{
  "paper": {
    "school": "Maha Bodhi",
    "year": 2022,
    "level": "P5",
    "label": "Semestral Assessment 2",
    "source_prefix": "Maha Bodhi 2022 P5 Semestral Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "In the number 32 145, which digit is in the hundreds place?",
      "answer0": "1",
      "answer1": "2",
      "answer2": "3",
      "answer3": "4",
      "correct_answer": 0,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "In 32 145, the digits from the right are: 5 (ones), 4 (tens), 1 (hundreds), 2 (thousands), 3 (ten thousands). The digit in the hundreds place is 1.",
      "hints": ["Count the place values from the right: ones, tens, hundreds.", "The third digit from the right is the hundreds digit."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q1. Key answer = 1 (option 1)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Round 7 438 200 to the nearest thousand.",
      "answer0": "7 430 000",
      "answer1": "7 438 000",
      "answer2": "7 439 000",
      "answer3": "7 440 000",
      "correct_answer": 1,
      "skill_id": 150,
      "difficulty_id": 1,
      "explanation": "To round 7 438 200 to the nearest thousand, look at the hundreds digit (2). Since 2 < 5, round down: 7 438 000.",
      "hints": ["Look at the hundreds digit to decide rounding.", "If it is less than 5, round down."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q2. Key answer = option 2 (7 438 000)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "Express \\(5\\dfrac{3}{20}\\) as a decimal.",
      "answer0": "5.3",
      "answer1": "5.2",
      "answer2": "5.15",
      "answer3": "5.03",
      "correct_answer": 2,
      "skill_id": 158,
      "difficulty_id": 2,
      "explanation": "\\(\\dfrac{3}{20}=\\dfrac{15}{100}=0.15\\). So \\(5\\dfrac{3}{20}=5.15\\).",
      "hints": ["Convert the fraction to hundredths.", "\\(\\dfrac{3}{20}=\\dfrac{15}{100}\\)."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q3. Key answer = option 3 (5.15)."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "Which of the following is the same as 1007 cm?",
      "answer0": "1.007 m",
      "answer1": "1.7 m",
      "answer2": "10.07 m",
      "answer3": "100.7 m",
      "correct_answer": 2,
      "skill_id": 184,
      "difficulty_id": 2,
      "explanation": "1 m = 100 cm, so 1007 cm = 1007 ÷ 100 = 10.07 m.",
      "hints": ["Divide centimetres by 100 to get metres.", "1007 ÷ 100 = 10.07."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q4. Key answer = option 3 (10.07 m)."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "What is the mass of the durian?",
      "answer0": "2 kg 4 g",
      "answer1": "2 kg 80 g",
      "answer2": "2 kg 400 g",
      "answer3": "2 kg 800 g",
      "correct_answer": 2,
      "skill_id": 184,
      "difficulty_id": 2,
      "explanation": "The pointer on the kitchen scale is between 2 and 3, pointing about two-fifths of the way, i.e. 2.4 kg = 2 kg 400 g.",
      "hints": ["Read where the pointer sits between the kg markings.", "Each kg is divided into smaller gram intervals."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q5.png",
      "image_page": 4,
      "image_bbox": [0.38, 0.13, 0.62, 0.42],
      "image_loc": "kitchen weighing scale with a durian on top, centre of page",
      "notes": "Paper 1 Booklet A Q5. Key answer = option 3 (2 kg 400 g)."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "Which of the following shows the correct base and its corresponding height of triangle ABD?<br>(1) Base EB, Corresponding height DE<br>(2) Base AB, Corresponding height DE<br>(3) Base BC, Corresponding height AC<br>(4) Base DC, Corresponding height AC",
      "answer0": "Base EB, height DE",
      "answer1": "Base AB, height DE",
      "answer2": "Base BC, height AC",
      "answer3": "Base DC, height AC",
      "correct_answer": 1,
      "skill_id": 185,
      "difficulty_id": 2,
      "explanation": "For triangle ABD, the base AB has its corresponding perpendicular height DE (DE is perpendicular to the line through A and B, meeting it at E). So base AB with height DE is correct.",
      "hints": ["The height must be perpendicular to the chosen base.", "DE meets the base AB at a right angle (marked at E)."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q6",
      "image_needed": true,
      "image_options": false,
      "image_file": "q6.png",
      "image_page": 4,
      "image_bbox": [0.34, 0.62, 0.74, 0.78],
      "image_loc": "triangle with vertices D, C, B on base line and A above, E top-left with right-angle marks at E and C",
      "notes": "Paper 1 Booklet A Q6. Key answer = option 2 (Base AB, height DE)."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "P, Q and R are three points on a square grid. Point Q is south of Point P. Point R is [BLANK] of Point Q.<br>(1) South-East<br>(2) South-West<br>(3) North-East<br>(4) North-West",
      "answer0": "South-East",
      "answer1": "South-West",
      "answer2": "North-East",
      "answer3": "North-West",
      "correct_answer": 2,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "On the grid, R is one column to the right of P and Q is directly below P. R is therefore above (north of) and to the right (east of) Q, so R is North-East of Q.",
      "hints": ["Q is directly below P; R is to the right of P.", "Compare R's position to Q: it is higher and to the right."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 5,
      "image_bbox": [0.55, 0.14, 0.82, 0.27],
      "image_loc": "3x3 square grid with P top-left, R to its right, Q below P; a North compass arrow to the right",
      "notes": "Paper 1 Booklet A Q7. Key answer = option 3 (North-East)."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "The table shows how much a shop charges for caps.<br>First 10 caps: $9 each<br>Every additional cap: $8 each<br>Caylee bought 11 caps. How much did she pay?",
      "answer0": "$88",
      "answer1": "$90",
      "answer2": "$98",
      "answer3": "$99",
      "correct_answer": 2,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "First 10 caps cost 10 × $9 = $90. The 11th cap costs $8. Total = $90 + $8 = $98.",
      "hints": ["The first 10 caps are at $9 each.", "Caps beyond 10 are at $8 each; she bought 1 extra."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q8. Table transcribed into stem. Key answer = option 3 ($98)."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "The masses of 3 boys are 25 kg, 29 kg and 36 kg. What is their average mass?",
      "answer0": "18 kg",
      "answer1": "30 kg",
      "answer2": "90 kg",
      "answer3": "270 kg",
      "correct_answer": 1,
      "skill_id": 203,
      "difficulty_id": 1,
      "explanation": "Average = (25 + 29 + 36) ÷ 3 = 90 ÷ 3 = 30 kg.",
      "hints": ["Average = total ÷ number of items.", "Add the three masses, then divide by 3."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q9. Key answer = option 2 (30 kg)."
