{
  "paper": {
    "school": "Nanyang",
    "year": 2025,
    "level": "P4",
    "label": "Weighted Assessment 2",
    "source_prefix": "Nanyang 2025 P4 Weighted Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "Which of the following shows $$\\frac{1}{3}$$ of the shapes shaded?",
      "answer0": "Figure 1",
      "answer1": "Figure 2",
      "answer2": "Figure 3",
      "answer3": "Figure 4",
      "correct_answer": 2,
      "skill_id": 120,
      "difficulty_id": 1,
      "explanation": "Method: a figure shows $$\\frac{1}{3}$$ shaded when the number of shaded parts is one third of the total equal parts. Figure 3 is a 2-by-3 grid of 6 equal cells with 2 cells shaded, and $$\\frac{2}{6}=\\frac{1}{3}$$. The answer is option 3.",
      "hints": [
        "Count the total number of equal parts in each figure, then count how many are shaded.",
        "Look for the figure where shaded parts divided by total parts equals $$\\frac{1}{3}$$."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q1",
      "image_needed": true,
      "image_options": true,
      "image_file": null,
      "image_page": 1,
      "image_bbox": [0.22, 0.6, 0.78, 0.82],
      "image_loc": "four labelled option figures (1)-(4), each a small grid of squares, below the question on page 1",
      "notes": "Image-option MCQ: each option is a grid figure showing some cells shaded. Key answer = option 3 (a 6-cell grid with 2 cells shaded = 1/3). Crop each option to q1_opt0.png..q1_opt3.png."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "The table shows the number of candies sold in a supermarket.<br>Find the number of sweets sold on Saturday.",
      "answer0": "527",
      "answer1": "952",
      "answer2": "1205",
      "answer3": "1303",
      "correct_answer": 0,
      "skill_id": 118,
      "difficulty_id": 2,
      "explanation": "Method: Saturday total = sweets + lollipops + chocolates. So sweets = total minus the other two. $$1830-425-878=527$$. The answer is option 1, 527.",
      "hints": [
        "The Saturday row total is 1830; subtract the known lollipops and chocolates.",
        "$$1830-425-878$$"
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q2",
      "image_needed": true,
      "image_options": false,
      "image_file": "q2.png",
      "image_page": 2,
      "image_bbox": [0.26, 0.14, 0.82, 0.2],
      "image_loc": "the candies sales table near the top of page 2, with columns Sweets/Lollipops/Chocolates/Total and rows Saturday/Sunday",
      "notes": "Shared-table question (Q2 and Q3 use the same table). Saturday: ?, 425, 878, total 1830. Sunday: blank, 670, ?, total 1150."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "The number of sweets sold on Sunday is twice the number of chocolates sold on Sunday. How many chocolates were sold on Sunday?",
      "answer0": "120",
      "answer1": "160",
      "answer2": "320",
      "answer3": "480",
      "correct_answer": 1,
      "skill_id": 118,
      "difficulty_id": 2,
      "explanation": "Method: Sunday sweets + chocolates = total minus lollipops = $$1150-670=480$$. Sweets are twice the chocolates, so sweets + chocolates = 3 units = 480, giving 1 unit (chocolates) = $$480\\div3=160$$. The answer is option 2, 160.",
      "hints": [
        "Sweets and chocolates together on Sunday = 1150 - 670.",
        "Sweets = 2 units, chocolates = 1 unit, so 3 units = 480; find 1 unit."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q3.png",
      "image_page": 2,
      "image_bbox": [0.26, 0.14, 0.82, 0.2],
      "image_loc": "the candies sales table near the top of page 2 (same table as Q2)",
      "notes": "Uses the same table as Q2. Key working: 1150-670=480 (sweets+chocolates), 480 divided by 3 = 160. Answer = option 2 (160)."
    },
    {
      "n": 4,
      "type_id": 2,
      "question": "The line graph shows the number of stickers sold over 4 months.<br>Find the difference between the number of stickers sold in March and April.",
      "answer0": "28",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 148,
      "difficulty_id": 1,
      "explanation": "Method: read both values from the line graph. March = 20 stickers, April = 48 stickers. Difference = $$48-20=28$$.",
      "hints": [
        "Read the height of the line at March and at April.",
        "Subtract the smaller value from the larger: $$48-20$$."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q4.png",
      "image_page": 3,
      "image_bbox": [0.33, 0.21, 0.85, 0.42],
      "image_loc": "line graph titled 'Number of stickers sold' in the upper-middle of page 3, x-axis months Jan-Apr, y-axis 0-60",
      "notes": "Line graph: Jan=14, Feb=36, March=20, April=48. Key answer = 28 (48-20). One real answer blank."
    },
    {
      "n": 5,
      "type_id": 2,
      "question": "Lucy had \\$954. She spent $$\\frac{5}{9}$$ of her money to buy a pair of shoes. How much had she left after buying the pair of shoes?",
      "answer0": "424",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 122,
      "difficulty_id": 2,
      "explanation": "Method: the money is 9 equal units. She spent $$\\frac{5}{9}$$, so $$\\frac{4}{9}$$ is left. 9 units = \\$954, so 1 unit = $$954\\div9=106$$... using the unitary method 4 units left = \\$424. The answer is \\$424.",
      "hints": [
        "She spent 5 of 9 units, so 4 of 9 units are left.",
        "Find the money left = $$\\frac{4}{9}\\times954$$."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Answer entered in dollars. Key answer = $424 (4/9 of 954). Answer value stored as plain 424."
