ADFE is a parallelogram; ABCD is a rectangle (all angles 90&deg;).<br><br>
&bull; In rectangle ABCD, \( \angle \)ADC = 90&deg;.<br>
&bull; From the diagram, \( \angle \)CDE = 22&deg; (given within the rectangle).<br>
&bull; In parallelogram ADFE, \( \angle \)AFE and \( \angle \)ADE are opposite angles, so they are equal.<br>
&bull; \( \angle \)ADE = \( \angle \)ADC + \( \angle \)CDE = 90&deg; + 22&deg; = 112&deg;.<br>
&bull; Therefore \( \angle \)AFE = 112&deg;.<br><br>
Final Answer: 112&deg;