ADFE is a parallelogram; ABCD is a rectangle.<br><br>
&bull; In triangle CDE within the rectangle, the three angles sum to 180&deg;.<br>
&bull; From the diagram, \( \angle \)CDE = 22&deg;.<br>
&bull; \( \angle \)DCE is an angle within the rectangle's 90&deg; corner; from the diagram it is 68&deg;.<br>
&bull; \( \angle \)CED = 180&deg; &minus; 90&deg; &minus; 68&deg; = 22&deg;.<br>
&bull; Alternatively, \( \angle \)CED + \( \angle \)CDE = 90&deg; (acute angles in right triangle CDE).<br>
&bull; \( \angle \)CED = 90&deg; &minus; 68&deg; = 22&deg;.<br><br>
Final Answer: 22&deg;