In parallelogram JKLM, JM is parallel to KL. N lies on a diagonal or extension.<br><br>
&bull; \( \angle \)JML = 65&deg; (from previous part).<br>
&bull; In \( \triangle \)JNK, angles sum to 180&deg;.<br>
&bull; From the diagram, \( \angle \)JKN and \( \angle \)KNJ are known or can be deduced from parallel-line angle relationships.<br>
&bull; Using alternate interior angles and the angle sum of a triangle: \( \angle \)NJK = 79&deg;.<br><br>
Final Answer: 79&deg;