{ "paper": { "school": "Catholic High", "year": 2024, "level": "P4", "label": "Practice", "source_prefix": "Catholic High 2024 P4 Practice", "has_answer_key": true }, "questions": [ { "n": 1, "type_id": 1, "question": "In the number 43.21, which digit is in the tenths place?", "answer0": "1", "answer1": "2", "answer2": "3", "answer3": "4", "correct_answer": 1, "skill_id": 123, "difficulty_id": 1, "explanation": "In a decimal, the first digit after the decimal point is the tenths place. In $$43.21$$, the digit immediately after the point is $$2$$, so the digit in the tenths place is $$2$$. Answer: option (2) = 2.", "hints": ["The tenths place is the first digit after the decimal point.", "$$43.21 = 4$$ tens $$3$$ ones $$.$$ $$2$$ tenths $$1$$ hundredth."], "source": "Catholic High 2024 P4 Practice Q1", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key = option (2) = 2, which is answer1 (index 1)." }, { "n": 2, "type_id": 1, "question": "Which of the following is a multiple of both 6 and 8?", "answer0": "12", "answer1": "2", "answer2": "16", "answer3": "24", "correct_answer": 3, "skill_id": 115, "difficulty_id": 2, "explanation": "A common multiple of 6 and 8 must be in both times tables. Multiples of 6: 6, 12, 18, 24... Multiples of 8: 8, 16, 24... The lowest common multiple is $$24$$. Of the options only $$24$$ is a multiple of both. Answer: option (4) = 24.", "hints": ["List the multiples of 6 and the multiples of 8.", "Find a number that appears in both lists."], "source": "Catholic High 2024 P4 Practice Q2", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key = option (4) = 24 (index 3)." }, { "n": 3, "type_id": 1, "question": "Which of the following is not a factor of 12?", "answer0": "8", "answer1": "2", "answer2": "3", "answer3": "4", "correct_answer": 0, "skill_id": 111, "difficulty_id": 2, "explanation": "The factors of 12 are $$1, 2, 3, 4, 6, 12$$. Among the options, 2, 3 and 4 are all factors of 12, but $$8$$ is not ($$12 \\div 8$$ does not give a whole number). Answer: option (1) = 8.", "hints": ["List all the factors of 12.", "A factor divides 12 exactly with no remainder."], "source": "Catholic High 2024 P4 Practice Q3", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key = option (1) = 8 (index 0)." }, { "n": 4, "type_id": 1, "question": "Mandy was facing the park. She made a $$\\frac{1}{4}$$-turn in a clockwise direction. Which point was she facing at the end?", "answer0": "F", "answer1": "H", "answer2": "K", "answer3": "M", "correct_answer": 2, "skill_id": 141, "difficulty_id": 2, "explanation": "On the map, Mandy faces the Park, which is directly to her left (west). A $$\\frac{1}{4}$$-turn clockwise rotates her 90° so she now faces upward (north). The point directly above Mandy is $$K$$. Answer: option (3) = K.", "hints": ["A quarter turn is a 90° turn.", "Clockwise from facing the Park, work out the new direction Mandy faces."], "source": "Catholic High 2024 P4 Practice Q4", "image_needed": true, "image_options": false, "image_file": "q4.png", "image_page": 2, "image_bbox": [0.20, 0.10, 0.78, 0.40], "image_loc": "grid map near top of page showing points M, K, Mandy, Park, H, F", "notes": "Answer key = option (3) = K (index 2)." }, { "n": 5, "type_id": 1, "question": "Abby saved 5 times as much as Ben. They saved $4860 altogether. How much did Ben save?", "answer0": "$810", "answer1": "$972", "answer2": "$4855", "answer3": "$4865", "correct_answer": 0, "skill_id": 118, "difficulty_id": 2, "explanation": "Ben is 1 unit and Abby is 5 units, so together they are $$6$$ units. $$6$$ units $$= \\$4860$$, so $$1$$ unit $$= 4860 \\div 6 = \\$810$$. Ben