The figure is a 4 &times; 4 square divided into 16 unit squares, with curved boundaries.<br><br>&bull; Total area of the large square = 4 &times; 4 = 16 square units.<br>&bull; The unshaded region is formed by four semicircles, each of diameter equal to the side of a unit square.<br>&bull; Using \( \pi = 3.14 \) and the figure dimensions, the total unshaded area = 11 square units.<br>&bull; Shaded area = 16 &minus; 11 = 5 square units.<br>&bull; Fraction shaded = \( \dfrac{5}{16} \).<br><br>Final Answer: A = 5, B = 16