The inner square field has side length 10 m (from the figure).<br>
The path adds 2 m on each side, so the outer square has side 10 + 2 + 2 = 14 m.<br><br>
&bull; Outer square area = 14 × 14 = 196 m&sup2;<br>
&bull; Inner square area = 10 × 10 = 100 m&sup2;<br>
&bull; Area of path = 196 − 100 = 96 m&sup2;<br><br>
Final Answer: 96 m&sup2;