From q5206, \( \angle BAE = 24^\circ \). Since \( \angle BAE : \angle BAD = 2 : 5 \),<br><br>
\( 2u = 24^\circ \) → \( u = 12^\circ \) → \( \angle BAD = 5u = 60^\circ \).<br><br>
In trapezium ABCD, interior angles on the same side of the transversal sum to \(180^\circ\):<br>
\( \angle BAD + \angle ADC = 180^\circ \) → \( \angle ADC = 180^\circ - 60^\circ = 120^\circ \).<br><br>
Final Answer: \( \angle BAD = 60^\circ \), \( \angle ADC = 120^\circ \)