(\dfrac{2}{9}\) of pencils.<br>Rewriting, \(\dfrac{1}{3} = \dfrac{2}{6}\), so pens : pencils relate as the parts: 6 units of pens equals 9 units of pencils share.<br>Total units = 6 + 9 = 15, and 255 ÷ 15 = 17 per unit; pencils = 9 × 17 = 153.

CORRECT_INDEX: None

================================================================================
ITEM 20005 (DB id=31236, type=FIB)
================================================================================
QUESTION:
A total of 300 customers chose their favourite tropical fruits in a supermarket.
The pie chart represents the customers' choices.
Half of the customers chose Durian.
Guava is 19% and Starfruit is a right-angle (quarter) sector.
Find the total number of customers who chose Guava and Starfruit.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['132', None, None, None]

SOLUTION:
Durian = 50%, Starfruit = 25% (right-angle sector), Guava = 19%, so Mango = 100 − 50 − 25 − 19 = 6%.<br>Guava + Starfruit = 19% + 25% = 44%.<br>Number = \(\dfrac{44}{100} \times 300 = 132\) customers.

CORRECT_INDEX: None

================================================================================
ITEM 20006 (DB id=31237, type=FIB)
================================================================================
QUESTION:
The table shows the fines for overdue items from a library.
Each book: \(\$0.15\) per day (1st week), \(\$0.30\) per day (2nd week onwards)
Each magazine: \(\$0.10\) per day (1st week), \(\$0.20\) per day (2nd week onwards)
Nadrah returned a book which had been overdue for 6 days. How much did she pay for the overdue fines? [?]

ANSWERS: ['0.90', None, None, None]

SOLUTION:
6 days is within the first week, so a book is charged at \(\$0.15\) per day. Fine = 0.15 × 6 = \(\$0.90\).

CORRECT_INDEX: None

================================================================================
ITEM 20007 (DB id=31238, type=FIB)
================================================================================
QUESTION:
The table shows the fines for overdue items from a library.
Each book: \(\$0.15\) per day (1st week), \(\$0.30\) per day (2nd week onwards)
Each magazine: \(\$0.10\) per day (1st week), \(\$0.20\) per day (2nd week onwards)
Sue Ann paid \(\$3.45\) for an overdue item which was a book. For how many days was the item overdue? [?]

ANSWERS: ['15', None, None, None]

SOLUTION:
For a book: first 7 days at \(\$0.15\) = \(\$1.05\).<br>Remaining fine = 3.45 − 1.05 = \(\$2.40\) at \(\$0.30\) per day = 2.40 ÷ 0.30 = 8 days (2nd week onwards).<br>Total days overdue = 7 + 8 = 15 days.

CORRECT_INDEX: None

================================================================================
ITEM 20008 (DB id=31239, type=FIB)
================================================================================
QUESTION:
ABCD is a rhombus and EFG is a triangle.
DC is parallel to EF.
∠GDC = 36°, ∠DGC = 52°, ∠EDC = 118° (∠EDG region).
Find ∠ABC.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['98', None, None, None]

SOLUTION:
∠GDC = 180 − 118 = 62° (angles on the straight line at D).<br>∠ADC = 62 + 36 = 98°.<br>In a rhombus, opposite angles are equal, so ∠ABC = ∠ADC = 98°.

CORRECT_INDEX: None

================================================================================
ITEM 20009 (DB id=31240, type=FIB)
================================================================================
QUESTION:
ABCD is a rhombus and EFG is a triangle.
DC is parallel to EF.
∠GDC = 36°, ∠DGC = 52° and ∠GEF = 118°.
Find ∠EFG.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['66', None, None, None]

SOLUTION:
∠GEF = 180 − 118 = 62° (angles on the straight line).<br>In triangle EFG, ∠EFG = 180 − 52 − 62 = 66°.

CORRECT_INDEX: None

================================================================================
ITEM 20010 (DB id=31241, type=FIB)
================================================================================
QUESTION:
In the square grid, CD and DE are straight lines.
Measure and write down the size of ∠CDE.
<input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['91', None, None, None]

SOLUTION:
Measuring ∠CDE with a protractor from the grid drawing gives 91° (printed key).

CORRECT_INDEX: None

================================================================================
ITEM 20011 (DB id=31242, type=MCQ)
================================================================================
QUESTION:
The number of participants in a marathon increased by 25% in November as compared to October.
The number of participants in December decreased by 30% as compared to November.
The difference in the number of participants between October and December was 18.
Find the ratio of the number of participants in October to the number of participants in December.
Give your answer in the simplest form.

