From q5219, \( \angle CDE = 100^\circ \).<br><br>
Triangle EFG: use the marked angles in the figure and the straight line BCEGH to find \( \angle FEG \).<br><br>
Then express the ratio \( \angle CDE : \angle FEG \) in simplest form: \( 100 : 40 = 5 : 2 \).<br><br>
Final Answer: 5 : 2