Original liquid: 2000 g, 97% water, 3% mud.<br><br>&bull; Mass of water = 0.97 × 2000 = 1940 g<br>&bull; Mass of mud = 0.03 × 2000 = 60 g (unchanged)<br><br>Water content decreased by 30%:<br>&bull; New water mass = 1940 × 0.70 = 1358 g<br>&bull; New total mass = 1358 + 60 = 1418 g<br><br>Check: Water loss = 1940 − 1358 = 582 g. 2000 − 582 = 1418. ✓<br><br>Final Answer: 1418