ABCD is a parallelogram and BCEF is a square. In a square, all angles are 90°.
\(\angle BCD\) in the parallelogram and \(\angle BCE\) in the square are adjacent.
\(\angle DCE = \angle BCD + \angle BCE\).
\(\angle BCE = 90°\) (square).
From the figure, \(\angle BCD = 77°\).
\(\angle DCE = 77° + 90° = 167°\).
Final Answer: 167°