Let original boys = \\(b\\), original girls = \\(b + 20\\).

After enrolment:
Boys = \\(1.10b\\), Girls = \\(1.25(b + 20) = 1.25b + 25\\)

After enrolment, 26 more girls than boys:
\\(1.25b + 25 - 1.10b = 26\\)
\\(0.15b + 25 = 26\\)
\\(0.15b = 1\\)
\\(b = \frac{20}{3}\\)

Original girls = \\(\frac{20}{3} + 20 = \frac{80}{3}\\)
Total at first = \\(\frac{20}{3} + \frac{80}{3} = \frac{100}{3}\\)

Final Answer: \\(\frac{100}{3}\\) (approximately 33)