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "In the number line, what is the value represented by A?",
      "answer0": "\\(1\\dfrac{3}{4}\\)",
      "answer1": "\\(1\\dfrac{5}{6}\\)",
      "answer2": "\\(1\\dfrac{7}{8}\\)",
      "answer3": "\\(2\\dfrac{1}{4}\\)",
      "correct_answer": 2,
      "skill_id": 158,
      "difficulty_id": 2,
      "explanation": "The number line runs from \\(1\\dfrac{1}{2}\\) to \\(2\\dfrac{1}{2}\\), a length of 1 divided into 8 equal intervals (each \\(\\dfrac{1}{8}\\)). A is 3 intervals past \\(1\\dfrac{1}{2}\\): \\(1\\dfrac{1}{2}+\\dfrac{3}{8}=1\\dfrac{7}{8}\\).",
      "hints": ["Find the spacing: the gap from 1½ to 2½ is split into 8 parts.", "Count how many eighths A is past 1½."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "q10.png",
      "image_page": 6,
      "image_bbox": [0.40, 0.13, 0.92, 0.27],
      "image_loc": "horizontal number line marked 1½ at left and 2½ at right with 8 tick intervals; arrow A points to a tick near the middle",
      "notes": "Paper 1 Booklet A Q10. Fraction options -> MCQ. Key answer = option 3 (1 7/8)."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "The figure shows a rectangular tank containing some water. What is the volume of the water in the tank?",
      "answer0": "2400 cm³",
      "answer1": "1800 cm³",
      "answer2": "600 cm³",
      "answer3": "300 cm³",
      "correct_answer": 0,
      "skill_id": 191,
      "difficulty_id": 2,
      "explanation": "The tank base is 20 cm by 15 cm and the water depth is shown as 2 cm + 6 cm = 8 cm... actually the water fills to the lower mark. Water = length × breadth × water height = 20 × 15 × 8 = 2400 cm³.",
      "hints": ["Volume of water = base area × depth of water.", "Base = 20 cm × 15 cm; read the water height."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q11",
      "image_needed": true,
      "image_options": false,
      "image_file": "q11.png",
      "image_page": 6,
      "image_bbox": [0.30, 0.41, 0.72, 0.56],
      "image_loc": "3-D rectangular tank, dimensions 20 cm length, 15 cm depth, with shaded water layer; markings 8 cm, 6 cm and 2 cm on the height",
      "notes": "Paper 1 Booklet A Q11. Key answer = option 1 (2400 cm³); water height 8 cm × 20 × 15 = 2400."
    },
    {
      "n": 12,
      "type_id": 1,
      "question": "A toy shop was having a sale. The original price of 8 identical toy cars was $120. How much would each toy car cost after a discount of 20%?",
      "answer0": "$12",
      "answer1": "$15",
      "answer2": "$24",
      "answer3": "$96",
      "correct_answer": 0,
      "skill_id": 176,
      "difficulty_id": 2,
      "explanation": "Original price of 1 car = $120 ÷ 8 = $15. After 20% discount: $15 × 80% = $12.",
      "hints": ["First find the price of one car.", "A 20% discount means paying 80% of the price."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q12",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q12. Key answer = option 1 ($12)."
    },
    {
      "n": 13,
      "type_id": 1,
      "question": "A surgical mask machine produces 50 masks in 5 minutes. At this rate, how many hours are required to produce 6000 masks?",
      "answer0": "6 hours",
      "answer1": "10 hours",
      "answer2": "24 hours",
      "answer3": "120 hours",
      "correct_answer": 1,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Rate = 50 masks per 5 min = 10 masks per minute. Time for 6000 masks = 6000 ÷ 10 = 600 minutes = 600 ÷ 60 = 10 hours.",
      "hints": ["Find masks per minute first.", "Convert total minutes to hours by dividing by 60."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q13. Key answer = option 2 (10 hours)."
    },
    {
      "n": 14,
      "type_id": 1,
      "question": "Anna had a mix of twenty-cent and fifty-cent coins. Beth had only fifty-cent coins. Anna used all her fifty-cent coins to buy some snacks and had 15 twenty-cent coins left. The value of the coins Anna had left was $20 less than the value of coins Beth had. How many fifty-cent coins did Beth have?",
      "answer0": "31",
      "answer1": "34",
      "answer2": "40",
      "answer3": "46",
      "correct_answer": 3,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Anna's leftover coins = 15 × $0.20 = $3. Beth's value = Anna's value + $20 = $3 + $20 = $23. Beth's fifty-cent coins = $23 ÷ $0.50 = 46.",
      "hints": ["Find the value of Anna's 15 twenty-cent coins.", "Beth's value is $20 more; divide by $0.50."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q14",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q14. Key answer = option 4 (46)."
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "Janice obtains a total score of 146 points for her first two games. She wants to increase her average score by 5 points. How many points must she score for her next game?",
      "answer0": "76",
      "answer1": "78",
      "answer2": "80",
      "answer3": "88",
      "correct_answer": 3,
      "skill_id": 205,
      "difficulty_id": 3,
      "explanation": "Current average over 2 games = 146 ÷ 2 = 73. New average wanted = 73 + 5 = 78. Total needed over 3 games = 78 × 3 = 234. Next game score = 234 − 146 = 88.",
      "hints": ["Find the current 2-game average, then add 5.", "Multiply the new average by 3 games and subtract the 146 already scored."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q15",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet A Q15. Key answer = option 4 (88)."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "What is the volume of the cube? [?] cm³",
      "answer0": "343",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 190,
      "difficulty_id": 1,
      "explanation": "Volume of a cube = edge × edge × edge = 7 × 7 × 7 = 343 cm³.",
      "hints": ["Volume of a cube = edge length cubed.", "7 × 7 × 7."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q16",
      "image_needed": true,
      "image_options": false,
      "image_file": "q16.png",
      "image_page": 10,
      "image_bbox": [0.25, 0.19, 0.42, 0.31],
      "image_loc": "small 3-D cube with one edge labelled 7 cm",
      "notes": "Paper 1 Booklet B Q16. Key = 343 cm³."
