Given: EFGH is a trapezium (EF ∥ HG) and GHI is an isosceles triangle.
∠HGI = 24°, ∠FEH = 65°.

In the trapezium, EF ∥ HG, so co-interior angles sum to 180°:
∠FEH + ∠EHG = 180°
65° + ∠EHG = 180°
∠EHG = 115°.

In isosceles triangle GHI, ∠HGI = 24° is the vertex angle, so the base angles are equal:
∠GHI = ∠GIH = (180° − 24°) ÷ 2 = 78°.

Sum of ∠GHI and ∠EHG = 78° + 115° = 193°.

Final Answer: 193°