The square has side 28 cm. The two semicircles sit on one side of the square,
with their diameters adding up to 28 cm.
• Ratio of radii P : Q = 2 : 5, so total parts = 7.
• Sum of diameters = 2rP + 2rQ = 28 cm.
• rP + rQ = 14 cm.
• rP = 14 × \(\frac{2}{7}\) = 4 cm, rQ = 14 × \(\frac{5}{7}\) = 10 cm.
• Arc of semicircle P = \(\pi r_P = 3.14 \times 4 = 12.56\) cm.
• Arc of semicircle Q = \(\pi r_Q = 3.14 \times 10 = 31.4\) cm.
• The remaining 3 sides of the square = 3 × 28 = 84 cm.
• Total perimeter = 84 + 12.56 + 31.4 = 127.96 cm.
Final Answer: 127.96 cm