Let the three consecutive odd numbers be n, n+2, n+4.

[[model:questions/solutions/q6985.png]]

Sum = n + (n + 2) + (n + 4) = 3n + 6
Given: Sum = 15 + 2n

3n + 6 = 2n + 15
• 3n − 2n = 15 − 6
• n = 9

The smallest number is 9.
Check: numbers are 9, 11, 13. Sum = 33. 15 + 2(9) = 33. ✓

Final Answer: 9