From the same figure: EFGH is a trapezium, GHI is an isosceles triangle.<br>&ang;HGI = 24&deg;, &ang;FEH = 65&deg;.<br><br>Given &ang;FIH = \( \frac{13}{6} \) &times; &ang;GIH.<br><br>From the diagram, read the angle &ang;GIH directly at point I (the angle<br>between GI and IH). The figure shows &ang;GIH = 24&deg;.<br><br>&ang;FIH = \( \frac{13}{6} \times 24&deg; = 13 \times 4&deg; = 52&deg; \).<br><br>Final Answer: 52&deg;