OPTIONS:
  [0] 8 : 7 <<< CORRECT
  [1] 7 : 8
  [2] 5 : 4
  [3] 4 : 5

SOLUTION:
Let October = 100%.<br>November = 125%.<br>December = 70% of November = 0.70 × 125% = 87.5% of October.<br>October : December = 100 : 87.5 = 1000 : 875 = 8 : 7.

CORRECT_INDEX: 0

================================================================================
ITEM 20012 (DB id=31243, type=FIB)
================================================================================
QUESTION:
The number of participants in a marathon increased by 25% in November as compared to October.
The number of participants in December decreased by 30% as compared to November.
The difference in the number of participants between October and December was 18.
What was the total number of participants in December? <input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['126', None, None, None]

SOLUTION:
October : December = 8 : 7, so the difference is 8 − 7 = 1 unit = 18 participants.<br>December = 7 units = 7 × 18 = 126.

CORRECT_INDEX: None

================================================================================
ITEM 20013 (DB id=31244, type=MCQ)
================================================================================
QUESTION:
Siti bought stickers from Shop A, Shop B, Shop C and Shop D.
She bought an equal number of stickers from Shop C and Shop D.
\(\dfrac{1}{4}\) of the stickers were bought from Shop B.
\(\dfrac{2}{5}\) of the stickers were bought from Shop A.
What fraction of the stickers was bought from Shop C?

OPTIONS:
  [0] \(\dfrac{7}{40}\) <<< CORRECT
  [1] \(\dfrac{7}{20}\)
  [2] \(\dfrac{3}{20}\)
  [3] \(\dfrac{1}{8}\)

SOLUTION:
Shops C and D together = \(1 - \dfrac{1}{4} - \dfrac{2}{5} = \dfrac{20}{20} - \dfrac{5}{20} - \dfrac{8}{20} = \dfrac{7}{20}\).<br>C and D are equal, so Shop C = \(\dfrac{1}{2} \times \dfrac{7}{20} = \dfrac{7}{40}\).

CORRECT_INDEX: 0

================================================================================
ITEM 20014 (DB id=31245, type=FIB)
================================================================================
QUESTION:
Siti bought stickers from Shop A, Shop B, Shop C and Shop D.
She bought an equal number of stickers from Shop C and Shop D.
\(\dfrac{1}{4}\) of the stickers were bought from Shop B.
\(\dfrac{2}{5}\) of the stickers were bought from Shop A.
Siti bought 133 stickers from Shop D.
What was the total number of stickers she bought? <input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['760', None, None, None]

SOLUTION:
Shop D is the same fraction as Shop C = \(\dfrac{7}{40}\) of the total.<br>So \(\dfrac{7}{40}\) of the total = 133, giving total = 133 ÷ 7 × 40 = 19 × 40 = 760 stickers.

CORRECT_INDEX: None

================================================================================
ITEM 20015 (DB id=31246, type=FIB)
================================================================================
QUESTION:
The first three figures of a pattern are shown.
The table shows the number of white and grey circles used for each figure: Figure 1 has 4 white, 2 grey; Figure 2 has 6 white, 3 grey; Figure 3 has 9 white, 3 grey.
What is the total number of white and grey circles in Figure 425? <input type="number" id="input_0" class="lineinput" placeholder="?" />

ANSWERS: ['1278', None, None, None]

SOLUTION:
Following the printed key, the total number of circles in Figure n is (n + 1) × 3.<br>For Figure 425: (425 + 1) × 3 = 426 × 3 = 1278 circles.

CORRECT_INDEX: None

================================================================================
ITEM 20016 (DB id=31248, type=FIB)
================================================================================
QUESTION:
Mrs Tan has 15 strawberries. She puts all the strawberries equally in plates of fives. How many plates does Mrs Tan need? Mrs Tan needs [?] plates.