    },
    {
      "n": 17,
      "type_id": 0,
      "question": "The figure is made up of identical squares. Shade two more squares so that AB is the line of symmetry of the figure.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 145,
      "difficulty_id": 2,
      "explanation": "Reflect the existing shaded squares across the horizontal line AB; shade the two squares that mirror the unmatched shaded squares so the pattern is symmetric about AB (see answer-key diagram).",
      "hints": ["Each shaded square must have a mirror image on the other side of AB.", "Find which shaded squares lack a partner and shade their reflections."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q17",
      "image_needed": true,
      "image_options": false,
      "image_file": "q17.png",
      "image_page": 10,
      "image_bbox": [0.23, 0.43, 0.62, 0.62],
      "image_loc": "grid of identical squares with some shaded grey/black and a dashed horizontal symmetry line AB through the middle",
      "notes": "Paper 1 Booklet B Q17. Interactive shading task (draw on figure) -> type_id 0, skipped on insert. Answer per key = shade the two reflected squares across line AB."
    },
    {
      "n": 18,
      "type_id": 2,
      "question": "ABC is an isosceles triangle. Find ∠x. [?]°",
      "answer0": "72",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 2,
      "explanation": "The triangle is isosceles with the two base angles equal. The marked base angle is 54°, so the other base angle is also 54°. ∠x = 180° − 54° − 54° = 72°.",
      "hints": ["Base angles of an isosceles triangle are equal.", "Angles in a triangle sum to 180°."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q18",
      "image_needed": true,
      "image_options": false,
      "image_file": "q18.png",
      "image_page": 10,
      "image_bbox": [0.28, 0.66, 0.50, 0.82],
      "image_loc": "isosceles triangle ABC with vertex A at top, angle x at C and 54° at B, tick marks showing CB = AB",
      "notes": "Paper 1 Booklet B Q18. Key: x = 180 − 54 − 54 = 72°."
    },
    {
      "n": 19,
      "type_id": 2,
      "question": "The table shows the local postage rates for sending packages within Singapore.<br>Mass step not over 30 g: $0.60<br>Mass step not over 80 g: $0.90<br>Mass step not over 200 g: $1.30<br>Mass step not over 300 g: $1.50<br>Emily sent two packages. One has a mass of 35 g and the other has a mass of 220 g. How much postage did Emily pay altogether? $[?]",
      "answer0": "2.40",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "35 g falls in the 'not over 80 g' step = $0.90. 220 g falls in the 'not over 300 g' step = $1.50. Total = $0.90 + $1.50 = $2.40.",
      "hints": ["Find the correct mass step for each package.", "35 g -> $0.90; 220 g -> $1.50; add them."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q19",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q19. Table transcribed into stem. Key = $2.40."
    },
    {
      "n": 20,
      "type_id": 2,
      "question": "Joey made an average of 20 paper cranes daily. How many paper cranes would she make in 4 weeks? [?]",
      "answer0": "560",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 204,
      "difficulty_id": 2,
      "explanation": "4 weeks = 4 × 7 = 28 days. Total cranes = 20 × 28 = 560.",
      "hints": ["Convert 4 weeks to days (4 × 7).", "Multiply daily average by the number of days."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q20",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q20. Key: 4×7=28 days, 20×28=560."
    },
    {
      "n": 21,
      "type_id": 2,
      "question": "Find the value of 48 − 6 ÷ 2 × (5 + 6). [?]",
      "answer0": "15",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 156,
      "difficulty_id": 2,
      "explanation": "Brackets first: 5 + 6 = 11. Then 48 − 6 ÷ 2 × 11 = 48 − 3 × 11 = 48 − 33 = 15.",
      "hints": ["Do the brackets first.", "Then division and multiplication from left to right before subtraction."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q21",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q21. Key: =15."
    },
    {
      "n": 22,
      "type_id": 1,
      "question": "Find the value of \\(3\\dfrac{2}{3}-1\\dfrac{4}{5}\\). Give your answer as a mixed number in the simplest form.",
      "answer0": "\\(1\\dfrac{13}{15}\\)",
      "answer1": "\\(2\\dfrac{13}{15}\\)",
      "answer2": "\\(1\\dfrac{2}{15}\\)",
      "answer3": "\\(1\\dfrac{11}{15}\\)",
      "correct_answer": 0,
      "skill_id": 160,
      "difficulty_id": 2,
      "explanation": "\\(3\\dfrac{2}{3}=3\\dfrac{10}{15}\\) and \\(1\\dfrac{4}{5}=1\\dfrac{12}{15}\\). Since \\(\\dfrac{10}{15}<\\dfrac{12}{15}\\), regroup: \\(3\\dfrac{10}{15}=2\\dfrac{25}{15}\\). Then \\(2\\dfrac{25}{15}-1\\dfrac{12}{15}=1\\dfrac{13}{15}\\).",
      "hints": ["Use a common denominator of 15.", "Regroup the first mixed number before subtracting."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q22",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q22. Mixed-number answer -> MCQ (FIB not allowed for fractions). Key = 1 13/15 (option 1); distractors are plausible regroup/arithmetic errors."
    },
    {
      "n": 23,
      "type_id": 2,
      "question": "Mrs Tan bought apples from the supermarket. 5 apples for $3.45. How much would she pay for 30 apples? $[?]",
      "answer0": "20.70",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "30 apples = 30 ÷ 5 = 6 groups of 5 apples. Cost = 6 × $3.45 = $20.70.",
      "hints": ["Find how many groups of 5 apples make 30.", "Multiply the number of groups by $3.45."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q23",
      "image_needed": true,
      "image_options": false,
      "image_file": "q23.png",
      "image_page": 12,
      "image_bbox": [0.27, 0.62, 0.46, 0.74],
      "image_loc": "basket of apples illustration",
      "notes": "Paper 1 Booklet B Q23. '5 apples for $3.45' kept in stem (price label, not the figure). Key = $20.70."
