Let boys = \\(b\\), girls = \\(g\\).<br><br>\\(\begin{aligned}<br>\text{Boys failed} &= 15\% \times b = 0.15b<br>\\<br>\text{Girls failed} &= 10\% \times g = 0.10g<br>\\<br>\text{Boys failed} &= 3 \times \text{Girls failed}<br>\\<br>0.15b &= 3 \times 0.10g = 0.30g<br>\\<br>b &= 2g<br>\\<br>\text{Total failed} &= 0.15b + 0.10g = 60<br>\\<br>0.15(2g) + 0.10g &= 60<br>\\<br>0.30g + 0.10g &= 60<br>\\<br>0.40g &= 60<br>\\<br>g &= 150, \quad b = 300<br>\end{aligned}\\)<br><br>Final Answer: Boys 300, Girls 150