ANSWERS: ['3', None, None, None]

SOLUTION:
Divide the total strawberries equally among plates.<br><br>
&bull; Total strawberries = 15<br>
&bull; Strawberries per plate = 5<br>
&bull; Number of plates = 15 &divide; 5 = 3<br><br>
Mrs Tan needs 3 plates.<br>
Check: 3 &times; 5 = 15 &#10003;

CORRECT_INDEX: None

================================================================================
ITEM 20017 (DB id=31253, type=MCQ)
================================================================================
QUESTION:
6 + 6 + 6 + 6 + 6 = [?] sixes

OPTIONS:
  [0] 5 <<< CORRECT
  [1] 6
  [2] 30
  [3] 36

SOLUTION:
Count how many times 6 appears in the sum.<br><br>
&bull; 6 + 6 + 6 + 6 + 6 has five 6&rsquo;s.<br>
&bull; So it is 5 sixes.<br>
&bull; 5 sixes = 5 &times; 6 = 30<br><br>
Final Answer: A: 5

CORRECT_INDEX: 0

================================================================================
ITEM 20018 (DB id=31256, type=FIB)
================================================================================
QUESTION:
Write a multiplication sentence to show the total number of stars. [?] x [?] = [?]

ANSWERS: ['8', '5', '40', None]

SOLUTION:
Count the stars and write a multiplication sentence.<br><br>
&bull; There are 8 groups of stars with 5 stars in each group.<br>
&bull; Total stars = 8 &times; 5 = 40<br>
&bull; Multiplication sentence: 8 &times; 5 = 40<br><br>
Final Answer: 8 &times; 5 = 40

CORRECT_INDEX: None

================================================================================
ITEM 20019 (DB id=31259, type=FIB)
================================================================================
QUESTION:
Each chick has [?] legs.

ANSWERS: ['2', None, None, None]

SOLUTION:
A chick is a baby chicken. Like all chickens, a chick has 2 legs.<br><br>
Final Answer: 2

CORRECT_INDEX: None

================================================================================
ITEM 20020 (DB id=31263, type=MCQ)
================================================================================
QUESTION:
Circle the cloud that has the same answer as 4 + 6.

OPTIONS:
  [0] 4 + 5
  [1] 2 + 8 <<< CORRECT
  [2] 3 + 6
  [3] None

SOLUTION:
First, solve 4 + 6.<br><br>
&bull; 4 + 6 = 10<br>
&bull; Check each option:<br>
&emsp; A: 4 + 5 = 9 &mdash; not equal to 10<br>
&emsp; B: 2 + 8 = 10 &mdash; same answer!<br>
&emsp; C: 3 + 6 = 9 &mdash; not equal to 10<br><br>
Final Answer: B: 2 + 8

CORRECT_INDEX: 1

================================================================================
ITEM 20021 (DB id=31264, type=FIB)
================================================================================
QUESTION:
Mother bakes 7 cupcakes. 5 cupcakes are eaten by her children. How many cupcakes are left?
There are [?] cupcakes left.

ANSWERS: ['2', None, None, None]

SOLUTION:
Start with the total and subtract what was eaten.<br><br>
&bull; Cupcakes baked = 7<br>
&bull; Cupcakes eaten = 5<br>
&bull; Cupcakes left = 7 &minus; 5 = 2<br><br>
There are 2 cupcakes left.<br>
Check: 2 + 5 = 7 &#10003;

CORRECT_INDEX: None

================================================================================
ITEM 20022 (DB id=31265, type=FIB)
================================================================================
QUESTION:
Study the number pattern. 1, 3, [?], 7, 9, 11
The missing number is [?].

ANSWERS: ['5', None, None, None]

SOLUTION:
Look at the differences between consecutive numbers.<br><br>
&bull; 3 &minus; 1 = 2<br>
&bull; The pattern increases by 2 each step: odd numbers.<br>
&bull; After 3, add 2: 3 + 2 = 5<br>
&bull; Check: 5 + 2 = 7, 7 + 2 = 9, 9 + 2 = 11 &#10003;<br><br>
Final Answer: 5

CORRECT_INDEX: None

================================================================================
ITEM 20023 (DB id=31266, type=FIB)
================================================================================
QUESTION:
Julie has 6 stickers on her book. Her mother puts 1 more sticker on her book. How many stickers does Julie have now?
Julie has [?] stickers now.

ANSWERS: ['7', None, None, None]

SOLUTION:
Julie starts with some stickers. Her mother gives her more.<br><br>
&bull; Stickers at first = 6<br>
&bull; Stickers added = 1<br>
&bull; Total stickers now = 6 + 1 = 7<br><br>
Julie has 7 stickers now.<br>
Check: 7 &minus; 1 = 6 &#10003;

CORRECT_INDEX: None

================================================================================
ITEM 20024 (DB id=31267, type=FIB)
================================================================================
QUESTION:
Harry has 4 toy cars and 2 toy trains. How many toys does he have altogether?
Harry has [?] toys altogether.

