Apply each year's depreciation sequentially to the remaining value.<br><br>&bull; Year 1: \(\$85000 \times (1 - 0.15) = \$85000 \times 0.85 = \$72250\)<br>&bull; Year 2: \(\$72250 \times (1 - 0.20) = \$72250 \times 0.80 = \$57800\)<br><br>Final Answer: \(\$57800\)