    },
    {
      "n": 6,
      "type_id": 2,
      "question": "Bag A weighs $$\\frac{1}{4}$$ kg. Bag B weighs $$\\frac{3}{5}$$ kg. Bag C weighs $$\\frac{5}{8}$$ kg.<br>(a) Which 2 bags, when added together, will be heavier than 1 kg? Answer: Bag [?] and Bag [?]<br>(b) Muthu puts a laptop into Bag B. The total mass of Bag B and the laptop is 3 kg. What is the mass of the laptop, in kg?",
      "answer0": "B",
      "answer1": "C",
      "answer2": "2 2/5",
      "answer3": null,
      "correct_answer": null,
      "skill_id": 121,
      "difficulty_id": 2,
      "explanation": "(a) Check each pair against 1 kg. Bag B + Bag C = $$\\frac{3}{5}+\\frac{5}{8}=\\frac{24}{40}+\\frac{25}{40}=\\frac{49}{40}$$ which is more than 1 kg; the other pairs are less. So Bag B and Bag C. (b) Laptop mass = total minus Bag B = $$3-\\frac{3}{5}=2\\frac{2}{5}$$ kg.",
      "hints": [
        "(a) Add each pair of fractions and compare with 1 (which is $$\\frac{40}{40}$$).",
        "(b) Subtract Bag B's mass from 3 kg: $$3-\\frac{3}{5}$$."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Two-part. (a) two answer blanks = B and C (any order). (b) one answer blank = mixed number 2 2/5 kg. Answers stored plain (B, C, '2 2/5')."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "Ali drank $$\\frac{7}{10}$$ $$\\ell$$ of water. He drank $$\\frac{1}{5}$$ $$\\ell$$ of water more than Harry. How much water did Ali and Harry drink in total? Give your answer as a mixed number.",
      "answer0": "1 2/10",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 122,
      "difficulty_id": 2,
      "explanation": "Method: Harry = Ali minus $$\\frac{1}{5}$$ = $$\\frac{7}{10}-\\frac{2}{10}=\\frac{5}{10}$$. Total = Ali + Harry = $$\\frac{7}{10}+\\frac{5}{10}=\\frac{12}{10}=1\\frac{2}{10}$$ litres.",
      "hints": [
        "First find how much Harry drank: $$\\frac{7}{10}-\\frac{1}{5}$$.",
        "Add Ali's and Harry's amounts, then write as a mixed number."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q7",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Answer in litres. Key answer = 1 2/10 (left unsimplified per the key). Stored plain as '1 2/10'."
    },
    {
      "n": 8,
      "type_id": 2,
      "question": "Jim had 3 pieces of rope. Rope A is the longest. Its length is $$\\frac{9}{10}$$ m. The difference between the lengths of Rope A and Rope B is $$\\frac{3}{4}$$ m.<br>(a) What is the length of Rope B, in m? Give your answer in its simplest form.<br>(b) Rope B is the shortest. The difference between the lengths of Rope B and Rope C is $$\\frac{1}{2}$$ m. What is the length of Rope C, in m?",
      "answer0": "3/20",
      "answer1": "13/20",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 121,
      "difficulty_id": 2,
      "explanation": "(a) Rope B = Rope A minus the difference = $$\\frac{9}{10}-\\frac{3}{4}=\\frac{18}{20}-\\frac{15}{20}=\\frac{3}{20}$$ m. (b) Rope C is longer than Rope B by $$\\frac{1}{2}$$, so Rope C = $$\\frac{3}{20}+\\frac{1}{2}=\\frac{3}{20}+\\frac{10}{20}=\\frac{13}{20}$$ m.",
      "hints": [
        "(a) Subtract: $$\\frac{9}{10}-\\frac{3}{4}$$, using a common denominator of 20.",
        "(b) Rope B is the shortest, so add $$\\frac{1}{2}$$ to Rope B's length."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Two-part. (a) one blank = 3/20 m (simplest form). (b) one blank = 13/20 m. Answers stored plain (3/20, 13/20)."
    },
    {
      "n": 9,
      "type_id": 2,
      "question": "A fruit seller sold some apples, pears and watermelons. $$\\frac{2}{7}$$ of the fruits sold were pears, $$\\frac{4}{7}$$ of the fruits sold were apples and the rest of the fruits sold were watermelons. He sold 360 more apples than watermelons.<br>(a) How many pears did the fruit seller sell?<br>(b) How many apples, pears and watermelons did the fruit seller sell in total?",
      "answer0": "240",
      "answer1": "840",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 122,
      "difficulty_id": 3,
      "explanation": "Method: treat the total as 7 units. Pears = 2 units, apples = 4 units, watermelons = $$7-2-4=1$$ unit. Apples minus watermelons = $$4-1=3$$ units = 360, so 1 unit = $$360\\div3=120$$. (a) Pears = 2 units = $$2\\times120=240$$. (b) Total = 7 units = $$7\\times120=840$$.",
      "hints": [
        "Total = 7 units: pears 2, apples 4, watermelons 1.",
        "Apples - watermelons = 3 units = 360; find 1 unit, then pears (2u) and total (7u)."
      ],
      "source": "Nanyang 2025 P4 Weighted Assessment 2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Two-part. (a) pears = 240. (b) total = 840. Answers verified against key."
    }
  ]
}
