Average = Total mass ÷ Number of packets.<br><br>
&bull; Total mass = \( \frac{3}{8} \) kg<br>
&bull; Number of packets = 3<br>
&bull; Average = \( \frac{3}{8} \div 3 = \frac{3}{8} \times \frac{1}{3} = \frac{3}{24} = \frac{1}{8} \) kg<br>
&bull; \( \frac{1}{8} = 0.125 \) kg (to 3 decimal places)<br><br>
Final Answer: 0.125 kg