From the previous parts: \( \angle AOB = 63^\circ \), \( \angle EOF = 74^\circ \) (vertically opposite \( \angle BOC \)), and \( \angle COD = 43^\circ \).<br><br>
Sum = \( 63^\circ + 74^\circ + 43^\circ = 180^\circ \).<br><br>
This makes sense as these three angles lie on a straight line.<br><br>
Final Answer: 180&deg;