The folded (shaded) region has two layers of paper; the rest has one layer.<br><br>&bull; Radius of the circle = 28 &divide; 2 = 14 cm.<br>&bull; Total area of the paper = \( \pi r^2 = \dfrac{22}{7} \times 14 \times 14 = 616 \) cm&sup2;.<br>&bull; Let the visible shaded area = 2 units, visible unshaded area = 7 units (from the ratio 2 : 7).<br>&bull; Total paper area = visible unshaded + 2 &times; visible shaded (because the shaded part is double-layer).<br>&bull; 616 = 7 units + 2 &times; 2 units = 11 units.<br>&bull; 1 unit = 616 &divide; 11 = 56 cm&sup2;.<br>&bull; Shaded area = 2 units = 2 &times; 56 = 112 cm&sup2;.<br><br>Final Answer: 112 cm&sup2;