EFG is an isosceles triangle, so \(\angle EFG = \angle EGF\).<br>EGH is a straight line, so \(\angle FGH = 180&deg; - \angle EGF\).<br><br>From the figure, the exterior angle \(\angle FGH\) is 105&deg;.<br>So base angle \(\angle EGF\) = 180&deg; - 105&deg; = 75&deg;.<br>Since \(\angle EFG = \angle EGF\), \(\angle EFG\) = 75&deg;.<br><br>Final Answer: 75&deg;