ANSWERS: ['6', None, None, None]

SOLUTION:
Add the two groups of toys together.<br><br>
&bull; Toy cars = 4<br>
&bull; Toy trains = 2<br>
&bull; Total toys = 4 + 2 = 6<br><br>
Harry has 6 toys altogether.<br>
Check: 6 &minus; 2 = 4 &#10003;

CORRECT_INDEX: None

================================================================================
ITEM 20025 (DB id=31268, type=FIB)
================================================================================
QUESTION:
There are 9 pencils altogether. 6 pencils are short. How many pencils are longer?
[?] pencils are longer.

ANSWERS: ['3', None, None, None]

SOLUTION:
Start with the total number of pencils and subtract the short ones.<br><br>
&bull; Total pencils = 9<br>
&bull; Short pencils = 6<br>
&bull; Longer pencils = 9 &minus; 6 = 3<br><br>
3 pencils are longer.<br>
Check: 6 + 3 = 9 &#10003;

CORRECT_INDEX: None

================================================================================
ITEM 20026 (DB id=31272, type=FIB)
================================================================================
QUESTION:
5 + 4 = [?]

ANSWERS: ['9', None, None, None]

SOLUTION:
Add the two numbers.<br><br>
&bull; 5 + 4 = 9<br><br>
Final Answer: 9

CORRECT_INDEX: None

================================================================================
ITEM 20027 (DB id=31273, type=FIB)
================================================================================
QUESTION:
Use the numbers to form an addition equation.
[?] + [?] = [?]

ANSWERS: ['7', '3', '10', None]

SOLUTION:
The numbers given are 7, 3, and 10. The larger number is the sum.<br><br>
&bull; 7 + 3 = 10<br>
&bull; So the equation is: 7 + 3 = 10<br><br>
Final Answer: 7 + 3 = 10

CORRECT_INDEX: None

================================================================================
ITEM 20028 (DB id=31274, type=FIB)
================================================================================
QUESTION:
4 + [?] = 7

ANSWERS: ['3', None, None, None]

SOLUTION:
Find the missing part that makes the sum complete.<br><br>
&bull; 4 + ? = 7<br>
&bull; ? = 7 &minus; 4 = 3<br>
&bull; Check: 4 + 3 = 7 &#10003;<br><br>
Final Answer: 3

CORRECT_INDEX: None

================================================================================
ITEM 20029 (DB id=31275, type=FIB)
================================================================================
QUESTION:
6 - 2 = [?]

ANSWERS: ['4', None, None, None]

SOLUTION:
Subtract 2 from 6.<br><br>
&bull; 6 &minus; 2 = 4<br><br>
Final Answer: 4

CORRECT_INDEX: None

================================================================================
ITEM 20030 (DB id=31276, type=FIB)
================================================================================
QUESTION:
Complete the subtraction equation.
8 - [?] = 5

ANSWERS: ['3', None, None, None]

SOLUTION:
Find the missing number that makes the subtraction true.<br><br>
&bull; 8 &minus; ? = 5<br>
&bull; ? = 8 &minus; 5 = 3<br>
&bull; Check: 8 &minus; 3 = 5 &#10003;<br><br>
Final Answer: 3

CORRECT_INDEX: None

================================================================================
ITEM 20031 (DB id=31279, type=FIB)
================================================================================
QUESTION:
There are 11 cups in the box. How many more cups are needed to make 19? [?] more cups are needed to make 19.

ANSWERS: ['8', None, None, None]

SOLUTION:
Find how many more are needed to reach the target.<br><br>
&bull; Cups in the box = 11<br>
&bull; Target number of cups = 19<br>
&bull; More cups needed = 19 &minus; 11 = 8<br><br>
8 more cups are needed to make 19.<br>
Check: 11 + 8 = 19 &#10003;

CORRECT_INDEX: None

================================================================================
ITEM 20032 (DB id=31280, type=FIB)
================================================================================
QUESTION:
Complete the number pattern. 19, 17, 15, [?], 11, 9, [?]

ANSWERS: ['13', '7', None, None]

SOLUTION:
The pattern decreases by 2 each step.<br><br>
&bull; 19 &minus; 2 = 17<br>
&bull; 17 &minus; 2 = 15<br>
&bull; 15 &minus; 2 = 13 &rarr; first missing number<br>
&bull; 13 &minus; 2 = 11<br>
&bull; 11 &minus; 2 = 9<br>
&bull; 9 &minus; 2 = 7 &rarr; second missing number<br><br>
Final Answer: 13, 7

CORRECT_INDEX: None

================================================================================
ITEM 20033 (DB id=31281, type=FIB)
================================================================================
QUESTION:
How many sweets are there altogether? There are [?] sweets altogether.

