In parallelogram PQRS, opposite sides are equal and parallel.<br>Given PQ = PR = RS, triangle PQR is isosceles with angle PQR = 70&deg;.<br>Base angles are equal: angle PRQ = 70&deg;.<br>Angle QPR = 180&deg; - 70&deg; - 70&deg; = 40&deg;.<br>Since PT = QT, triangle PTQ is isosceles with angle TPQ = angle TQP.<br>Using the diagram: angle TPQ = angle QPR = 40&deg; (same angle).<br>So angle TQP = 40&deg;, and angle PTQ = 180&deg; - 40&deg; - 40&deg; = 100&deg;.<br><br>Final Answer: 100&deg;