saved $$\\$810$$. Answer: option (1) = $810.", "hints": ["Let Ben's savings be 1 unit; then Abby has 5 units.", "Total units = 6; divide $4860 by 6."], "source": "Catholic High 2024 P4 Practice Q5", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key = option (1) = $810 (index 0)." }, { "n": 6, "type_id": 1, "question": "Find the perimeter of the figure. (All lines meet at right angles)", "answer0": "160 cm", "answer1": "184 cm", "answer2": "204 cm", "answer3": "224 cm", "correct_answer": 3, "skill_id": 138, "difficulty_id": 3, "explanation": "The figure is a G/C-shape. The horizontal segments add up to twice the full width and the inner notch edges; the vertical segments add up to twice the full height. Adding all sides for this rectilinear figure gives a perimeter of $$224$$ cm. Answer: option (4) = 224 cm.", "hints": ["For a rectilinear figure, opposite horizontal segments sum to the full width.", "Add every straight edge once, including the inner notch edges."], "source": "Catholic High 2024 P4 Practice Q6", "image_needed": true, "image_options": false, "image_file": "q6.png", "image_page": 3, "image_bbox": [0.34, 0.10, 0.60, 0.30], "image_loc": "C/G-shaped figure near top of page, labelled 34 cm, 58 cm, 20 cm, 20 cm", "notes": "Answer key = option (4) = 224 cm (index 3)." }, { "n": 7, "type_id": 2, "question": "Write the missing number in the number pattern.
$$14\\,200$$ , $$14\\,100$$ , $$14\\,000$$ , [?] , $$13\\,800$$ , $$13\\,700$$", "answer0": "13900", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 108, "difficulty_id": 1, "explanation": "The pattern decreases by $$100$$ each step: $$14\\,200, 14\\,100, 14\\,000, \\ldots$$ The missing term is $$14\\,000 - 100 = 13\\,900$$.", "hints": ["Find the difference between consecutive numbers.", "Each number is 100 less than the one before."], "source": "Catholic High 2024 P4 Practice Q7", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: 14000 - 100 = 13900." }, { "n": 8, "type_id": 2, "question": "Express $$3\\frac{1}{50}$$ as a decimal.
Ans: [?]", "answer0": "3.02", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 127, "difficulty_id": 2, "explanation": "Convert the fraction part to a decimal: $$\\frac{1}{50} = \\frac{2}{100} = 0.02$$. So $$3\\frac{1}{50} = 3 + 0.02 = 3.02$$.", "hints": ["Make the denominator 100: $$\\frac{1}{50} = \\frac{2}{100}$$.", "$$\\frac{2}{100} = 0.02$$, then add the whole number 3."], "source": "Catholic High 2024 P4 Practice Q8", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key = 3.02. Decimal answer so FIB is valid." }, { "n": 9, "type_id": 1, "question": "Find the value of $$1 - \\frac{1}{3} - \\frac{7}{12}$$", "answer0": "$$\\frac{1}{12}$$", "answer1": "$$\\frac{1}{6}$$", "answer2": "$$\\frac{5}{12}$$", "answer3": "$$\\frac{1}{4}$$", "correct_answer": 0, "skill_id": 121, "difficulty_id": 2, "explanation": "Use a common denominator of 12: $$1 = \\frac{12}{12}$$, $$\\frac{1}{3} = \\frac{4}{12}$$. So $$\\frac{12}{12} - \\frac{4}{12} - \\frac{7}{12} = \\frac{12 - 4 - 7}{12} = \\frac{1}{12}$$.", "hints": ["Rewrite all terms with denominator 12.", "$$1 = \\frac{12}{12}$$ and $$\\frac{1}{3} = \\frac{4}{12}$$."], "source": "Catholic High 2024 P4 Practice Q9", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key = 1/12. Fraction answer, so made MCQ with fraction options." }, { "n": 10, "type_id": 2, "question": "The table shows the favourite food of all the pupils in 2 classes. Each pupil chose only 1 favourite food.
State whether each statement is True, False or Not possible to tell.
(a) The total number of pupils in 4X is more than the total number of pupils in 4Y. [?]
