In isosceles triangle JKL, angle JKL = 110&deg;.<br>Base angles are equal: angle JLK = angle KJL = (180&deg; - 110&deg;) / 2 = 35&deg;.<br>Given angle JKM = 75&deg;, angle LKM = angle JKM - angle JKL? No -- working from the figure:<br>angle KLN = 35&deg;.<br><br>Final Answer: 35&deg;