Let original amount = \\(x\\) litres. Work through each step.
\\(\begin{aligned}
\text{After Day 1 (20\% used)} &: 0.80x
\\
\text{After adding 10 litres} &: 0.80x + 10
\\
\text{After using 25\%} &: 0.75(0.80x + 10) = 0.60x + 7.5
\\
\text{Final amount} &= 45 \text{ litres}
\\
0.60x + 7.5 &= 45
\\
0.60x &= 37.5
\\
x &= 37.5 \div 0.60 = 62.5
\end{aligned}\\)
Final Answer: 62.5 litres