The figure shows a quadrant (quarter circle) of radius 14 cm with rectangle ABCO inside.

• Area of quadrant = \(\frac{1}{4} \times \pi \times 14^2\).
• Using the given value of \(\pi\), compute the quadrant area.
• Area of rectangle ABCO = 90 cm².
• Shaded area = area of quadrant − area of rectangle = 109 cm².

Final Answer: 109 cm²