Find how much of the novel is left after the weekend, then determine how many days of \(\(\frac{1}{9}\)\) reading are needed.<br><br>
&bull; Read on Saturday: \(\(\frac{1}{5}\)\)<br>
&bull; Read on Sunday: \(\(\frac{1}{4}\)\)<br>
&bull; Total read by end of Sunday: \(\(\frac{1}{5} + \frac{1}{4} = \frac{4}{20} + \frac{5}{20} = \frac{9}{20}\)\)<br>
&bull; Remaining: \(\(1 - \frac{9}{20} = \frac{11}{20}\)\)<br>
&bull; Each day from Monday she reads \(\(\frac{1}{9}\)\) of the novel<br>
&bull; Days needed: \(\(\frac{11}{20} \div \frac{1}{9} = \frac{11}{20} \times 9 = \frac{99}{20} = 4\frac{19}{20}\)\) days<br>
&bull; After 4 days (Mon, Tue, Wed, Thu): read \(\(4 \times \frac{1}{9} = \frac{4}{9} = \frac{80}{180}\)\). Total = \(\(\frac{81}{180} + \frac{80}{180} = \frac{161}{180}\)\). Remaining = \(\(\frac{19}{180}\)\)<br>
&bull; On the 5th day (Friday), she reads \(\(\frac{1}{9} = \frac{20}{180}\)\), which finishes the novel<br>
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She completes the novel on Friday.<br>
Check: Sat \(\(\frac{36}{180}\)\) + Sun \(\(\frac{45}{180}\)\) + Mon–Fri \(\(5 \times \frac{20}{180} = \frac{100}{180}\)\) = \(\(\frac{181}{180}\)\), which is just over 1. She finishes during the 5th day. ✓<br><br>
Final Answer: A: Friday