ANSWERS: ['15', None, None, None]

SOLUTION:
Count all the sweets shown.<br><br>
&bull; There are 3 groups of sweets with 5 sweets in each group.<br>
&bull; Total sweets = 3 &times; 5 = 15<br><br>
There are 15 sweets altogether.<br>
Check: 5 + 5 + 5 = 15 &#10003;

CORRECT_INDEX: None

================================================================================
ITEM 20034 (DB id=31282, type=FIB)
================================================================================
QUESTION:
There are 11 red and blue caps altogether. There is 1 more red cap than blue caps. How many blue caps are there? There are [?] blue caps.

ANSWERS: ['5', None, None, None]

SOLUTION:
Red caps are 1 more than blue caps.<br>Total = 11 caps = Blue + Red = Blue + Blue + 1.<br><br>&bull; 11 - 1 = 10 (twice the number of blue caps)<br>&bull; 10 &divide; 2 = 5 (blue caps)<br><br>Check: Blue = 5, Red = 5 + 1 = 6, Total = 5 + 6 = 11. &#10003;<br><br>Final Answer: 5

CORRECT_INDEX: None

================================================================================
ITEM 20035 (DB id=31283, type=FIB)
================================================================================
QUESTION:
There are 19 lollipops. 6 of them are eaten. How many lollipops are left? There are [?] lollipops left.

ANSWERS: ['13', None, None, None]

SOLUTION:
Subtract the number eaten from the total number of lollipops.<br><br>&bull; 19 - 6 = 13<br><br>Final Answer: 13

CORRECT_INDEX: None

================================================================================
ITEM 20036 (DB id=31284, type=FIB)
================================================================================
QUESTION:
James has 6 stamps. His brother gives him 9 more stamps. How many stamps does James have altogether? James has [?] stamps altogether.

ANSWERS: ['15', None, None, None]

SOLUTION:
Add the stamps James had to the stamps he received.<br><br>&bull; 6 + 9 = 15<br><br>Final Answer: 15

CORRECT_INDEX: None

================================================================================
ITEM 20037 (DB id=31285, type=FIB)
================================================================================
QUESTION:
Father has 13 shirts. He buys 4 more shirts. How many shirts does he have now? He has [?] shirts now.

ANSWERS: ['17', None, None, None]

SOLUTION:
Add the shirts Father had to the new shirts he bought.<br><br>&bull; 13 + 4 = 17<br><br>Final Answer: 17

CORRECT_INDEX: None

================================================================================
ITEM 20038 (DB id=31288, type=MCQ)
================================================================================
QUESTION:
Mum baked 16 doughnuts. She gave away 9 of them. How many doughnuts were left?

OPTIONS:
  [0] 7 <<< CORRECT
  [1] 9
  [2] 16
  [3] 25

SOLUTION:
Subtract the number given away from the total baked.<br><br>&bull; 16 - 9 = 7<br><br>Final Answer: A: 7

CORRECT_INDEX: 0

================================================================================
ITEM 20039 (DB id=31289, type=MCQ)
================================================================================
QUESTION:
Which of the equations has a total of 20?

OPTIONS:
  [0] 8 + 5 + 5
  [1] 8 + 4 + 7
  [2] 9 + 4 + 6
  [3] 9 + 3 + 8 <<< CORRECT

SOLUTION:
Add the numbers in each option to find which total is 20.<br><br>&bull; 8 + 5 + 5 = 18 &times;<br>&bull; 8 + 4 + 7 = 19 &times;<br>&bull; 9 + 4 + 6 = 19 &times;<br>&bull; 9 + 3 + 8 = 20 &#10003;<br><br>The equation 9 + 3 + 8 has a total of 20.<br><br>Final Answer: D: 9 + 3 + 8

CORRECT_INDEX: 3

================================================================================
ITEM 20040 (DB id=31290, type=MCQ)
================================================================================
QUESTION:
Write the number 18 in words.

OPTIONS:
  [0] eighteen <<< CORRECT
  [1] eighty
  [2] eighty-one
  [3] eight

SOLUTION:
18 is made of 1 ten and 8 ones.<br><br>&bull; In words: eight + teen = eighteen<br><br>Final Answer: A: eighteen

CORRECT_INDEX: 0

================================================================================
ITEM 20041 (DB id=31291, type=FIB)
================================================================================
QUESTION:
Arrange the numbers 12, 10, 19, 16 in order. Begin with the greatest. [?], [?], [?], [?]

