Let total students = \\(n\\), number who passed = \\(p\\).
\\(\begin{aligned}
\text{If 10 more passed: } \frac{p+10}{n} &= 0.80 \quad \Rightarrow \quad p+10 = 0.80n \quad (1)
\\
\text{If 10 fewer passed: } \frac{p-10}{n} &= 0.60 \quad \Rightarrow \quad p-10 = 0.60n \quad (2)
\\
\text{Subtract (2) from (1): } (p+10) - (p-10) &= 0.80n - 0.60n
\\
20 &= 0.20n
\\
n &= 100
\end{aligned}\\)
Final Answer: 100