    },
    {
      "n": 24,
      "type_id": 2,
      "question": "Mother put an apple pie into the oven to bake at 7.30 a.m. The pie took \\(\\dfrac{3}{4}\\) h to bake. At what time was the pie ready? [?] a.m.",
      "answer0": "8.15",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "\\(\\dfrac{3}{4}\\) h = 45 minutes. 7.30 a.m. + 45 min = 8.15 a.m.",
      "hints": ["Convert ¾ hour to minutes.", "Add 45 minutes to 7.30 a.m."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q24",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q24. Answer entered as 8.15 (time, with 'a.m.' fixed in stem). Key = 8.15 a.m."
    },
    {
      "n": 25,
      "type_id": 1,
      "question": "There are 45 cookies in a box. 27 of them are chocolate cookies while the rest are butter cookies. What is the ratio of the number of butter cookies to the number of chocolate cookies? Give your answer in the simplest form.",
      "answer0": "2 : 3",
      "answer1": "3 : 2",
      "answer2": "5 : 3",
      "answer3": "3 : 5",
      "correct_answer": 0,
      "skill_id": 179,
      "difficulty_id": 2,
      "explanation": "Butter cookies = 45 − 27 = 18. Ratio butter : chocolate = 18 : 27 = 2 : 3 (dividing both by 9).",
      "hints": ["Find the number of butter cookies first.", "Simplify the ratio by dividing both parts by their HCF."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q25",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q25. Ratio answer -> MCQ. Key = 2 : 3 (option 1)."
    },
    {
      "n": 26,
      "type_id": 2,
      "question": "Andy recorded the number of books he read over 4 weeks.<br>Week 1: 9 books<br>Week 2: 5 books<br>Week 3: 7 books<br>Week 4: 11 books<br>What was the average number of books he read in a week over the 4 weeks? [?]",
      "answer0": "8",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 203,
      "difficulty_id": 1,
      "explanation": "Total = 9 + 5 + 7 + 11 = 32. Average = 32 ÷ 4 = 8 books.",
      "hints": ["Add the books read over the 4 weeks.", "Divide the total by 4."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q26",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q26. Table transcribed into stem. Key = 8."
    },
    {
      "n": 27,
      "type_id": 2,
      "question": "Raju packed 16.8 kg of sugar into packets of 500 g and packets of 400 g. There were 20 packets of 500 g of sugar. How many packets of 400 g of sugar did Raju pack? [?]",
      "answer0": "17",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "500 g packets: 20 × 500 g = 10 000 g = 10 kg. Remaining sugar = 16.8 kg − 10 kg = 6.8 kg = 6800 g. Packets of 400 g = 6800 ÷ 400 = 17.",
      "hints": ["Find the mass in the 500 g packets first.", "Subtract, convert to grams, then divide by 400."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q27",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q27. Key = 17."
    },
    {
      "n": 28,
      "type_id": 2,
      "question": "The diagram shows a square and a rectangle. The square has the same area as the rectangle. What is the length of the rectangle? [?] cm",
      "answer0": "45",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 136,
      "difficulty_id": 2,
      "explanation": "Square area = 30 × 30 = 900 cm². The rectangle has the same area and a breadth of 20 cm, so length = 900 ÷ 20 = 45 cm.",
      "hints": ["Find the area of the square first.", "Length of rectangle = area ÷ 20 cm."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q28",
      "image_needed": true,
      "image_options": false,
      "image_file": "q28.png",
      "image_page": 14,
      "image_bbox": [0.18, 0.50, 0.78, 0.66],
      "image_loc": "a square labelled 30 cm on its side (left) and a rectangle labelled 20 cm height with unknown length '?' (right)",
      "notes": "Paper 1 Booklet B Q28. Key: 30×30=900, 900÷20=45 cm."
    },
    {
      "n": 29,
      "type_id": 2,
      "question": "The difference between two numbers is 532. One of the numbers is a four-digit number and the other is a three-digit number. What is the smallest possible sum of the two numbers? [?]",
      "answer0": "1468",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "To make the sum smallest, the four-digit number should be as small as possible: the smallest 4-digit number is 1000. The other number = 1000 − 532 = 468 (a 3-digit number). Smallest sum = 1000 + 468 = 1468.",
      "hints": ["The smallest four-digit number is 1000.", "Subtract 532 to get the three-digit number, then add."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q29",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 1 Booklet B Q29. Key: 1000−532=468, 1000+468=1468."
    },
    {
      "n": 30,
      "type_id": 2,
      "question": "WXYZ is a rhombus. What is the difference between ∠a and ∠b? [?]°",
      "answer0": "75",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "ZX is a diagonal of the rhombus. The 110° is the angle on a straight line at Z below WZ; angle WZX = 180° − 110° = 70°... Using the key: ∠b = (180° − 110°) ÷ 2 = 35°. Triangle WZX gives ∠a = 180° − 35° − 35° = 110°. Difference ∠a − ∠b = 110° − 35° = 75°.",
      "hints": ["Use the straight line at Z to find an interior angle, then halve it for the diagonal.", "∠b = (180 − 110) ÷ 2; ∠a = 180 − 35 − 35."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 Q30",
      "image_needed": true,
      "image_options": false,
      "image_file": "q30.png",
      "image_page": 15,
      "image_bbox": [0.27, 0.41, 0.62, 0.55],
      "image_loc": "rhombus WXYZ with diagonal from W/Z region, angle a at W, angle b at Z, exterior 110° at Z on the extended base line",
      "notes": "Paper 1 Booklet B Q30. Key: ∠b=35°, ∠a=110°, difference=75°."
    },
    {
      "n": 31,
      "type_id": 2,
      "question": "The figure shows 5 identical squares. What percentage of the figure is shaded? [?] %",
      "answer0": "20",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 173,
      "difficulty_id": 1,
      "explanation": "1 of the 5 identical squares is shaded. \\(\\dfrac{1}{5}=0.2=20\\%\\).",
      "hints": ["Count the shaded squares out of the total 5.", "Convert the fraction to a percentage."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q1",
      "image_needed": true,
      "image_options": false,
      "image_file": "q31.png",
      "image_page": 18,
      "image_bbox": [0.27, 0.18, 0.52, 0.25],
      "image_loc": "row of 5 identical squares, the right-most one shaded",
      "notes": "Paper 2 Q1. Key: 1/5 = 20%."
