Let the radius of the large semicircle be \(R\).
The diameter of the small semicircle = \(R\), so its radius = \(\frac{R}{2}\).
Area of small semicircle = \(\frac{1}{2}\pi(\frac{R}{2})^2 = \frac{\pi R^2}{8}\).
Area of large semicircle = \(\frac{1}{2}\pi R^2 = \frac{\pi R^2}{2}\).
Ratio = \(\frac{\pi R^2}{8} : \frac{\pi R^2}{2} = \frac{1}{8} : \frac{1}{2} = 1 : 4\).
Final Answer: C: 1 : 4