Distance for one complete turn = circumference of the hoop = \(\pi \times \text{diameter}\).<br><br>Circumference = \(\frac{22}{7} \times 70 = 220\) cm = 2.2 m.<br><br>For 10 complete turns: distance = \(10 \times 2.2 = 22\) m.<br><br>Final Answer: 22 m