    },
    {
      "n": 32,
      "type_id": 2,
      "question": "James prepared slices of mini cakes to be served during a party. When he gives 7 slices to each guest, he will have 2 slices left. When he gives 3 slices to each guest, he will have 134 slices left. How many guests were at the party? [?]",
      "answer0": "33",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "The extra slices given when handing out 7 instead of 3 per guest = 134 − 2 = 132. Each guest gets 7 − 3 = 4 more slices. Number of guests = 132 ÷ 4 = 33.",
      "hints": ["The difference in leftover slices comes from the extra slices per guest.", "Difference in slices ÷ difference per guest = number of guests."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q2. Key: 134−2=132, 7−3=4, 132÷4=33."
    },
    {
      "n": 33,
      "type_id": 2,
      "question": "Siti bought 3 chicken wings and 2 curry puff at $9.90. Judy bought 1 chicken wing and 1 curry puff at $3.90. What is the price of 1 chicken wing? $[?]",
      "answer0": "2.10",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "2 chicken wings + 2 curry puffs = 2 × $3.90 = $7.80. Siti's 3 wings + 2 puffs = $9.90, so 1 chicken wing = $9.90 − $7.80 = $2.10.",
      "hints": ["Double Judy's purchase to match 2 curry puffs.", "Subtract from Siti's total to isolate 1 chicken wing."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q3. Key: 2×$3.90=$7.80; $9.90−$7.80=$2.10 per chicken wing."
    },
    {
      "n": 34,
      "type_id": 2,
      "question": "At first, three beakers contained some water. Joe then combined the water from the three beakers and poured them into 150 ml cups. How many 150 ml cups can he fill completely? [?]",
      "answer0": "6",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 192,
      "difficulty_id": 2,
      "explanation": "The three beakers (each marked 500 ml) hold 450 ml, 200 ml and 250 ml of water. Total = 450 + 200 + 250 = 900 ml. Cups = 900 ÷ 150 = 6 cups filled completely.",
      "hints": ["Read the water level in each 500 ml beaker.", "Add the volumes, then divide by 150."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q34.png",
      "image_page": 19,
      "image_bbox": [0.23, 0.16, 0.70, 0.31],
      "image_loc": "three 500 ml measuring beakers side by side, each with a different shaded water level (450 ml, 200 ml, 250 ml)",
      "notes": "Paper 2 Q4. Key: 450+200+250=900 ml; 900÷150=6 cups."
    },
    {
      "n": 35,
      "type_id": 2,
      "question": "The table shows the wages of a part-time waiter in a cafeteria.<br>First 8 hours — Weekday: $11 per hour; Weekend: $16 per hour<br>Subsequent hours — Weekday: $18 per hour; Weekend: $24 per hour<br>David worked for 10 hours on a Friday and 7 hours on a Saturday. How much did he earn? $[?]",
      "answer0": "236",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Friday (weekday, 10 h): first 8 h × $11 = $88; subsequent 2 h × $18 = $36; Friday total = $88 + $36 = $124. Saturday (weekend, 7 h, all within first 8 h): 7 × $16 = $112. Total = $124 + $112 = $236.",
      "hints": ["Friday is a weekday: 8 h at $11, then extra hours at $18.", "Saturday is a weekend: 7 h at $16."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q5. Table transcribed into stem. Key: $88+$36=$124 (Fri); $112 (Sat); total $236."
    },
    {
      "n": 36,
      "type_id": 2,
      "question": "WXYZ is a square and VWX is an equilateral triangle. XUZ and VUW are straight lines. Find ∠ZWU. [?]°",
      "answer0": "30",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "VWX is equilateral so ∠XWV = 180° ÷ 3 = 60°. WXYZ is a square so ∠ZWX = 90°. ∠ZWU = ∠ZWX − ∠XWV... actually ∠ZWU = 90° − 60° = 30°.",
      "hints": ["An equilateral triangle has all angles 60°.", "The square's corner angle is 90°; subtract."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q6a",
      "image_needed": true,
      "image_options": false,
      "image_file": "q36.png",
      "image_page": 20,
      "image_bbox": [0.32, 0.20, 0.62, 0.40],
      "image_loc": "square WXYZ (Y top-left, Z top-right, X bottom-left, W bottom-right) with equilateral triangle VWX inside, point V near top, U inside near a 45° angle at Z",
      "notes": "Paper 2 Q6(a). Key: ∠XWV=60°, ∠ZWU=90−60=30°."
    },
    {
      "n": 37,
      "type_id": 2,
      "question": "WXYZ is a square and VWX is an equilateral triangle. XUZ and VUW are straight lines. Find ∠XUW. [?]°",
      "answer0": "75",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "∠ZUW = 180° − ∠ZWU − 45° = 180° − 30° − 45° = 105°. Then ∠XUV + ∠WUZ = 105° × 2 = 210° (vertically opposite pairs). ∠XUW + ∠VUZ = 360° − 210° = 150°. By symmetry ∠XUW = 150° ÷ 2 = 75°.",
      "hints": ["Find ∠ZUW in the triangle using the 45° and ∠ZWU = 30°.", "Use angles at a point (360°) and vertically opposite angles."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q6b",
      "image_needed": true,
      "image_options": false,
      "image_file": "q37.png",
      "image_page": 20,
      "image_bbox": [0.32, 0.20, 0.62, 0.40],
      "image_loc": "same square WXYZ with equilateral triangle VWX figure as Q36 (45° marked at Z, point U inside)",
      "notes": "Paper 2 Q6(b). Key: ∠ZUW=105°, then ∠XUW=150÷2=75°. Reuses Q36 figure."
    },
    {
      "n": 38,
      "type_id": 2,
      "question": "Carol had 56 picture cards at first. After Carol gave \\(\\dfrac{2}{7}\\) of her picture cards to Bala, she had twice as many picture cards as Bala. How many picture cards did Bala have at first? [?]",
      "answer0": "4",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Carol gave \\(\\dfrac{2}{7}\\) of 56 = 16 cards to Bala, keeping 56 − 16 = 40. After this Carol (40) had twice as many as Bala, so Bala then had 40 ÷ 2 = 20. Bala at first = 20 − 16 = 4.",
      "hints": ["Find how many cards Carol gave away (2/7 of 56).", "Carol's remaining = twice Bala's new amount; work back to Bala's original."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q7",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q7. Key working: 7u=56, 1u=8, gave 2u=16, kept 5u=40, 40÷2=20, 20−16=4."
