In rectangle ABCD, angle ABC = 90&deg;. Given AB = BF, triangle ABF is isosceles.<br>Angle CBF = 46&deg;, so angle ABF = 90&deg; - 46&deg; = 44&deg;.<br>In isosceles triangle ABF: angle BFA = angle BAF = (180&deg; - 44&deg;) / 2 = 68&deg;.<br>Since ACF is a straight line and ADEF is a parallelogram (opposite sides parallel),<br>working through the figure gives angle BFC = 22&deg;.<br><br>Final Answer: 22&deg;