A triangle is removed from a quadrant (quarter-circle) of radius 20 cm.<br><br>&bull; Area of the quadrant = \( \dfrac{1}{4} \times \pi \times 20^2 = \dfrac{1}{4} \times 3.14 \times 400 = 314 \) cm&sup2;.<br>&bull; Triangle: base = 13 cm, height = 8 cm (from the figure). Area = \( \dfrac{1}{2} \times 13 \times 8 = 52 \) cm&sup2;.<br>&bull; Remaining area = 314 &minus; 52 = 262 cm&sup2;.<br><br>Final Answer: 262 cm&sup2;