Box B = 1 unit, Box A = 4 units, Box C = 1 unit + 208 (208 more than B). The three boxes total 1450.<br><br>[[model:questions/solutions/q4148.png]]<br><br>• 1 + 4 + 1 = 6 units, plus 208 → 1450<br>• 6 units → 1450 − 208 = 1242<br>• 1 unit → 1242 ÷ 6 = 207<br>• A − C = 4 units − (1 unit + 208) = 3 units − 208 = 621 − 208 = 413<br><br>There are 413 more beads in Box A than in Box C.<br>Check: B 207 + A 828 + C 415 = 1450. ✓