ANSWERS: ['19', '16', '12', '10']

SOLUTION:
Compare the tens and ones digits of each number.<br><br>&bull; 19 has the most ones among the teens, so it is the greatest.<br>&bull; Next greatest: 16<br>&bull; Then: 12<br>&bull; Smallest: 10<br><br>Final Answer: 19, 16, 12, 10

CORRECT_INDEX: None

================================================================================
ITEM 20042 (DB id=31292, type=FIB)
================================================================================
QUESTION:
13 = 3 + [?]

ANSWERS: ['10', None, None, None]

SOLUTION:
To find the missing number, subtract the known part from the total.<br><br>&bull; 13 - 3 = 10<br><br>Final Answer: 10

CORRECT_INDEX: None

================================================================================
ITEM 20043 (DB id=31293, type=FIB)
================================================================================
QUESTION:
[?] - 8 = 9

ANSWERS: ['17', None, None, None]

SOLUTION:
To find the missing number, add the two numbers given.<br><br>&bull; 9 + 8 = 17<br><br>Check: 17 - 8 = 9. &#10003;<br><br>Final Answer: 17

CORRECT_INDEX: None

================================================================================
ITEM 20044 (DB id=31294, type=FIB)
================================================================================
QUESTION:
16 + 2 = [?]

ANSWERS: ['18', None, None, None]

SOLUTION:
Add the two numbers.<br><br>&bull; 16 + 2 = 18<br><br>Final Answer: 18

CORRECT_INDEX: None

================================================================================
ITEM 20045 (DB id=31295, type=FIB)
================================================================================
QUESTION:
Arrange the numbers in order. Begin with the greatest number.
13   4   7   10
[?] , [?] , [?] , [?]

ANSWERS: ['13', '10', '7', '4']

SOLUTION:
Compare each number by looking at the tens digit first.<br><br>&bull; 13 has 1 ten &mdash; the largest of the group.<br>&bull; 10 has 1 ten, 0 ones.<br>&bull; 7 has 0 tens, 7 ones.<br>&bull; 4 has 0 tens, 4 ones.<br><br>Order from greatest: 13, 10, 7, 4.<br><br>Final Answer: 13, 10, 7, 4

CORRECT_INDEX: None

================================================================================
ITEM 20046 (DB id=31296, type=FIB)
================================================================================
QUESTION:
Complete the number pattern.
[?] , 19 , 18 , 17 , 16 , [?] , 14

ANSWERS: ['20', '15', None, None]

SOLUTION:
The numbers are counting down by 1 each step.<br><br>&bull; Before 19 comes 20 (19 + 1).<br>&bull; After 16 comes 15, then 14 (16 - 1 = 15).<br><br>The pattern: 20, 19, 18, 17, 16, 15, 14.<br><br>Final Answer: 20, 15

CORRECT_INDEX: None

================================================================================
ITEM 20047 (DB id=31298, type=FIB)
================================================================================
QUESTION:
Complete the equation. How many hearts are there altogether?
[?] [?] [?] = [?]

ANSWERS: ['5', '+', '4', '9']

SOLUTION:
Count the hearts in each group, then add them together.<br><br>&bull; The equation is: 5 + 4 = 9<br><br>Final Answer: 5 + 4 = 9

CORRECT_INDEX: None

================================================================================
ITEM 20048 (DB id=31299, type=FIB)
================================================================================
QUESTION:
Count and write the number.

ANSWERS: ['17', None, None, None]

SOLUTION:
Count the objects one by one to find the total.<br><br>&bull; The total is 17.<br><br>Final Answer: 17

CORRECT_INDEX: None

================================================================================
ITEM 20049 (DB id=31303, type=MCQ)
================================================================================
QUESTION:
Write the number in word.
12

OPTIONS:
  [0] Twelve <<< CORRECT
  [1] Twenty
  [2] Twenty-one
  [3] Two

SOLUTION:
12 is made of 1 ten and 2 ones.<br><br>&bull; In words: Twelve<br><br>Final Answer: A: Twelve

CORRECT_INDEX: 0

================================================================================
ITEM 20050 (DB id=31306, type=FIB)
================================================================================
QUESTION:
Complete the number pattern. Fill in the missing numbers.
63, 61, [?], [?], 55, 53, 51

ANSWERS: ['59', '57', None, None]

SOLUTION:
The numbers are counting down by 2 each step.<br><br>&bull; 63 - 2 = 61, so the pattern decreases by 2.<br>&bull; 61 - 2 = 59<br>&bull; 59 - 2 = 57<br>&bull; Check: 57 - 2 = 55, 55 - 2 = 53, 53 - 2 = 51. &#10003;<br><br>Final Answer: 59, 57

CORRECT_INDEX: None

================================================================================
ITEM 20051 (DB id=31307, type=FIB)
================================================================================
QUESTION:
Find the total length of the paper clip and pencil.
The total length of the paper clip and pencil is [?] cm.

