Mike sold $$\frac{5}{8}$$ in the morning, so $$\frac{3}{8}$$ remained. He sold $$\frac{1}{3}$$ of the remainder in the afternoon.<br><br>[[model:questions/solutions/q4353.png]]<br><br>• Morning → $$\frac{5}{8}$$ of whole = $$\frac{15}{24}$$<br>• Remainder → 1 − $$\frac{5}{8}$$ = $$\frac{3}{8}$$ = $$\frac{9}{24}$$<br>• Afternoon → $$\frac{1}{3}$$ × $$\frac{9}{24}$$ = $$\frac{3}{24}$$ → 3u<br>• Left → 9u − 3u = 6u → 48 pies<br>• 1u → 48 ÷ 6 = 8 ⇒ Morning − Afternoon = 15u − 3u = 12u → 12 × 8 = 96<br><br>Mike sold 96 more pies in the morning than in the afternoon.<br>Check: Total = 24 × 8 = 192. Morning = $$\frac{5}{8}$$ × 192 = 120. Remainder = 72. Afternoon = $$\frac{1}{3}$$ × 72 = 24. Left = 48. ✓