Before transfer:
• Class A: n students, total = 60n.
• Class B: m students, total = 90m.
After 5 students (avg 92) move from B to A:
• Class A new total = 60n + 5×92 = 60n + 460, count = n + 5.
• Class B new total = 90m − 5×92 = 90m − 460, count = m − 5.
A's new average = 65: (60n + 460) ÷ (n + 5) = 65.
60n + 460 = 65n + 325.
135 = 5n, so n = 27.
B's new average = 88: (90m − 460) ÷ (m − 5) = 88.
90m − 460 = 88m − 440.
2m = 20, so m = 10.
Final Answer: n = 27, m = 10