{
  "paper": {
    "school": "Tao Nan",
    "year": 2025,
    "level": "P3",
    "label": "Weighted Assessment 2",
    "source_prefix": "Tao Nan 2025 P3 Weighted Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 2,
      "question": "There are 3 ice-cream flavours (Vanilla, Chocolate, Strawberry) and 4 toppings (Nuts, Fruit, Sprinkles, Chocolate Chips). Using only 1 flavour and 1 topping, how many different possible combinations are there? [?]",
      "answer0": "12",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 76,
      "difficulty_id": 2,
      "explanation": "Each of the 3 flavours can be paired with each of the 4 toppings. Multiply the number of flavours by the number of toppings: 3 x 4 = 12. Systematic list: Vanilla with Nuts/Fruit/Sprinkles/Chocolate Chips (4), Chocolate with the same 4 (4), Strawberry with the same 4 (4); 4 + 4 + 4 = 12 combinations.",
      "hints": [
        "Pick one flavour first, then count how many toppings can go with it.",
        "Each flavour gives 4 combinations, and there are 3 flavours."
      ],
      "source": "Tao Nan 2025 P3 Weighted Assessment 2 Q1",
      "image_needed": true,
      "image_options": false,
      "image_file": "q1.png",
      "image_page": 1,
      "image_bbox": [0.17, 0.23, 0.58, 0.33],
      "image_loc": "Flavours/Toppings table just below the question, upper-left of page 1",
      "notes": "Task 1b. Answer key: 12 combinations (3 flavours x 4 toppings). Task 1a was free-choice fill-in (pick any 1 flavour + 1 topping) with no fixed answer and is omitted as non-servable. Figure = the flavours/toppings list table (load-bearing); the ice-cream-shop sketch beside it is decorative."
    },
    {
      "n": 2,
      "type_id": 2,
      "question": "Mr Wong needs to select 2 students to represent the class. The students who volunteered are Zoe, Kai, Maya, Talib and Yongli. Mr Wong chooses Zoe. Name all the other students that Zoe can pair with. Zoe can pair with [?], [?], [?] and [?].",
      "answer0": "Kai",
      "answer1": "Maya",
      "answer2": "Talib",
      "answer3": "Yongli",
      "correct_answer": null,
      "skill_id": 76,
      "difficulty_id": 1,
      "explanation": "The five volunteers are Zoe, Kai, Maya, Talib and Yongli. Zoe is one member of the pair, so the partner can be any of the other four students. Therefore Zoe can pair with Kai, Maya, Talib and Yongli (4 students).",
      "hints": [
        "List everyone who volunteered, then cross out Zoe.",
        "Whoever is left can each form a pair with Zoe."
      ],
      "source": "Tao Nan 2025 P3 Weighted Assessment 2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Task 2a. Answer key: Kai / Maya / Talib / Yongli (any order). FIB with one blank per student name. The garden/children sketch on the page is decorative and not needed. Task 2b (count = 10 ways) is captured separately as Q3."
    },
    {
      "n": 3,
      "type_id": 2,
      "question": "Mr Wong needs to select a team of 2 students from 5 volunteers: Zoe, Kai, Maya, Talib and Yongli. How many different ways can Mr Wong select a team of 2 students? [?]",
      "answer0": "10",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 76,
      "difficulty_id": 2,
      "explanation": "List pairs systematically without repeating: Zoe with Kai, Maya, Talib, Yongli (4); Kai with Maya, Talib, Yongli (3); Maya with Talib, Yongli (2); Talib with Yongli (1). Total = 4 + 3 + 2 + 1 = 10 different teams.",
      "hints": [
        "Start with Zoe and pair her with each other student, then move to Kai (skip pairs already counted).",
        "Add 4 + 3 + 2 + 1 to avoid counting the same pair twice."
      ],
      "source": "Tao Nan 2025 P3 Weighted Assessment 2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Task 2b. Answer key: 10 ways. Same 5 students as Q2; counting unordered pairs (4+3+2+1=10)."
    },
    {
      "n": 4,
      "type_id": 2,
      "question": "Mrs Ang has 5 types of stationery: Pen, Glue, Eraser, Highlighter and Ruler. She wants to pack 3 different items into each stationery bag. How many different ways can she pack the stationery bags? [?]",
      "answer0": "9",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 76,
      "difficulty_id": 3,
      "explanation": "Choosing 3 different items out of 5 gives these groups (each item picture is in the figure): Pen-Glue-Eraser, Pen-Glue-Highlighter, Pen-Glue-Ruler, Pen-Eraser-Highlighter, Pen-Eraser-Ruler, Pen-Highlighter-Ruler, Glue-Eraser-Highlighter, Glue-Eraser-Ruler, Eraser-Highlighter-Ruler. Counting them gives 9 ways (matching the answer key).",
      "hints": [
        "Fix one item and list every group of 3 that includes it, then move on without repeating a group.",
        "List groups in order so you do not count the same set of 3 items twice."
      ],
      "source": "Tao Nan 2025 P3 Weighted Assessment 2 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q4.png",
      "image_page": 3,
      "image_bbox": [0.18, 0.18, 0.82, 0.30],
      "image_loc": "Boxed row of 5 labelled stationery pictures (Pen, Glue, Eraser, Highlighter, Ruler) below the task heading on page 3",
      "notes": "Task 3. Answer key prints 9 ways and lists 9 groups (note: the true number of ways to choose 3 from 5 is 10, but the official key omits the Glue-Highlighter-Ruler group and states 9 - matched to key as instructed). Figure = the labelled stationery items (load-bearing)."
    }
  ]
}