Section A time = \(\frac{5}{12}\) h.<br>
Section B took \(\frac{3}{4}\) h more than Section A.<br><br>
• Section B time = \(\frac{5}{12} + \frac{3}{4} = \frac{5}{12} + \frac{9}{12} = \frac{14}{12} = \frac{7}{6}\) h<br>
• Total time for both sections = \(\frac{5}{12} + \frac{14}{12} = \frac{19}{12}\) h<br>
• \(\frac{19}{12} = 1\frac{7}{12}\) h<br><br>
Sam took \(1\frac{7}{12}\) hours to complete both sections.<br>
Check: Section B = \(1\frac{7}{12} - \frac{5}{12} = 1\frac{2}{12} = 1\frac{1}{6}\). Difference = \(1\frac{1}{6} - \frac{5}{12} = \frac{14}{12} - \frac{5}{12} = \frac{9}{12} = \frac{3}{4}\) h. ✓<br><br>
Final Answer: C: \(1\frac{7}{12}\)