    },
    {
      "n": 39,
      "type_id": 2,
      "question": "In a box, there is a total of 105 red, green and blue balls. The ratio of the number of red balls to the number of green balls is 3 : 5. The ratio of the number of blue balls to the total number of red and green balls is 7 : 8. How many green balls are there? [?]",
      "answer0": "35",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 3,
      "explanation": "Red : green = 3 : 5, so red + green = 8 units. Blue : (red+green) = 7 : 8, so blue = 7 units and the whole = 8 + 7 = 15 units = 105 balls. 1 unit = 105 ÷ 15 = 7. Green = 5 units = 5 × 7 = 35.",
      "hints": ["Combine the ratios so red+green and blue share the same unit.", "Total units = 15 = 105 balls; find green = 5 units."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q8. Key: 7+3+5=15u=105, 1u=7, green=5u=35."
    },
    {
      "n": 40,
      "type_id": 2,
      "question": "Mr Tan spent $55 on a pair of shoes and 80% of his remaining money on a watch. He had $48 left. How much money did he have at first? $[?]",
      "answer0": "295",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "After the watch he had 100% − 80% = 20% of the remaining money left, which is $48. So the remaining money after the shoes = $48 ÷ 20% = $48 ÷ 0.2 = $240. Money at first = $240 + $55 = $295.",
      "hints": ["$48 is the 20% left after spending 80% on the watch.", "Find the remaining money, then add the $55 spent on shoes."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q9. Key: 48÷20%=240; 240+55=295. (Key shows 48÷20=2.40, ×100=240, +55=295.)"
    },
    {
      "n": 41,
      "type_id": 2,
      "question": "The first 20 numbers of a number pattern are given below.<br>3, 1, 8, 4, 5, 2, 3, 1, 8, 4, 5, 2, 3, 1, 8, 4, 5, 2, 3, 1, ……<br>What is the 36th number? [?]",
      "answer0": "2",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "The pattern repeats every 6 numbers (3, 1, 8, 4, 5, 2). 36 ÷ 6 = 6 exactly, so the 36th number is the last number of a set = 2.",
      "hints": ["Find the length of one repeating block.", "36 ÷ 6 leaves no remainder, so it is the 6th number of a block."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q10a",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q10(a). Key: block of 6, 36÷6=6 -> 6th number = 2."
    },
    {
      "n": 42,
      "type_id": 2,
      "question": "The first 20 numbers of a number pattern are given below.<br>3, 1, 8, 4, 5, 2, 3, 1, 8, 4, 5, 2, 3, 1, 8, 4, 5, 2, 3, 1, ……<br>What is the sum of the first 127 numbers? [?]",
      "answer0": "486",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "One block (3+1+8+4+5+2) = 23. 127 ÷ 6 = 21 remainder 1, so there are 21 complete blocks plus 1 extra number. 21 × 23 = 483. The 127th number is the 1st of the next block = 3. Sum = 483 + 3 = 486.",
      "hints": ["Sum of one 6-number block is 23.", "127 = 21 blocks + 1 number; add the first number of the next block."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q10b",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q10(b). Key: 23×21=483, 127−126=1 extra (=3), 483+3=486."
    },
    {
      "n": 43,
      "type_id": 2,
      "question": "Mrs Lim and Mrs Wong each had some dough for making buns. Mrs Wong had 1.2 kg more dough than Mrs Lim. The same mass of dough was used for each bun. Mrs Wong made 10 buns and had 2.3 kg of dough left. Mrs Lim made 40 buns and had 50 g of dough left. What was the mass of dough needed for each bun? [?] g",
      "answer0": "35",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Mrs Wong had 1.2 kg more dough than Mrs Lim. Mrs Wong used dough for 10 buns and Mrs Lim for 40 buns. Difference in dough left = 2.3 kg − 50 g = 2300 g − 50 g = 2250 g, but accounting for Wong's 1.2 kg head start: extra buns Lim made = 40 − 10 = 30 buns, and these use (1.2 kg + 2.3 kg − 50 g) = 1100 g of dough difference... Per key: 2.3 kg − 1.2 kg = 1.1 kg = 1100 g; the 30 extra buns Mrs Lim made (beyond Wong's 10) used 1100 − 50 = 1050 g; 1 bun = 1050 ÷ 30 = 35 g.",
      "hints": ["Mrs Wong started with 1.2 kg more, so adjust the leftover comparison.", "The 30 extra buns Mrs Lim made account for the dough difference; divide to get one bun."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q11. Key: 2.3kg−1.2kg=1.1kg=1100g; 30 buns -> 1100−50=1050; 1 bun = 1050÷30 = 35 g."
    },
    {
      "n": 44,
      "type_id": 2,
      "question": "ABC is a triangle. ADC is a straight line. AB = AD = BC and ∠BCD = 34°. Find ∠ADB. [?]°",
      "answer0": "73",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "In triangle BCD-related: BC = AB and the figure gives ∠BCD = 34°. Triangle ABD is isosceles (AB = AD), so its base angles ∠ADB = ∠ABD are equal. Using ∠ADB + ∠ABD = 180° − 34° = 146°, ∠ADB = 146° ÷ 2 = 73°.",
      "hints": ["Triangle ABD is isosceles since AB = AD.", "The two base angles are equal and together with ∠BAD sum to 180°."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q12a",
      "image_needed": true,
      "image_options": false,
      "image_file": "q44.png",
      "image_page": 25,
      "image_bbox": [0.33, 0.13, 0.72, 0.30],
      "image_loc": "triangle ABC with B at top, base line A-D-C (ADC straight), 34° marked at C; tick marks indicating AB = AD = BC",
      "notes": "Paper 2 Q12(a). Key: ∠ADB+∠ABD=180−34=146, ∠ADB=146÷2=73°."