(b) Least number of pupils chose fried rice as their favourite food. [?]", "answer0": "True", "answer1": "False", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 148, "difficulty_id": 2, "explanation": "(a) 4X total $$= 13 + 18 + 12 = 43$$; 4Y total $$= 21 + 6 + 11 = 38$$. Since $$43 > 38$$, the statement is True. (b) Total choosing fried rice $$= 18 + 6 = 24$$; burgers $$= 34$$; pizza $$= 23$$. Fewest is pizza (23), not fried rice, so the statement is False.", "hints": ["Add each class's row to compare 4X and 4Y totals.", "Add each food's column to find which food the fewest pupils chose."], "source": "Catholic High 2024 P4 Practice Q10", "image_needed": true, "image_options": false, "image_file": "q10.png", "image_page": 5, "image_bbox": [0.17, 0.46, 0.70, 0.54], "image_loc": "data table (Class / Burgers / Fried Rice / Pizza for rows 4X and 4Y) in middle of page", "notes": "Answer key: (a) True, (b) False. Two True/False/Not-possible-to-tell blanks rendered as a 2-blank FIB with word answers True/False." }, { "n": 11, "type_id": 2, "question": "Dayrus paid $9.60 for 5 pens and a marker. 1 marker cost thrice as much as a pen. How much did a pen cost?
Ans: $[?]", "answer0": "1.20", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 131, "difficulty_id": 2, "explanation": "1 marker costs 3 pens, so 5 pens + 1 marker $$= 5 + 3 = 8$$ pens worth. $$8$$ pens $$= \\$9.60$$, so 1 pen $$= 9.60 \\div 8 = \\$1.20$$.", "hints": ["A marker = 3 pens, so express the total in 'pen units'.", "5 pens + 1 marker = 8 pens; divide $9.60 by 8."], "source": "Catholic High 2024 P4 Practice Q11", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: 9.60 / 8 = $1.20." }, { "n": 12, "type_id": 2, "question": "Measure and write down the size of $$\\angle x$$.
Ans: [?]°", "answer0": "136", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 140, "difficulty_id": 2, "explanation": "Using a protractor to measure the angle $$x$$ between the horizontal line and the slanting ray gives $$136°$$.", "hints": ["Place the protractor centre at the vertex along the base line.", "Read the scale where the slanting ray crosses it."], "source": "Catholic High 2024 P4 Practice Q12", "image_needed": true, "image_options": false, "image_file": "q12.png", "image_page": 6, "image_bbox": [0.20, 0.52, 0.80, 0.72], "image_loc": "angle diagram in lower half of page: horizontal line with a slanting ray, angle x marked at the vertex", "notes": "Answer key = 136°. Answer is in degrees (whole number), unit shown in stem." }, { "n": 13, "type_id": 0, "question": "In the square grid, shade two unit squares so that the dotted line is a line of symmetry.", "answer0": null, "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 145, "difficulty_id": 2, "explanation": "Reflect each already-shaded square across the dotted diagonal line of symmetry; the two squares whose mirror images are not yet shaded must be shaded so the whole pattern is symmetric about the diagonal.", "hints": ["Reflect shaded squares across the dotted line.", "Each shaded square must have a shaded mirror image."], "source": "Catholic High 2024 P4 Practice Q13", "image_needed": true, "image_options": false, "image_file": "q13.png", "image_page": 7, "image_bbox": [0.24, 0.13, 0.52, 0.32], "image_loc": "5x5 square grid with some shaded cells and a dotted diagonal line, upper part of page", "notes": "Interactive shade-the-grid task, no value answer; type_id 0 (skipped on insert). Key: shade the two squares making the diagonal a line of symmetry." }, { "n": 14, "type_id": 0, "question": "In the square grid, draw rectangle ABCD from the given lines.", "answer0": null, "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 143, "difficulty_id": 2, "explanation": "Lines AB and BC are given. To complete rectangle ABCD, draw CD parallel and equal to AB, and DA parallel and equal to BC, so that all four angles are right angles.", "hints": ["AB and BC are two adjacent sides; the fourth vertex D completes the rectangle.", "Opposite sides of a rectangle are equal and parallel."], "source": "Catholic High 2024 P4 Practice Q14", "image_needed": true, "image_options": false, "image_file": "q14.png", "image_page": 7, "image_bbox": [0.22, 0.50, 0.58, 0.80], "image_loc": "square grid with partial lines and labelled points A, B, C in lower part of page", "notes": "Interactive draw-on-grid task, no value answer; type_id 0 (skipped on insert)." }, { "n": 15, "type_id": 2, "question": "Larry had 35 more cookies than Kenny. Matthew had twice the total number of cookies that Larry and Kenny had. The 3 boys had 717 cookies altogether. How many cookies did Kenny have?
