Pam sold $$\frac{1}{3}$$ to relatives, so $$\frac{2}{3}$$ remained. She sold $$\frac{1}{6}$$ of the remainder to friends.<br><br>[[model:questions/solutions/q4344.png]]<br><br>• Relatives → $$\frac{1}{3}$$ of whole = $$\frac{3}{9}$$<br>• Remainder → 1 − $$\frac{1}{3}$$ = $$\frac{2}{3}$$ = $$\frac{6}{9}$$<br>• Friends → $$\frac{1}{6}$$ × $$\frac{2}{3}$$ = $$\frac{2}{18}$$ = $$\frac{1}{9}$$ → 1u<br>• 9u → 135 tickets ⇒ 1u → 135 ÷ 9 = 15<br>• Relatives − Friends → 3u − 1u = 2u → 2 × 15 = 30<br><br>She sold 30 more tickets to relatives than to friends.<br>Check: Relatives = 45, Friends = 15, Left = 75. 45 + 15 + 75 = 135. ✓