JKLM is a rhombus and KLN is a triangle. In a rhombus, opposite angles are equal and diagonals bisect the angles.<br><br>From the figure, \(\angle JKL\) is given as 130&deg;.<br>The diagonal KM bisects \(\angle JKL\).<br>So \(\angle MKN = \angle JKL \div 2 = 130&deg; \div 2 = 65&deg;\).<br><br>Final Answer: 65&deg;