Ans: [?]", "answer0": "102", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 118, "difficulty_id": 3, "explanation": "Larry + Kenny = 1 part; Matthew = 2 parts, so all 3 boys = 3 parts $$= 717$$, giving Larry + Kenny $$= 717 \\div 3 = 239$$... Using the key's method: Larry's extra 35 counted across Matthew gives $$35 \\times 3 = 105$$. Removing this, $$717 - 105 = 612$$, which is 6 equal 'Kenny' units, so Kenny $$= 612 \\div 6 = 102$$.", "hints": ["Let Kenny = 1 unit; Larry = 1 unit + 35.", "Matthew = 2(Larry+Kenny). Total = 6 units + (2 x 35) + 35... use the model to get 6 units = 612."], "source": "Catholic High 2024 P4 Practice Q15", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: 35 x 3 = 105; 717 - 105 = 612; 612 / 6 = 102. Kenny = 102." }, { "n": 16, "type_id": 2, "question": "Ethan had some money at first. He spent $$\\frac{4}{9}$$ of it on a meal and $58 on groceries. He then had $72 left.
(a) How much money did he have at first?
(b) How much money did he spend on the meal?
Ans: (a) $[?] (b) $[?]", "answer0": "234", "answer1": "104", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 122, "difficulty_id": 3, "explanation": "(a) After the meal he had $$1 - \\frac{4}{9} = \\frac{5}{9}$$ left. The groceries ($58) and remaining ($72) come from this $$\\frac{5}{9}$$: $$58 + 72 = 130$$, which is $$\\frac{5}{9}$$ of the total. So $$\\frac{1}{9} = 130 \\div 5 = 26$$, and the whole $$= 26 \\times 9 = \\$234$$. (b) The meal was $$\\frac{4}{9}$$: $$26 \\times 4 = \\$104$$.", "hints": ["After the meal, $$\\frac{5}{9}$$ of the money was left; this $$\\frac{5}{9}$$ equals $58 + $72.", "Find 1 unit ($$\\frac{1}{9}$$), then multiply by 9 for the total and by 4 for the meal."], "source": "Catholic High 2024 P4 Practice Q16", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: (a) $234, (b) $104. Two-blank money FIB." }, { "n": 17, "type_id": 2, "question": "The total mass of a container and a watermelon was 2.36 kg. When some oranges were put into the container, the total mass became 3.26 kg. The mass of the watermelon was twice the mass of all the oranges.
(a) Find the mass of the watermelon.
(b) Find the mass of the container. Give your answer in kilograms.
Ans: (a) [?] kg (b) [?] kg", "answer0": "1.8", "answer1": "0.56", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 131, "difficulty_id": 3, "explanation": "(a) Mass of oranges added $$= 3.26 - 2.36 = 0.9$$ kg. The watermelon is twice this: $$0.9 \\times 2 = 1.8$$ kg. (b) Container = (container + watermelon) - watermelon. First container + oranges = $$2.36 - 1.8 = 0.56$$... using the key: watermelon + oranges $$= 1.8 + 0.9 = 2.7$$ kg, so container $$= 3.26 - 2.7 = 0.56$$ kg.", "hints": ["The oranges' mass is the increase: $$3.26 - 2.36$$.", "Watermelon = 2 x oranges; container = total mass - (watermelon + oranges)."], "source": "Catholic High 2024 P4 Practice Q17", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: (a) 1.8 kg, (b) 0.56 kg. Decimal answers; unit kg shown in stem." } ] }