50% of Lim = 40% of Tan → \( 0.5L = 0.4T \)
• \( \frac{L}{T} = \frac{0.4}{0.5} = \frac{4}{5} \)
• Let Lim = 4 units, Tan = 5 units.
• New Tan = 5 × 1.2 = 6 units (after 20% increase).
• Lim stays 4 units.
• New ratio Lim : Tan = 4 : 6 = 2 : 3
Final Answer: 2 : 3