ANSWERS: ['8', None, None, None]

SOLUTION:
Read the length of each object from the ruler, then add them.<br><br>&bull; Total length = paper clip length + pencil length = 8 cm<br><br>Final Answer: 8 cm

CORRECT_INDEX: None

================================================================================
ITEM 20052 (DB id=31308, type=FIB)
================================================================================
QUESTION:
Arrange the ribbons from the longest to the shortest. Write the letters.
The order from longest to shortest is [?], [?], [?].

ANSWERS: ['Z', 'X', 'Y', None]

SOLUTION:
Compare the lengths of the three ribbons and order them.<br><br>&bull; Z is the longest ribbon.<br>&bull; X is next in length.<br>&bull; Y is the shortest ribbon.<br><br>Final Answer: Z, X, Y

CORRECT_INDEX: None

================================================================================
ITEM 20053 (DB id=31309, type=MCQ)
================================================================================
QUESTION:
A number is 69 when you subtract 5 from it. What is the number?

OPTIONS:
  [0] 64
  [1] 62
  [2] 74 <<< CORRECT
  [3] 79

SOLUTION:
A number is 69 when you subtract 5 from it.<br><br>&bull; Let the unknown number be a box: &square; - 5 = 69<br>&bull; To find the number, add 5 back: 69 + 5 = 74.<br><br>Check: 74 - 5 = 69. &#10003;<br><br>Final Answer: C: 74

CORRECT_INDEX: 2

================================================================================
ITEM 20054 (DB id=31310, type=FIB)
================================================================================
QUESTION:
Andy buys 8 stickers. Peter buys 23 stickers. How many more stickers does Peter buy than Andy?
Peter buys [?] more stickers than Andy.

ANSWERS: ['15', None, None, None]

SOLUTION:
Subtract the smaller number from the larger number to find the difference.<br><br>&bull; 23 - 8 = 15<br><br>Final Answer: 15

CORRECT_INDEX: None

================================================================================
ITEM 20055 (DB id=31311, type=FIB)
================================================================================
QUESTION:
Use the correct numbers from 7, 8, 3 and 9 to complete the equation.
[?] + [?] + [?] = 20

ANSWERS: ['8', '3', '9', None]

SOLUTION:
Try different combinations of 7, 8, 3, and 9 to make 20.<br><br>&bull; 8 + 3 + 9 = 20 (the number 7 is not used)<br><br>Check: 8 + 3 = 11, then 11 + 9 = 20. &#10003;<br><br>Final Answer: 8 + 3 + 9 = 20

CORRECT_INDEX: None

================================================================================
ITEM 20056 (DB id=31313, type=MCQ)
================================================================================
QUESTION:
Write the number in words.
75

OPTIONS:
  [0] Seventy-five <<< CORRECT
  [1] Fifty-seven
  [2] Seventy-four
  [3] Sixty-five

SOLUTION:
75 is made of 7 tens and 5 ones.<br><br>&bull; 7 tens = seventy<br>&bull; 5 ones = five<br>&bull; Together: seventy-five (with a hyphen)<br><br>Final Answer: A: Seventy-five

CORRECT_INDEX: 0

================================================================================
ITEM 20057 (DB id=31314, type=FIB)
================================================================================
QUESTION:
Write the correct symbol "+" or "−" in the space.
19 [?] 5 = 14

ANSWERS: ['−', None, None, None]

SOLUTION:
Check which operation makes the statement true.<br><br>&bull; 19 + 5 = 24 (not 14) &times;<br>&bull; 19 &minus; 5 = 14 &#10003;<br><br>Final Answer: &minus;

CORRECT_INDEX: None

================================================================================
ITEM 20058 (DB id=31315, type=FIB)
================================================================================
QUESTION:
Look at these number cards: 36, 26, 4.
Use 2 of the cards to fill in the number bond. The whole is 40.
The two parts are [?] and [?].

