Both walk the same distance. Find the distance, then Germaine's time.

• Distance = 45 m/min × 15 min = 675 m
• Germaine's time = 675 m ÷ 75 m/min = 9 min
• Rachael left at 06 55, arrived at 06 55 + 15 min = 07 10
• Germaine left at 07 10 − 9 min = 07 01
• 07 01 in decimal hours = \( 7 + \frac{1}{60} \approx 7.02 \) h

Final Answer: \( 7\frac{1}{60} \) h