From the same figure: EFGH is a trapezium, GHI is an isosceles triangle.
∠HGI = 24°, ∠FEH = 65°.
In isosceles triangle GHI, ∠HGI = 24° is the vertex angle, so:
∠GHI = ∠GIH = (180° − 24°) ÷ 2 = 78°.
Ratio ∠GHI : ∠FEH = 78 : 65.
Divide both by their HCF (13): 78 ÷ 13 = 6, 65 ÷ 13 = 5.
Final Answer: 6 : 5