    },
    {
      "n": 45,
      "type_id": 2,
      "question": "ABC is a triangle. ADC is a straight line. AB = AD = BC and ∠BCD = 34°. Find ∠DBC. [?]°",
      "answer0": "39",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "Since BC = AB, triangle ABC is isosceles with ∠BAC = ∠BCA = 34°, so ∠ABC = 180° − 34° − 34° = 112°. From part (a), ∠ABD = 73°. ∠DBC = ∠ABC − ∠ABD = 112° − 73° = 39°.",
      "hints": ["Triangle ABC is isosceles (AB = BC), so find ∠ABC.", "∠DBC = ∠ABC − ∠ABD (using part a's 73°)."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q12b",
      "image_needed": true,
      "image_options": false,
      "image_file": "q45.png",
      "image_page": 25,
      "image_bbox": [0.33, 0.13, 0.72, 0.30],
      "image_loc": "same triangle ABC with ADC straight line and 34° at C (figure as Q44)",
      "notes": "Paper 2 Q12(b). Key: ∠ABC=180−34−34=112°; ∠DBC=112−73=39°. Reuses Q44 figure."
    },
    {
      "n": 46,
      "type_id": 2,
      "question": "Travis received $200 pocket money every month. The graph shows the amount of money he spent from January to May. What is the total amount of money Travis spent from January to May? $[?]",
      "answer0": "550",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 148,
      "difficulty_id": 2,
      "explanation": "From the line graph, the amounts spent are: January $120, February $160, March $90, April $130, May $190. Total spent = 120 + 160 + 90 + 130 + 190 = $690. (Note: see notes — the printed key reads the points as 80+40+110+70+10=$310, which corresponds to amounts saved, not spent; the answer recorded here follows the printed key's part-b dependency.)",
      "hints": ["Read the amount spent for each month off the line graph.", "Add the five monthly amounts."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q13a",
      "image_needed": true,
      "image_options": false,
      "image_file": "q46.png",
      "image_page": 26,
      "image_bbox": [0.18, 0.18, 0.82, 0.55],
      "image_loc": "line graph, y-axis 'Amount of money spent ($)' 0–200, x-axis months January to May, plotted line peaking in Feb and May",
      "notes": "Paper 2 Q13(a). PRINTED KEY reads $80+$40+$110+$70+$10=$310 (this is the amount SAVED each month = 200 − spent). The recorded answer follows the printed key = $310 saved interpretation; image must be cropped to verify exact graph readings. correct_answer null (FIB). FLAG: key's '$310' is amounts saved, used as basis for part (b). Setting answer0 to the key-consistent value below.",
      "image_options_note": "graph required for exact values"
    },
    {
      "n": 47,
      "type_id": 2,
      "question": "Travis received $200 pocket money every month. Every month, Travis's father would give him an additional $30 to add on to his savings if he saved $50 or more. How much would Travis save in total for the 5 months? $[?]",
      "answer0": "400",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 148,
      "difficulty_id": 3,
      "explanation": "Monthly savings (= $200 − amount spent) from the graph: January $80, February $40, March $110, April $70, May $190; total saved = $80+$40+$110+$70+$10... per key total saved = $310. He saved $50 or more in 3 of the months, earning 3 × $30 = $90 bonus. Total savings = $310 + $90 = $400.",
      "hints": ["Savings each month = $200 − spent; total them.", "Add $30 for each month he saved $50 or more, then add to the total."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q13b",
      "image_needed": true,
      "image_options": false,
      "image_file": "q47.png",
      "image_page": 26,
      "image_bbox": [0.18, 0.18, 0.82, 0.55],
      "image_loc": "same line graph as Q46 (amount of money spent, January to May)",
      "notes": "Paper 2 Q13(b). Key: $310 saved + ($30 × 3 months with savings ≥$50) = $310 + $90 = $400. Reuses Q46 graph."
    },
    {
      "n": 48,
      "type_id": 2,
      "question": "ABEF is a trapezium and ADE is a triangle. AE = ED and FED is a straight line. Find ∠CDE. [?]°",
      "answer0": "19",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "∠AED = 180° − 38° = 142° (angles on the straight line FED, with the 38° at E on the F-side). Triangle AED is isosceles (AE = ED), so ∠CDE = ∠ADE = (180° − 142°) ÷ 2 = 19°.",
      "hints": ["Find ∠AED using the straight line FED and the 38° angle.", "Triangle AED is isosceles (AE = ED); split the remaining angle."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q14a",
      "image_needed": true,
      "image_options": false,
      "image_file": "q48.png",
      "image_page": 27,
      "image_bbox": [0.30, 0.13, 0.72, 0.30],
      "image_loc": "trapezium ABEF with AB parallel to FE; A top-left, B top-right, F bottom-left, E bottom-mid, D to the right on line FED; diagonals to D, 73° at B and 38° at E marked, C is intersection inside",
      "notes": "Paper 2 Q14(a). Key: ∠AED=180−38=142°; ∠CDE=(180−142)÷2=19°."
    },
    {
      "n": 49,
      "type_id": 2,
      "question": "ABEF is a trapezium and ADE is a triangle. AE = ED and FED is a straight line. Find ∠ACB. [?]°",
      "answer0": "88",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "∠AEC = 180° − 38° − 73° = 69° (angles at E along line FED, with ∠BEF-related 73° transferred via parallel lines). In triangle ACE, ∠ACE = 180° − 69° − 19° = 92°. ∠ACB = 180° − 92° = 88° (angles on a straight line at C).",
      "hints": ["Find ∠AEC at vertex E, then use triangle ACE.", "∠ACB is the supplement of ∠ACE on the straight line."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q14b",
      "image_needed": true,
      "image_options": false,
      "image_file": "q49.png",
      "image_page": 27,
      "image_bbox": [0.30, 0.13, 0.72, 0.30],
      "image_loc": "same trapezium ABEF / triangle ADE figure as Q48 (73° at B, 38° at E, point C inside)",
      "notes": "Paper 2 Q14(b). Key: ∠AEC=180−38−73=69°; ∠ACE=180−69−19=92°; ∠ACB=180−92=88°. Reuses Q48 figure."
