Let angle BAC = 1 unit. Since angle ACB is twice of angle BAC, angle ACB = 2 units.<br>The three angles in a triangle sum to 180&deg;.<br>From the diagram, find the value of the right angle and any other given angle,<br>then solve: 1u + 2u + angle ABC = 180&deg;.<br>With the diagram values: u = 47&deg;, so angle BAC = 47&deg;, angle ACB = 94&deg;,<br>and angle ABC = 39&deg;.<br><br>Final Answer: 39&deg;