Bala spent $$\frac{2}{5}$$ on a watch, so $$\frac{3}{5}$$ remained. He spent $$\frac{1}{2}$$ of the remainder on a toy.

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• Watch → $$\frac{2}{5}$$ of whole = $$\frac{4}{10}$$
• Remainder → 1 − $$\frac{2}{5}$$ = $$\frac{3}{5}$$ = $$\frac{6}{10}$$
• Toy → $$\frac{1}{2}$$ × $$\frac{6}{10}$$ = $$\frac{3}{10}$$ → 3u
• Left → $$\frac{6}{10}$$ − $$\frac{3}{10}$$ = $$\frac{3}{10}$$ → 3u = $15
• 1u → $15 ÷ 3 = $5 ⇒ whole 10u → 10 × $5 = $50

Bala had $50 at first.
Check: Watch = $$\frac{2}{5}$$ × 50 = $20. Remainder = $30. Toy = $$\frac{1}{2}$$ × 30 = $15. Left = $15. ✓