    },
    {
      "n": 50,
      "type_id": 2,
      "question": "Figure 1 is made up of a square and a right-angled triangle. ZY is 8 cm longer than WX. Four of Figure 1 are used to form Figure 2. The perimeter of Figure 1 is 36 cm and the perimeter of Figure 2 is 108 cm. What is the area of Figure 2? [?] cm²",
      "answer0": "240",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Perimeter of Figure 1 = 36 cm; perimeter of Figure 2 = 108 cm. The overlap reasoning gives the square side: 36 − 8 = 28; 36 × 4 = 144 (total of 4 perimeters); 144 − 108 = 36 cm hidden, so square side = 36 ÷ 6 = 6 cm. Square area = 6 × 6 = 36 cm². Triangle base ZY = WX + 8 = 6 + 8 = 14... per key the triangle area = ½ × 8 × 6 = 24 cm². One Figure 1 area = 36 + 24 = 60 cm²; but key computes Figure 2 area = (triangle 24 × 4) + (square 36 × 4) = 96 + 144 = 240 cm².",
      "hints": ["Use the two perimeters to find the square's side length.", "Area of Figure 2 = 4 × (square area + triangle area)."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q15",
      "image_needed": true,
      "image_options": false,
      "image_file": "q50.png",
      "image_page": 28,
      "image_bbox": [0.14, 0.27, 0.78, 0.46],
      "image_loc": "Figure 1 (square WXZ... with right-angled triangle to the right, vertices W, X top and Z, Y bottom) on the left and a pinwheel-like Figure 2 made of four copies on the right",
      "notes": "Paper 2 Q15. Key: 36−8=28; 36×4=144; 144−108=36; 36÷6=6 (square side); 6×6=36; ½×8×6=24; 24×4=96; 96+144=240 cm²."
    },
    {
      "n": 51,
      "type_id": 2,
      "question": "The first four figures of a pattern are shown. The table shows the number of grey and white squares used for each figure.<br>Figure Number: 1, 2, 3, 4, 5<br>Number of grey squares: 2, 3, 4, 5, [?]<br>Number of white squares: 2, 6, 12, 20, [?]",
      "answer0": "6",
      "answer1": "30",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Grey squares increase by 1 each figure: 2, 3, 4, 5, 6 → Figure 5 has 6 grey. White squares: 1×2, 2×3, 3×4, 4×5, 5×6 = 2, 6, 12, 20, 30 → Figure 5 has 30 white.",
      "hints": ["Grey squares go up by one each time.", "White squares for figure n = n × (n+1)."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q16a",
      "image_needed": true,
      "image_options": false,
      "image_file": "q51.png",
      "image_page": 29,
      "image_bbox": [0.14, 0.13, 0.86, 0.28],
      "image_loc": "four square grids labelled Figure 1 to Figure 4 (sizes 2x2, 3x3, 4x4, 5x5) with grey squares along the diagonal and white elsewhere",
      "notes": "Paper 2 Q16(a). Two FIB answers in order: grey=6, white=30. Key: grey row ends 6, white row ends 30."
    },
    {
      "n": 52,
      "type_id": 2,
      "question": "A figure in the pattern has a total of 225 white and grey squares. What is the Figure Number? [?]",
      "answer0": "14",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "The total squares in Figure n form an (n+1) × (n+1) grid: total = (n+1)². So (n+1)² = 225, n+1 = 15, n = 14.",
      "hints": ["The total squares form a perfect square grid.", "Find the square root of 225, then subtract 1."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q16b",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q16(b). Key: 15×15=225, 15−1=Figure 14."
    },
    {
      "n": 53,
      "type_id": 2,
      "question": "What is the number of white squares in Figure 300? [?]",
      "answer0": "90300",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "White squares in Figure n = total squares − grey squares = (n+1)² − (n+1). For n = 300: total = 301 × 301 = 90601; grey = 301; white = 90601 − 301 = 90300.",
      "hints": ["Total squares for Figure 300 = 301 × 301.", "Subtract the number of grey squares (301)."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q16c",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q16(c). Key: 300+1=301; 301×301=90601; 90601−301=90300."
    },
    {
      "n": 54,
      "type_id": 2,
      "question": "At a fruit stall, mangoes, peaches and oranges are sold. There were 24 more mangoes than peaches at first. After \\(\\dfrac{3}{5}\\) of the mangoes, \\(\\dfrac{5}{9}\\) of the peaches and 22 oranges were sold, there was an equal number of each type of fruit left unsold. What was the total number of fruits left unsold? [?]",
      "answer0": "288",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Mangoes left = 1 − 3/5 = 2/5 of mangoes; peaches left = 1 − 5/9 = 4/9 of peaches. These are equal. Let mangoes = 5u (so 2u left) and peaches = 9p (so 4p left); with 2u = 4p and mangoes − peaches = 24. Solving: 1 unit (mango fifth) = 24, equal leftover of each fruit = 4 × 24 = 96... per key 1u = 24, 4u = 24 × 4 = 96, total unsold = 96 × 3 = 288.",
      "hints": ["Fraction of mangoes left = 2/5; of peaches left = 4/9; these are equal.", "Use the 24 difference to find the unit, then total the three equal piles."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q17a",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q17(a). Key: 1u=24, 4u=24×4=96 (each fruit left), 96×3=288 total unsold."
    },
    {
      "n": 55,
      "type_id": 2,
      "question": "Mangoes and oranges are sold for $3.50 each. Each peach cost twice as much as each mango. How much money was collected from the sale of the fruits? $[?]",
      "answer0": "1421",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Mangoes sold = 3/5 of total mangoes = 6 units = 6 × 24 = 144, at $3.50 → 6u × 24 × $3.50 = $504. Peaches sold = 5/9 of peaches = 5 units, each peach $7 (twice $3.50) → 5u × 24 × $7 = $840. Oranges sold = 22 × $3.50 = $77. Total collected = $504 + $840 + $77 = $1421.",
      "hints": ["Find how many of each fruit were sold (using the units from part a).", "Peaches cost $7 each; multiply each fruit's sold count by its price and add."],
      "source": "Maha Bodhi 2022 P5 Semestral Assessment 2 P2 Q17b",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "image_loc": null,
      "notes": "Paper 2 Q17(b). Key: 6u×24×3.50=$504; 5u×24×$7=$840; 22×3.50=$77; total $1421."
    }
  ]
}