In isosceles triangle ABE, base angles are equal: angle ABE = angle AEB.<br>Given angle BAE = 112&deg;, each base angle = (180&deg; - 112&deg;) / 2 = 34&deg;.<br>In rectangle BCDE, all angles are 90&deg;. Given angle BDE = 74&deg;,<br>angle ABD can be found from the angle sums in the figure: angle ABD = 50&deg;.<br><br>Final Answer: 50&deg;