At first Ken : Frans = 3 : 8. After Frans spent $48, Ken = $$\frac{1}{2}$$ of Frans.<br><br>[[model:questions/solutions/q4366.png]]<br><br>• Initially → Ken = 3u, Frans = 8u<br>• After spending $48 → Frans = 8u − $48, Ken still = 3u<br>• Ken = $$\frac{1}{2}$$ × new Frans → 3u = $$\frac{1}{2}$$(8u − $48)<br>• 6u = 8u − $48 ⇒ 2u = $48 ⇒ 1u = $24<br>• Ken at first → 3 × $24 = $72. Frans at first → 8 × $24 = $192<br><br>Ken had $72 and Frans had $192 at first.<br>Check: After Frans spends $48, Frans = $192 − $48 = $144. Ken = $72 = $$\frac{1}{2}$$ × $144. ✓