ANSWERS: ['36', '4', None, None]

SOLUTION:
Find two number cards that add up to the whole, 40.<br><br>&bull; 36 + 4 = 40 (works) &#10003;<br>&bull; 36 + 26 = 62 (too big) &times;<br>&bull; 26 + 4 = 30 (too small) &times;<br><br>The two parts are 36 and 4.<br><br>Final Answer: 36 and 4

CORRECT_INDEX: None

================================================================================
ITEM 20059 (DB id=31316, type=FIB)
================================================================================
QUESTION:
Find the length of the pencil.
The length of the pencil is [?] cm.

ANSWERS: ['10', None, None, None]

SOLUTION:
Read the length of the pencil by looking at the ruler markings.<br><br>&bull; The pencil starts at 0 cm and ends at 10 cm.<br>&bull; Length = 10 - 0 = 10 cm.<br><br>Final Answer: 10 cm

CORRECT_INDEX: None

================================================================================
ITEM 20060 (DB id=31317, type=MCQ)
================================================================================
QUESTION:
Who is the tallest?
[?] is the tallest.

OPTIONS:
  [0] Jovie
  [1] Sam <<< CORRECT
  [2] Allan
  [3] None of them

SOLUTION:
Compare the heights shown in the question.<br><br>&bull; Sam is taller than both Jovie and Allan.<br><br>Final Answer: B: Sam

CORRECT_INDEX: 1

================================================================================
ITEM 20061 (DB id=31319, type=MCQ)
================================================================================
QUESTION:
Who is correct?
Gary says "79 is greater than 83". Betty says "81 is greater than 68".
[?] is correct.

OPTIONS:
  [0] Gary
  [1] Betty <<< CORRECT
  [2] Both of them
  [3] Neither of them

SOLUTION:
Check each person's statement by comparing the numbers.<br><br>&bull; Gary: "79 is greater than 83" &rarr; FALSE (79 < 83)<br>&bull; Betty: "81 is greater than 68" &rarr; TRUE (81 > 68)<br><br>Only Betty made a correct statement.<br><br>Final Answer: B: Betty

CORRECT_INDEX: 1

================================================================================
ITEM 20062 (DB id=31324, type=FIB)
================================================================================
QUESTION:
Xiao Ming plays at the playground from 5:30 pm to 6:30 pm. How long does Xiao Ming play at the playground? Xiao Ming plays for [?] at the playground.

ANSWERS: ['1 h', None, None, None]

SOLUTION:
Find the difference between the start and end times.<br><br>&bull; Start: 5:30 pm<br>&bull; End: 6:30 pm<br>&bull; Duration: 6:30 - 5:30 = 1 hour<br><br>Final Answer: 1 h

CORRECT_INDEX: None

================================================================================
ITEM 20063 (DB id=31325, type=FIB)
================================================================================
QUESTION:
Peter started watching The Big Cats at 1:30 pm. He watched it for half an hour and the show ended. Quiz Show started immediately. What time did Quiz Show start? Quiz Show started at [?].

ANSWERS: ['2:00 pm', None, None, None]

SOLUTION:
Add half an hour to the starting time.<br><br>
&bull; 1:30 pm + 30 minutes = 2:00 pm<br>
<br>
Final Answer: 2:00 pm

CORRECT_INDEX: None

================================================================================
ITEM 20064 (DB id=31327, type=FIB)
================================================================================
QUESTION:
4 groups of 10 = [?]

ANSWERS: ['40', None, None, None]

SOLUTION:
4 groups of 10 means 4 &times; 10.<br><br>
&bull; 4 &times; 10 = 40<br>
<br>
Final Answer: 40

CORRECT_INDEX: None

================================================================================
ITEM 20065 (DB id=31331, type=MCQ)
================================================================================
QUESTION:
Mother is cooking dinner at 6:15 [?].

OPTIONS:
  [0] am
  [1] pm <<< CORRECT
  [2] None
  [3] None

SOLUTION:
Dinner is the evening meal, eaten after 12:00 noon.<br><br>
&bull; 6:15 in the evening is 6:15 pm.<br>
<br>
Final Answer: pm

CORRECT_INDEX: 1

================================================================================
ITEM 20066 (DB id=31332, type=FIB)
================================================================================
QUESTION:
There are 8 bicycles. Each bicycle has 2 wheels. How many wheels are there in all? There are [?] wheels in all.

ANSWERS: ['16', None, None, None]

SOLUTION:
Each bicycle has 2 wheels, so multiply the number of bicycles by 2.<br><br>
&bull; 8 &times; 2 = 16<br>
<br>
Final Answer: 16

CORRECT_INDEX: None