Add the two masses: bag = \( \frac{1}{3} \) kg, ball = 3 kg.

• Convert 3 to a fraction with denominator 3: \( 3 = \frac{9}{3} \)
• Add: \( \frac{1}{3} + \frac{9}{3} = \frac{10}{3} \)
• \( \frac{10}{3} \) is already in its lowest terms (HCF of 10 and 3 is 1).

Final Answer: A = 10, B = 3